WEBVTT 00:00.150 --> 00:05.490 We already discussed on how we use a logical operator, OK, with the data flow modeling state. 00:05.520 --> 00:09.470 Now we want to understand the next operator, right? 00:09.480 --> 00:15.750 Remember that the operator that we are covering over here are equally eligible for either modeling styles. 00:15.840 --> 00:22.850 So this operator that we are discussing in the data flow modeling state are not restricted only to data 00:22.860 --> 00:28.260 flow modeling state, but operator in general are eligible for all the modeling state, right? 00:28.500 --> 00:33.720 So we'll just be building up our foundation of an operator in this data flow modeling state and as we 00:33.720 --> 00:39.000 progress to other modeling state, will discuss some of an important concept related to that right? 00:39.330 --> 00:40.980 So we already have a logical operator. 00:40.980 --> 00:46.170 The next operator that we're going to discuss is shift operator, as well as the rotation of it, right? 00:46.530 --> 00:51.480 So the rest was discussed the fundamentals of shift down rotation operator. 00:51.480 --> 00:57.420 And then we proceed to discuss the ways we have in a deal to achieve it, right? 00:57.720 --> 01:02.190 So shift could be categorized into two. 01:02.910 --> 01:05.830 So it could either be a logical shift, OK? 01:06.300 --> 01:10.370 Or it could also be an automatic shift, right? 01:10.380 --> 01:16.710 So in this case, when we perform a right shift, we basically preserve the but that is the only difference 01:16.710 --> 01:19.770 that we have with an automatic ideological operation. 01:19.770 --> 01:23.400 So we'll be discussing in a word that means OK, logical. 01:23.910 --> 01:25.320 Operator OK. 01:25.330 --> 01:27.690 Could be further categorized into two. 01:27.870 --> 01:34.080 OK, so it could either be a left logical shift, OK, or it could be a radiological shift. 01:34.110 --> 01:34.410 All right. 01:34.890 --> 01:41.310 So if you consider automatic, there are also two categories rated could either be a lift automatic 01:41.310 --> 01:43.500 shift or it could be right. 01:43.680 --> 01:49.950 Automatic shift data automatically left shift and logical left shift are exactly equivalent right. 01:49.950 --> 01:56.190 So we see that they do not exist anything like automatic left shift right because both of them operating 01:56.190 --> 01:58.170 in exactly same fashion. 01:58.530 --> 02:03.950 But when we consider an automatic right and logic lights, there exists a huge difference, right? 02:03.960 --> 02:05.160 That is what we want to discuss. 02:05.170 --> 02:09.890 So first, let's just understand how a logical shift work, right? 02:09.900 --> 02:13.020 So we consider first a logical shift. 02:13.020 --> 02:16.770 OK, assume that we have a full arbitrate this, right? 02:16.770 --> 02:23.280 So this is the full bit registered that we have and the container that we have in a register is one 02:23.280 --> 02:27.480 zero zero right now if you want to perform a left shift right. 02:27.480 --> 02:32.760 So when we see a left shift, we basically add the zero in and Elizabeth little betrayed. 02:32.770 --> 02:34.850 So here we have our end gesture. 02:34.860 --> 02:42.000 So when we considered the left shift right, so left shift by this specific position, let's assume 02:42.000 --> 02:43.430 the position is one. 02:43.440 --> 02:49.290 So we basically add a single zero right single zero at 10, unless be saved right? 02:49.620 --> 02:54.730 And then you'll be noticing that since we already have a full present in our gesture. 02:54.810 --> 03:00.670 OK, so the big or the value that we have on an MSP will be automatically true. 03:00.690 --> 03:06.120 Not great because we have added a new value, which is zero at LSP. 03:06.130 --> 03:09.300 Say now when we consider the right shift. 03:09.300 --> 03:18.150 OK, so the operation is exactly opposite, so we add a zero on an MSP site and whatever we have the 03:18.150 --> 03:21.300 canteen on and this debate will be thrown out great. 03:21.780 --> 03:25.590 So this bit basically make the position where we could c, right? 03:25.590 --> 03:29.220 So those are the two logical shift operations that we have right now. 03:29.220 --> 03:37.380 What we're going to do is let it just work with one zero zero hand with the register that we have granted. 