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‫Welcomed the Alieu demonstration but the base is too short for this demonstration.

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‫We have two four digit seven segment displays located on solderless breadboard where each of the segments

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‫are tied together through a 56 ohm resistor that is fed into the J and J b p mod ports of the Base to

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‫board.

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‫We also have all the digits selects all eight of them are connected through a two and thirty nine or

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‫four and transistor where the 470 ohm resistor are connected through the base and these are fed and

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‫controlled through the J.C. Jaydee the main ports of the bases to board we also are using switches 7

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‫6 and 5 for the opcode of the Alieu we have are using switch one to determine if we're going to add

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‫or subtract whenever we want to select the value we're going to place into that A and B and R switch

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‫0 selects which which value we're displaying for displaying value or displaying value B and Button 0

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‫determines if we're going to add or subtract one button to button one is ours check ten button to add

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‫or subtract 100.

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‫Button 3 is the exit queue.

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‫So that will start the Alieu and execute the command.

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‫So to start off we are displaying our switch 0 is pulled down or displaying the FI pull switch up.

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‫Display.

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‫Now both are set to zero and we are initialized so that is why we don't see a difference when we switch

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‫from down to up.

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‫So right now we're just playing a and or add subtract is down.

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‫So we're going to subtract.

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‫Let's pull that up and we'll press button 0.

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‫You can see we're adding one.

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‫If I pull it down the switch too and I hit that we subtraction our down to zero.

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‫I hit it once again.

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‫We go down to a negative one into the negative as indicated by the the far left segments I want to see

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‫why having the centerpiece illuminated so we can go ahead and select the value for a will make it negative

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‫3 and we can go up by 10 or by 100.

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‫And if we just add we can go right back to where negative 3.

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‫So we're at negative 3 on our input A.

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‫If we select down our input B is still 0.

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‫So our input B is now displayed on the 7 segment display.

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‫And just like before we can add if we have our add subtracts which called high if we pull low now we'll

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‫subtract and we can go down the negatives.

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‫But we're going to make our be a positive number so we'll make that a positive too or we'll make it

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‫a positive for.

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‫So our input A is a negative three and B is a positive for.

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‫So right now let's run through the different opcode operations to see how how this works.

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‫So the first opcode operation we have is three zeroes.

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‫So we pool our switch 7 switch 6 and switch 5 all down to zero and if we pressed the execute command

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‫this will take the value of a and display it in the result register.

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‫So to see the value based we poor switch 0 high.

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‫So it's a negative 3.

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‫So by pressing our execute button we now see we have a negative 3 being displayed in our result register

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‫our next command is at 0 0 1 and this will take the value of B which is 0 0 for a place that in the

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‫result register for us to execute.

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‫Now you see we have a value of 4 in our result register our next command is 0 1 0.

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‫So 0 1 0 and this will take the result of a plus b.

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‫So we have our negative 3 plus four is a value of 1 to execute and we'll see 1 shows up in the result

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‫register.

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‫Now for your 0 1 1 that's a minus B.

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‫So 0 1 1 that's a negative 3 minus be negative 3 minus 4 is negative 7 which is the value we see displayed

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‫in our result register.

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‫And now we have two different commands that are used to set all the values to either zero or negative

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‫1.

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‫So if we set you a 1 0 0 1 0 0 for opcode and press execute this is going to set all of the values in

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‫our result register to zero.

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‫So basically we're setting a result back to zero execute our result register.

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‫We can see is set to zero if we do a 1 0 1.

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‫This sets all of the values in a result register to a 1.

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‫Now since we're doing a sign notation This is actually the representation of a negative one because

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‫in VHDL sign notation is represented using two's complement.

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‫And so in twos complement form all ones is the same as a negative one.

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‫So we press execute.

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‫We'll see a negative one display in our result register and that is the Alieu demonstration running

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‫on the basis of or.