WEBVTT 00:08.330 --> 00:14.570 Walk them to the demonstration of the multiplier running on the basis through your board here I have 00:14.570 --> 00:19.250 the complete design for the multiplier running on the basis through your board. 00:19.790 --> 00:28.520 And we have the product which is the output the multiplication is mapped to all of the 16 different 00:28.620 --> 00:37.570 ladies we have on our board and our inputs are mapped to we have input 1 is the first 8 switches are 00:37.680 --> 00:42.020 basically board and the input 2 is our second switches. 00:42.260 --> 00:47.410 So we have 2 8 but 8 bit inputs that we're using for this multiplier. 00:47.570 --> 00:55.740 And we have our star which is the center button on the basis three board our reset is a top button. 00:56.090 --> 01:02.140 So to run this demonstration I'm going to go ahead and just run through a few quick easy multiplications 01:02.150 --> 01:06.460 because we start getting to larger numbers or gets a little more complex. 01:06.470 --> 01:11.810 So right here I have an input of one in all zeros and a 1. 01:11.840 --> 01:14.480 So what I'm doing is multiplying one times one. 01:14.600 --> 01:19.690 When I push the start button I should see a binary one represented on the bottom. 01:19.900 --> 01:26.180 So let's go ahead and press the center button and if you notice the least the least significant bit 01:26.540 --> 01:31.610 is lit up which is telling us that we have all of the original one and that is a binary one which makes 01:31.610 --> 01:34.040 sense we have a 1 times 1. 01:34.040 --> 01:44.810 Now if I make the second input 1 1 we have a 1 times a 3 so we're output should be at 3 which is a 1 01:44.810 --> 01:45.580 1. 01:45.590 --> 01:49.300 Now in order to do that we need to hit our reset the top button. 01:49.310 --> 01:51.620 You don't notice that all the ladies cleared. 01:51.790 --> 01:58.190 So go Figler hadn't hit the center button which is a start but we should see a one time three as our 01:58.190 --> 02:03.660 output which is a binary 3 which is represented as a 1 1. 02:04.010 --> 02:06.230 So now I'm going to take a little bit larger number. 02:06.290 --> 02:13.640 We're going to have a binary three times a binary three which should give us a binary 9. 02:13.640 --> 02:16.650 So it's go ahead and hit our clear. 02:16.650 --> 02:21.980 And you notice that the always clear and are most multipliers ready to notification again. 02:21.980 --> 02:26.300 So 1 1 times of 1 1 which is a three times of 3. 02:26.330 --> 02:29.850 So we should see a binary 9 appear on a Bonomo IDs. 02:30.050 --> 02:36.340 Let's get our start button then we'll see that we have a 1 0 0 1 which the first one is the value of 02:36.340 --> 02:43.910 A and two zeroes Plus our last one which is the value of 1 gives us a representation of 9. 02:43.930 --> 02:46.850 So this is how you can test your multiplier works. 02:46.880 --> 02:50.730 And I've gone through and run some big numbers through and it does work. 02:50.740 --> 02:55.080 However it's kind of hard to do the math here but if you just put some random numbers. 02:55.330 --> 03:00.640 So we have 1 0 1 1 times 1 1. 03:00.640 --> 03:02.050 If I had to clear. 03:02.200 --> 03:08.620 You'll notice that all the ladies go to zero indicating we're ready to start a multiply multiply that 03:08.620 --> 03:18.970 is the output 1 0 0 0 0 1 is the output of multiplying 1 1 times 1 0 1 1 and you go through any different 03:18.970 --> 03:19.660 combination. 03:19.660 --> 03:23.260 We have 8 input values. 03:23.260 --> 03:30.670 So we could toggle just randomly toggle into bits here and I'm going to go ahead and leave this a challenge 03:30.670 --> 03:36.400 for you to go ahead and you should be able to do binary to death smoke emergence So take these two numbers 03:36.760 --> 03:42.670 in binary and convert them to decimal perform the multiplication and turn that value back into an area 03:42.700 --> 03:46.170 and see if that's what value actually see on the ideas below. 03:46.180 --> 03:48.240 And that's how you can test the multiplier. 03:48.700 --> 03:50.510 So I'm going to go ahead and hit clear. 03:50.620 --> 03:52.540 Press the run button again. 03:52.540 --> 04:01.330 And as you see as we have larger numbers as a 1 1 0 0 0 1 1 times are 1 1 0 1 1. 04:01.360 --> 04:02.520 This is the output. 04:02.620 --> 04:07.570 So it gets to be relatively large numbers but it's pretty cool in that we can perform this multiplier 04:07.810 --> 04:12.200 on our FPGA without actually using a dedicated multiplier on the FDA. 04:12.250 --> 04:14.660 So just kind of helps with resource utilization. 04:14.980 --> 04:22.090 So get a good clear again and the best way to test this is just kind to start with very simple values 04:22.590 --> 04:26.680 where we have the 1 1 times or 1. 04:26.680 --> 04:30.360 So are three times one which gives us the value of three. 04:30.410 --> 04:34.860 And I would suggest when you run this that's the first way to sort out do your one times one one times 04:34.870 --> 04:36.640 two one times 3. 04:36.730 --> 04:37.640 So on and so forth. 04:37.640 --> 04:38.470 That's an easy math. 04:38.470 --> 04:41.110 And then go ahead and try a complex number. 04:41.110 --> 04:44.830 So that is how the multiplier lab runs on the bases for.