03:37.740 --> 03:42.090 Now if you want to perform the left shift, OK and the bit. 03:42.840 --> 03:46.860 So we just want to shift by one right, so left shift by one. 03:47.250 --> 03:52.410 What that will do is basically whatever we have on and it may be saying, OK, so that will be thrown 03:52.410 --> 03:52.650 out. 03:53.430 --> 03:57.660 OK, whatever we have on the next big two zero will be coming over here. 03:57.690 --> 04:00.530 OK, so now here we have zero, right? 04:00.690 --> 04:03.480 So we'll again draw a full compartment rate. 04:03.480 --> 04:05.340 So this seal will come over here. 04:05.580 --> 04:08.280 This zero will come over here. 04:08.670 --> 04:11.460 This one will come over here. 04:11.670 --> 04:20.430 And finally, when we considered the left shift, OK, we basically add zero in then l'esprit right. 04:20.650 --> 04:21.450 This makes sense. 04:22.140 --> 04:27.040 Next, if you consider this is you may want to perform shift by factor of two, right? 04:27.050 --> 04:31.170 So here again, we have that is you. 04:31.950 --> 04:34.200 This is our original value, right? 04:34.410 --> 04:37.590 And we want to perform ship by a factor of two, right? 04:38.040 --> 04:45.810 So in this case, if we have this four compartment available, right, so ship by a factor of two. 04:45.810 --> 04:49.290 So two bit for my name is beside will be thrown out, right? 04:49.290 --> 04:50.550 So this debate will be gone. 04:50.940 --> 04:52.440 This will be gone, right? 04:52.620 --> 04:55.260 And whatever we have next, that is zero. 04:55.290 --> 04:55.620 OK. 04:55.950 --> 04:59.490 That will basically come over here right on an MSP. 04:59.740 --> 05:01.300 So we have zero over here. 05:01.680 --> 05:08.920 Then we have one over here, and finally, we need to add to see if this makes sense, why we have to 05:08.920 --> 05:13.150 add two zeros because we want to perform shift by the factor of two. 05:13.160 --> 05:18.640 This is how we get the value for logical shift, right? 05:19.570 --> 05:27.310 Hey, that too in the left direction right now, if you want to perform a logical shift, OK? 05:27.820 --> 05:29.680 And that too in the right direction. 05:29.740 --> 05:37.750 OK, so ladies, you we have to register with the contained of one zero zero one right now if you want 05:37.750 --> 05:43.120 to perform a right check by a factor of one right in that case, and it is just draw four compartments 05:43.120 --> 05:44.680 where we could add the data. 05:44.980 --> 05:51.260 So when we see right shift, so whatever we have on in a list, we bet will be thrown out, right? 05:51.280 --> 05:55.240 And this basically make the place for the zero to be added on. 05:55.240 --> 05:56.230 And I misspoke, right? 05:56.620 --> 05:59.740 So here we have a zero that will be coming over here. 06:00.070 --> 06:02.230 This zero will be coming over here. 06:02.290 --> 06:07.900 This one will be coming over here and this bit will be filled with seat, right? 06:07.960 --> 06:10.340 This is how we perform the right. 06:11.170 --> 06:19.720 We basically throw out whatever bit we have on the LSP side, OK, and then we add the seat right? 06:19.720 --> 06:20.740 And it must be said great. 06:20.740 --> 06:25.010 So this is how we perform the logical shift. 06:25.090 --> 06:25.430 OK. 06:25.720 --> 06:27.480 No advantage with logical shift. 06:27.480 --> 06:33.730 This, for example, let's assume we do not overflow the size of where is this right? 06:33.730 --> 06:40.160 So if you have zero zero one zero right, so this is the container now if you perform the left shift 06:40.240 --> 06:40.550 right. 06:40.550 --> 06:47.560 So if you perform the left shift, so contained will be the zero will be thrown out right. 06:47.560 --> 06:52.840 And then we have this zero right and then maybe this one right and next. 06:52.840 --> 06:54.160 And then this year, right? 06:54.160 --> 06:55.420 And finally, we have been zero. 06:55.690 --> 07:02.950 Now, if you can guess, the equivalent decimal value for this is to right when we both left shift two, 07:02.950 --> 07:06.970 this is equivalent to four right to be able to multiply by two. 07:07.240 --> 07:10.780 So this help us to implement a multiplier. 07:10.810 --> 07:13.510 OK, so depending on the shift. 07:15.930 --> 07:21.990 We perform great, so, for example, and is the number of ship that we want to perform, right? 07:21.990 --> 07:23.010 In this case, it is one. 07:23.400 --> 07:26.820 So whatever value the original value that we have. 07:26.940 --> 07:32.520 So after the shifting operation, we'll be getting the value, which is multiplied by two, restrain 07:32.520 --> 07:36.020 red and represent the number of ships that we perform, right? 