1 00:00:01,520 --> 00:00:02,120 Hi everyone. 2 00:00:02,120 --> 00:00:08,670 So in this video we want to understand the difference between the text file and the binary files so 3 00:00:09,360 --> 00:00:12,960 the definition is very simple text file that those file that are human literally. 4 00:00:12,960 --> 00:00:19,500 Well so basically human can easily read text files but binary files are not very human friendly so they 5 00:00:19,500 --> 00:00:27,540 are basically machine readable now let's see how the data will be stored in text and the binary file. 6 00:00:27,540 --> 00:00:33,140 So for example in your program if you're doing something like this in Texas 23. 7 00:00:33,360 --> 00:00:36,480 So if you want to store the data in binary files so what will happen. 8 00:00:36,490 --> 00:00:37,790 So this 23. 9 00:00:37,890 --> 00:00:39,820 So what is a binary representation of twenty. 10 00:00:39,810 --> 00:00:44,070 So this is 1 0 1 1 1. 11 00:00:44,070 --> 00:00:49,070 And we know basically integer is of 4 bytes so 4 bytes means 32 bits. 12 00:00:49,080 --> 00:00:59,200 So basically in binary what will happen you will have to do two bits so these are two little bits first 13 00:00:59,290 --> 00:01:06,940 eight bits are all zeros the next eight bits are also all zeros the next eight bits are also all zeros. 14 00:01:07,420 --> 00:01:13,900 So then here you have 1 0 1 1 1 and then there are three zeros. 15 00:01:13,900 --> 00:01:16,320 So basically this will be stored in your binary file. 16 00:01:16,320 --> 00:01:18,110 So this is 0 0 0 0. 17 00:01:18,130 --> 00:01:19,800 You can write all the zeros. 18 00:01:19,810 --> 00:01:22,360 And finally you will have 1 0 1 1 1. 19 00:01:22,890 --> 00:01:23,130 Okay. 20 00:01:23,140 --> 00:01:27,720 So you're buying verifiable stored data in this format. 21 00:01:27,740 --> 00:01:31,890 Now let's see how this string degree will be stored in our text file. 22 00:01:31,940 --> 00:01:36,410 So what will happen first of all this too will be converted into into its archive and do so ask any 23 00:01:36,410 --> 00:01:38,270 value of two is actually 50. 24 00:01:38,480 --> 00:01:44,530 Similarly t will be converted into its ask value and ask the value of trees 51 so missing really my 25 00:01:44,530 --> 00:01:51,790 mother to ask a value of 0 is 49 and similarly it will go on so that I ask a value of when will be fifty 26 00:01:52,120 --> 00:01:55,800 and it will go on like this so what will happen. 27 00:01:55,800 --> 00:01:59,880 This tool is going to be converted in goods ask a character called. 28 00:01:59,880 --> 00:02:01,380 So this value is actually 50. 29 00:02:01,380 --> 00:02:02,700 So what will happen. 30 00:02:02,850 --> 00:02:09,850 So this 50 is going to be converted into its binary form and its binary farmers 1 1 0 0 1 0. 31 00:02:09,990 --> 00:02:19,860 And similarly the binary form of 51 is 1 1 0 0 1 1 and basically ask take only one bit so you take only 32 00:02:19,860 --> 00:02:26,350 one byte so how many boots are there one two three four five and six so two zeros will be appended here 33 00:02:26,680 --> 00:02:30,960 and twos the list will be appended here then in the text format what will happen. 34 00:02:30,970 --> 00:02:32,470 I was told it in this format. 35 00:02:32,530 --> 00:02:35,660 1 0 0 1 1 0 0 1 0. 36 00:02:35,710 --> 00:02:38,760 So this thing and now I restored this thing. 37 00:02:38,800 --> 00:02:44,020 So this is actually 0 0 then 1 1 0 0 1 1. 38 00:02:44,140 --> 00:02:50,650 So this is how I was told the data in the text file and this is how I will store the data in our binary 39 00:02:50,650 --> 00:02:51,300 file. 40 00:02:51,310 --> 00:02:56,250 Now I told you that the text files are human readable but I don't think this is your money really well 41 00:02:57,190 --> 00:02:58,370 so why I told you that. 42 00:02:58,410 --> 00:02:59,740 Takes to until you manage really well. 43 00:02:59,750 --> 00:03:00,880 So let's discuss. 44 00:03:00,900 --> 00:03:04,930 So what will happen you will open the text file into your notepad. 45 00:03:05,140 --> 00:03:14,920 Now what nobody will do so it will pick the first 8 bits it will pick the first 8 bits and it will convert 46 00:03:14,990 --> 00:03:16,150 into its ask value. 47 00:03:16,180 --> 00:03:20,920 So this is going to lose actually Fifty and fifty is corresponding to three of these corresponding to 48 00:03:20,920 --> 00:03:21,430 two. 49 00:03:21,490 --> 00:03:24,280 So instead of this the notepad will print two. 50 00:03:24,460 --> 00:03:27,520 Similarly it will pick the next eight bits. 51 00:03:27,670 --> 00:03:33,340 Again it will find out the ask value which is fifty one then the character corresponding 251 is three 52 00:03:33,640 --> 00:03:34,890 so three will get printed. 53 00:03:34,930 --> 00:03:38,500 If you will open the file in notepad but this is binary. 54 00:03:38,710 --> 00:03:41,400 So if you will open the binary filing notepad. 55 00:03:41,470 --> 00:03:42,180 So what will happen. 56 00:03:42,180 --> 00:03:44,560 It will pick the first 8 bits. 57 00:03:44,560 --> 00:03:50,140 So the first 8 bits are actually 0 also the first eight which set actually 0. 58 00:03:50,140 --> 00:03:51,210 So it will happen. 