WEBVTT 00:00.060 --> 00:04.980 So now we'll try to understand how we use an automatic operating in Virginia, right, so here. 00:05.100 --> 00:11.660 First, let's proceed to decline a signal, OK, which will be holding the source of data for our automatic 00:11.660 --> 00:12.150 clock, right? 00:12.450 --> 00:19.470 So we declare two variables being 119 two, which represent our brand one an opening to four are automatic 00:19.470 --> 00:19.970 block, right? 00:19.980 --> 00:26.130 So we declare them to be of state standard and good logic and disco vector and the size that we specify, 00:26.130 --> 00:30.660 it's full, but similarly to it's also of, say, standard underscore logic, underscore vector. 00:31.050 --> 00:34.110 And then we have a four bit size, right? 00:34.260 --> 00:37.020 So we initialized in one to seven, right? 00:37.030 --> 00:39.000 So this you could clearly guess from here. 00:39.010 --> 00:41.610 So 0111 is equal to seven. 00:42.180 --> 00:42.480 Right. 00:42.480 --> 00:44.100 So this is equal to seven. 00:44.340 --> 00:51.210 And then two is equal to one right now when we consider an attrition rate. 00:51.210 --> 00:55.460 So we need to allocate one more bit to who is the result of carry out, right? 00:55.470 --> 01:00.360 So we declare the variable to hold the result of our addition as well as subtraction. 01:00.570 --> 01:04.170 OK, and here we added the size to be four down to zero. 01:04.170 --> 01:10.500 That is vibrant, so an extra bit is added to hold the result of carry out or about bottom right, then 01:10.650 --> 01:11.790 for a multiplication. 01:11.820 --> 01:18.060 OK, do we should have a size of at least eight because we are working with an all brand of sites for 01:18.070 --> 01:23.340 bitrate, so we should at least look at the size of twice the size that we have for an open rate. 01:23.340 --> 01:28.770 So we declared the variable model and that is the same the size of eight bit rate. 01:28.770 --> 01:30.450 So we initialize it to zero. 01:30.460 --> 01:35.230 And here we are specifying the initialization value in n hexadecimal format. 01:35.230 --> 01:38.070 Hence we have added the suffix as x ray. 01:38.550 --> 01:43.770 So first thing, whenever you want to work with a standard underscore logic, underscore vector, and 01:43.770 --> 01:49.590 to perform an athletic operation is to include the mandatory library, let us assume that we want to 01:49.590 --> 01:51.370 work on an unseen number eight. 01:51.660 --> 01:53.850 So we'll just try to use it properly. 01:54.240 --> 01:58.590 OK, Dot Standard underscore the logic underscore Unsane, right? 01:58.590 --> 02:04.440 So this is the library that you need to include if you wish to work with an automatic operation and 02:04.440 --> 02:07.120 with the standard and disco logic on the score vector type. 02:07.220 --> 02:09.000 Right now, we proceed. 02:09.300 --> 02:15.630 So here we have a signal, so to assign a value to a variable will again be utilizing a signal assignment 02:15.630 --> 02:16.080 operator. 02:16.240 --> 02:20.580 So this is how we work when we have a data flow, more exchange rate. 02:20.580 --> 02:21.700 So addition. 02:21.720 --> 02:24.900 OK, so I will be with to d in one. 02:25.140 --> 02:26.180 OK, Blostein. 02:26.400 --> 02:32.130 Remember that we usually strongly type language, so the size that you have on analogies must be matching 02:32.130 --> 02:34.220 to the size that you have on an interest rate. 02:34.230 --> 02:40.680 So on analogies, you have a size of five bit, whereas in and 192 is having a set of four bitrate. 02:40.980 --> 02:44.940 So if you just perform this edition, we won't be getting any cardio through it. 02:44.970 --> 02:48.360 So what we could do is we could just abandon zero, right? 02:48.360 --> 02:49.500 And it might be OK. 02:49.570 --> 02:54.780 So if fire is originally to carry, that will be automatically added on that fifth bitrate. 02:55.080 --> 02:58.440 So to perform concatenation. 02:58.470 --> 03:04.620 OK, so what we do is let's assume we want to obtain 018 and Mississippi State rate, so we are at an 03:04.620 --> 03:05.100 impasse. 03:05.400 --> 03:08.220 OK, and then we want to append zero and it must be. 03:08.220 --> 03:13.080 So we'll just be at zero in a single rate and the parentheses rate. 03:13.090 --> 03:16.860 So this is how we obtained zero at the Mississippi State. 03:16.920 --> 03:24.090 Now this will make this entire thing firing rate of orbit from the union and the single zero will make 03:24.360 --> 03:26.840 five it four out or opened one right. 03:27.120 --> 03:30.680 Similarly, he will be making this to be also five bitrate. 03:30.690 --> 03:36.510 So we basically match the size that we have on in colleges and an outrageous rate. 03:37.380 --> 03:40.380 Similar thing we will be doing with then subtraction also. 03:40.380 --> 03:44.700 So we'll go ahead and will try to add, OK, subtract, right? 03:45.300 --> 03:49.200 We're here and this should be replaced with the subtraction operator. 03:49.260 --> 03:49.530 Right? 03:49.950 --> 03:53.260 The last thing is for a multiplication right multiplication. 03:53.370 --> 03:59.100 We will just be doing the one rosti into right, so this will automatically return. 03:59.640 --> 04:00.730 We'll give it an asterisk. 04:00.750 --> 04:06.620 We basically retain the result of eight bit and we have an election that is also a size eight great. 04:06.630 --> 04:09.900 So we do not need to perform any additional phases, right? 