07:36.060 --> 07:37.800 So if you want to perform ship, buy one. 07:38.100 --> 07:39.390 So this end will be one. 07:39.410 --> 07:42.300 And in that case, the original value will be multiplied by two. 07:42.690 --> 07:45.840 Similarly, if you consider all right, shift trade. 07:46.170 --> 07:53.530 So in this case, what will happen is so this bit, this bit will be thrown out, right? 07:53.670 --> 07:56.610 We again have four compartments, so this gate will be thrown out. 07:56.940 --> 07:59.550 And then this one will be coming at LSP. 07:59.550 --> 08:04.350 Then we have zero zero and we'll add zero when we consider right ship, right? 08:04.810 --> 08:09.150 If you calculate the equal and value for this register, so it is one. 08:09.180 --> 08:11.460 So you could clearly guess the original value is two. 08:11.700 --> 08:17.100 And when we perform right ship two, we get basically original value divided by two race to end very 08:17.100 --> 08:19.510 and represent the number of ship that we perform, right? 08:19.530 --> 08:24.150 In this case, we perform shift by a single bit position. 08:24.210 --> 08:29.950 OK, in that case, we will be getting additional value by two to one, which is dividing by two to 08:29.960 --> 08:32.910 so to divide by two, it'll basically result into one, right? 08:32.910 --> 08:36.210 So we could easily perform this computation. 08:36.270 --> 08:36.630 OK. 08:36.750 --> 08:42.540 With the logical shift, right, the next one that we have is an automatic shift, right? 08:42.750 --> 08:47.220 So this can again be divided into two categories so left. 08:47.370 --> 08:48.480 And we have. 08:49.320 --> 08:49.950 Right, right. 08:49.950 --> 08:50.520 So left. 08:51.780 --> 08:58.440 Will operate exactly similar to what we discussed in a logical left shift, or guess who will not be 08:58.440 --> 08:59.020 discussing it? 08:59.040 --> 09:05.310 This will be exactly equal to what we discuss with the logical left right when we consider right, for 09:05.310 --> 09:07.590 example, the latest, as you will. 09:07.890 --> 09:11.110 So one see to see it right. 09:11.160 --> 09:16.350 So automatically, if this predominant view delays, when we work with the same number 18, it may be 09:16.350 --> 09:18.690 better present the same bitrate. 09:18.690 --> 09:21.450 So this is the same bit that we have for a number. 09:21.450 --> 09:24.540 And this basically represented the No is the negative number, right? 09:24.870 --> 09:25.980 When by design. 09:26.280 --> 09:30.500 So when we perform right shift, let's assume we perform a shift by a factor of one. 09:30.810 --> 09:33.240 So we again have a four compartment, right? 09:33.600 --> 09:40.290 So this weight will be thrown out, OK, to make the place for one bit rate. 09:40.290 --> 09:41.580 So we will be going. 09:41.820 --> 09:42.540 This will be going. 09:42.870 --> 09:45.490 This zero will be coming over here. 09:45.540 --> 09:47.670 This zero will be coming over here. 09:48.060 --> 09:49.950 This one will be coming over here. 09:50.190 --> 09:57.850 But now when we consider the automatic shift, OK, so it maintains the sine bitrate. 09:57.850 --> 10:00.600 So whatever value that we have on hand is beside. 10:00.650 --> 10:02.100 OK, so that represent the same. 10:02.370 --> 10:06.810 So we maintain the same value at the same rate. 10:06.840 --> 10:13.070 So here we do not have been zero as we are doing with the logical automatic and logical right chip. 10:13.100 --> 10:17.640 OK, but in a case of an automatic right shift, we preserve the same bitrate. 10:17.640 --> 10:23.790 So this will be as it is at whatever value that we have over here will be shifted on the right side, 10:23.790 --> 10:24.030 right? 10:24.030 --> 10:28.830 So to consider one more example, let's assume the same value, right? 10:28.830 --> 10:35.190 We have one zero zero one against the same value, but in this case, the factor of shift is to right. 10:35.250 --> 10:39.540 We need to perform shift by the double digits rate. 10:39.540 --> 10:42.180 So we again draw for compartment. 10:43.170 --> 10:43.470 OK. 10:43.710 --> 10:44.790 Again, same with this one. 10:45.120 --> 10:47.760 So this debate will be gone, right? 10:47.760 --> 10:50.430 So this zero will be coming over here. 10:50.460 --> 10:53.110 This one will be coming over here. 10:53.430 --> 10:54.750 Then again. 10:54.900 --> 10:59.880 OK, so we will whatever value that we have on n same, but will be again. 10:59.880 --> 11:02.850 Our data were here and here. 11:03.390 --> 11:03.730 Right. 11:04.380 --> 11:12.090 So whatever we have on assignment, OK, we will be adding that value on the bits that are left when 11:12.090 --> 11:14.680 we remove the bit, for example, distributor input. 11:14.970 --> 11:17.190 OK, so we have this stupid right. 11:17.190 --> 11:23.340 So after we perform shifting right, this two will be shifted right here, right? 11:23.520 --> 11:28.710 And whatever bit left there, we add a sign which greatly in this case you are saying which is one. 11:28.980 --> 11:32.470 OK, so would the position will be filled with the same bit value? 11:32.530 --> 11:35.940 That is what now if we're going to do that, if we have. 11:37.110 --> 11:39.000 OK, zero on insane, right? 11:39.030 --> 11:39.300 Right. 11:39.300 --> 11:41.070 So zero one one zero. 11:41.070 --> 11:42.690 Let's assume this is the value right? 11:43.230 --> 11:45.990 And we perform shift by a factor of two. 11:46.200 --> 11:46.500 Right? 11:46.680 --> 11:49.410 So again, for a compartment we have. 11:49.830 --> 11:50.160 Right. 11:50.250 --> 11:54.520 So this tool will be gone right because we want to perform well, right? 11:54.520 --> 11:55.860 Shift right to this two bit. 11:55.860 --> 11:59.950 This two values will be coming out zero one, whatever value that we have. 11:59.970 --> 12:01.970 So this one will be coming over here. 12:01.980 --> 12:03.660 This zero will be coming over here. 12:03.960 --> 12:09.840 And then the two positions that are left will be filled with whatever value that we have on the same 12:09.840 --> 12:10.260 bit rate. 12:10.260 --> 12:11.760 So here we have a value of zero. 12:12.090 --> 12:14.700 So this two position will be filled with the Z, right? 12:14.700 --> 12:17.600 So this is how we perform automatically, right? 12:17.710 --> 12:18.050 Right. 12:18.120 --> 12:23.070 So these are the four operation that we frequently utilize an automatic operation. 12:23.070 --> 12:25.380 We predominantly work with the same number, right? 12:25.710 --> 12:32.010 And when we discuss the function that are used to specify which type of shift that we are utilizing, 12:32.010 --> 12:37.310 we'll get to the are differentiated on the basis of the data rate that we are specifying. 12:37.320 --> 12:42.880 So when we specify Unsane, so that basically give us the logical shift and then we can the same to 12:43.110 --> 12:48.160 be automatically give us the ultimate ActionScript. 12:49.080 --> 12:56.370 So just to summarize, we have two type of shift, OK, that will either be a logical shift, or it 12:56.370 --> 12:58.890 could either be an automatic 13:01.440 --> 13:02.100 shift, right? 13:02.310 --> 13:07.500 So logic, a shift can be further divided into two could either be right or left. 13:07.560 --> 13:15.120 Similarly, automatic could be divided into right and left right in this case, when we consider a logical 13:15.120 --> 13:15.540 right. 13:15.690 --> 13:18.160 OK, so when we consider logical, right? 13:18.240 --> 13:20.310 So we had zero. 13:20.430 --> 13:24.410 OK, two and pivot again, we removed a lisp, right? 13:24.420 --> 13:29.010 So this is how we perform the right shift and when we consider the logical left right. 13:29.250 --> 13:35.070 So we are zero from an Elizabeth site and we remove the bit from an image we say, right? 13:35.070 --> 13:37.710 So this is how we make a prediction for zero to be added. 13:37.840 --> 13:45.060 And unless we pretend when we consider are automatic so left or exactly operate as we have ideological 13:45.060 --> 13:45.370 left. 13:45.390 --> 13:49.050 OK, so this is exactly similar we will be having. 13:50.580 --> 13:55.200 Who will be adding the euro to analyze the site and reviewing out the mystery bit? 13:55.800 --> 13:59.560 But when we consider the right shift, so we will be maintaining the same bit. 13:59.560 --> 14:05.630 So even though the shift operation will be exactly grueling, that is the bit that we have wanted in 14:05.640 --> 14:06.690 this bill will be removed. 14:06.900 --> 14:14.850 But whatever value that we have, an insane bit is used to feel the Viking position, right, so it 14:14.850 --> 14:16.290 will not be filled with a zero. 14:16.500 --> 14:23.490 Instead, it will be filled with whatever the value that we have for sign bitrate that is the MSP better 14:23.490 --> 14:24.500 off register. 14:24.540 --> 14:31.080 So remember this fundamental because these are useful as we progress to use the functions that are available 14:31.080 --> 14:32.610 to perform shift operation in.