04:09.900 --> 04:11.490 And they must be right now. 04:11.850 --> 04:14.450 You could see we get a green indication over here. 04:14.460 --> 04:19.500 So that basically means all the package that is required to work with an automatic operator are correctly 04:19.500 --> 04:20.010 specified. 04:20.040 --> 04:26.790 Now, if you just try to in this library, right, so you could clearly see that our compiler won't 04:26.790 --> 04:31.350 be able to understand the proper definition for plus minus an asterisk, right? 04:31.590 --> 04:37.770 If you're just whowere or an error, you could find that we that the compiler won't be able to find 04:37.770 --> 04:39.690 any definition for an operator rate. 04:39.930 --> 04:45.680 So whenever we work with the standard underscore logic on the score vector Unsane type, right? 04:45.870 --> 04:51.030 And if we want to utilize and metric operator, then this is the package which is mandated. 04:51.330 --> 04:56.130 So we'll just see what I could go ahead and try to perform a simulation. 04:56.130 --> 04:59.820 So we already set this source as a top model and S. 05:00.270 --> 05:06.050 So, OK, so we just need to go ahead and try to perform a simulation right now, you could clearly 05:06.050 --> 05:06.440 see. 05:06.890 --> 05:07.190 Right. 05:07.430 --> 05:11.000 So our opinion will have a value of seven offering to have a value of one. 05:11.070 --> 05:11.260 Right. 05:11.270 --> 05:14.810 So the result of violation is seven plus one will result in to it. 05:15.260 --> 05:17.100 The result of the extraction is six. 05:17.120 --> 05:23.570 Now here, since option one is created an opening two and we are performing option one minus 0.2. 05:23.900 --> 05:27.920 OK, so result will be positive rate and it is having a value of zero. 05:28.760 --> 05:33.590 Similarly, the result of multiplication is seven cross one will be set right now. 05:33.590 --> 05:39.710 Let's understand what will happen if we have the result of subtraction, which is negative, right? 05:39.980 --> 05:46.340 And that will happen if we perform the subtraction between Dean two and in one right. 05:46.340 --> 05:48.080 So the two have a value of one. 05:48.320 --> 05:54.470 And Dean one have a value of seven three two one minus seven will be giving us minus six. 05:54.500 --> 05:54.770 OK. 05:54.980 --> 06:00.770 So let it just go ahead and try to see how we how you handle this situation whenever you have a negative 06:00.770 --> 06:02.830 result for a subtraction operation, right? 06:02.850 --> 06:03.650 So we'll just see why. 06:04.310 --> 06:08.900 Now here we are performing a subtraction between the dying two and in one, right? 06:08.900 --> 06:10.760 So this will give us the negative result. 06:11.180 --> 06:15.710 They just go ahead and try to again, just click on this relaunch simulation. 06:15.920 --> 06:23.510 OK, so this will again apply the updated stimulus to our duty and then we'll be analyzing the result 06:23.510 --> 06:26.330 right now here, if you analyze. 06:26.360 --> 06:29.030 So we have a seven right one. 06:29.360 --> 06:32.030 OK, so election result is this makes sense. 06:32.420 --> 06:35.600 And then we have a multiplication result at seven. 06:35.600 --> 06:41.600 But if you analyze the subtraction, we are getting one zero to let it just go ahead and try to change 06:41.600 --> 06:44.300 the relics to an unseen decimal rate. 06:44.300 --> 06:47.870 So if you just select an unseen decimal, you get twenty six, right? 06:47.870 --> 06:54.380 And if you just select the same decimal, you will be clearly finding that you are getting minus six, 06:54.380 --> 06:54.620 right? 06:54.620 --> 06:57.020 So whatever value that you see over here, right? 06:57.020 --> 07:02.360 So if you just convert this to a binary, this is basically a CPU's complement value when we have a 07:02.360 --> 07:03.460 negative result, right? 07:03.470 --> 07:08.630 So let it just go ahead and try to see how we get minus six out of it, right? 07:08.810 --> 07:12.770 So the value that we have over here is one one zero one zero eight. 07:13.280 --> 07:17.060 So the value that we get after subtraction is one. 07:18.750 --> 07:22.020 One zero one zero. 07:22.110 --> 07:22.380 Right. 07:22.650 --> 07:26.540 So first thing to observe is what you have it, and I miss pubic trade. 07:26.550 --> 07:30.750 So this is one that basically mean the result is negative. 07:30.870 --> 07:31.010 Right. 07:31.010 --> 07:34.680 So this is the first instance out of this result, right? 07:34.980 --> 07:42.650 Then as we have a negative result, OK, we need to find the two compliment value to predict, right? 07:42.660 --> 07:45.960 So let it just invert all the bits that we have in the. 07:46.440 --> 07:48.150 So one will be inverted to zero. 07:48.390 --> 07:55.170 One will be negative two zero zero two one one two zero and zero to one right and after. 07:56.120 --> 08:03.050 Inverting this, basically is to just give this one compliment right now, we proceed and add one to 08:03.050 --> 08:05.090 this to get the two compliment value, right? 08:05.090 --> 08:08.210 So when and when will returning to zero? 08:08.240 --> 08:11.060 And here we have a carry rate, so this will be one. 08:11.450 --> 08:12.470 This will be one. 08:12.470 --> 08:14.150 And then we have a two zero three. 08:14.420 --> 08:18.260 So if you find out any equal in decimal, so this will be six today. 08:18.650 --> 08:25.140 So the result this is equivalent to minus six. 08:25.400 --> 08:29.500 This is what we get because we are subtracting one minus seven, right? 08:29.510 --> 08:33.250 So this is how you handle the situation when you get the negative number right.