59 00:03:51,250 --> 00:03:55,000 The correct corresponding to ask I lose you know will get printed. 60 00:03:55,000 --> 00:03:58,960 So what is the character corresponding to the sky values 0. 61 00:03:59,040 --> 00:04:04,990 So ask a value 0 and the character corresponding to asking will lose zero sum will be a very meaningful 62 00:04:04,990 --> 00:04:05,580 character. 63 00:04:05,680 --> 00:04:09,600 Very strange Celtic Bill question mark or it can be anything. 64 00:04:09,760 --> 00:04:13,320 So we know that there will be some asking will look corresponding. 65 00:04:13,420 --> 00:04:14,270 I think it is nil. 66 00:04:14,320 --> 00:04:17,730 Yes I remember it isn't an so this isn't that. 67 00:04:17,750 --> 00:04:22,050 So what will happen now it will get printed again the next eight which are evil. 68 00:04:22,330 --> 00:04:24,340 So again none will get printed. 69 00:04:24,340 --> 00:04:26,050 Again the next asking value of zero. 70 00:04:26,060 --> 00:04:28,090 So again none value will be rendered. 71 00:04:28,240 --> 00:04:31,770 And this is actually so what is this number. 72 00:04:32,590 --> 00:04:33,910 So this number was twenty three. 73 00:04:33,910 --> 00:04:39,340 So the asking value corresponding to quantity will get printed and it will be a very strong symbol. 74 00:04:39,730 --> 00:04:41,910 So let's say this question mark. 75 00:04:42,100 --> 00:04:44,050 It will be a very meaningful symbol. 76 00:04:44,050 --> 00:04:45,420 So finally what will we had output. 77 00:04:45,430 --> 00:04:51,070 This will be it output to fill open the file if you open the binary file in notepad so and we know this 78 00:04:51,070 --> 00:04:53,660 is very meaningful to us. 79 00:04:53,830 --> 00:04:56,140 So this is under meaningful unintelligible 80 00:04:59,390 --> 00:05:02,000 so this thing is unintelligible. 81 00:05:02,210 --> 00:05:09,560 So that's why I told you that the text files are actually humility devil and the binary files are basically 82 00:05:09,560 --> 00:05:10,340 machine readable. 83 00:05:11,540 --> 00:05:19,210 So how can we read and write it out into the text file so we can use these operators so we can use this 84 00:05:19,210 --> 00:05:21,850 operator to read and write it into a text file. 85 00:05:21,850 --> 00:05:28,300 Now if you want to read and write data in two binary file then basically in C++ you have a mode and 86 00:05:28,300 --> 00:05:31,960 this mode is actually a US I don't remember exactly. 87 00:05:32,380 --> 00:05:34,140 So I think it is a US binary. 88 00:05:35,890 --> 00:05:41,230 So this is the mode if you want to take if you want to read and write data to a binary file and there 89 00:05:41,230 --> 00:05:42,370 are also functions. 90 00:05:42,490 --> 00:05:46,000 So the functions are doing the function to read the data. 91 00:05:46,420 --> 00:05:55,530 And similarly you have a function right so this read function is actually in the class ice cream. 92 00:05:55,540 --> 00:05:57,310 I think it is input stream. 93 00:05:57,820 --> 00:06:06,120 And similarly the right function is present in the class output stream. 94 00:06:06,180 --> 00:06:08,150 Now let's discuss which one is faster. 95 00:06:08,520 --> 00:06:14,760 So text or binary so actually binary our faster binary files are faster and the text files a slower 96 00:06:14,790 --> 00:06:19,040 via this slower it is slower because of the conclusion. 97 00:06:19,080 --> 00:06:23,180 So this is how we are studying the data and this is how we are displaying the data. 98 00:06:23,190 --> 00:06:28,840 So basically there is some calculation involved and you do the calculation it becomes slower and it 99 00:06:28,850 --> 00:06:34,620 is faster now let us discuss which will take more space. 100 00:06:34,650 --> 00:06:40,260 So basically this is going to take more space why more space. 101 00:06:40,260 --> 00:06:46,480 And this is going to take less space so let us consider one example so suppose you want to store this 102 00:06:46,480 --> 00:06:47,290 number. 103 00:06:47,290 --> 00:06:50,970 So you have something like an X equals let's say a bigger number. 104 00:06:51,190 --> 00:06:56,320 So let's say 4 7 3 2 5 and 6. 105 00:06:56,320 --> 00:07:00,060 Now if you want to store this number in binary what will happen. 106 00:07:00,070 --> 00:07:05,990 So again binary integer is basically 32 bits or we can say for bytes. 107 00:07:06,010 --> 00:07:11,550 So if you want to store this number in binary it will take four bytes simple. 108 00:07:11,770 --> 00:07:13,080 So just like here. 109 00:07:13,420 --> 00:07:17,460 It is going to take four bytes or you can set twenty two bits. 110 00:07:17,470 --> 00:07:20,370 Now let's see how much space will be taken. 111 00:07:20,500 --> 00:07:22,990 If I want to store this number in the text file. 112 00:07:22,990 --> 00:07:24,100 So again what will happen. 113 00:07:24,100 --> 00:07:33,120 Each digit will be converted to ask value and we know the square value is basically one byte you can 114 00:07:33,120 --> 00:07:33,360 see. 115 00:07:33,360 --> 00:07:39,660 So this is one byte so this is one byte then two byte then three then four and five and six. 116 00:07:39,660 --> 00:07:47,440 So if you want to store this number in the text format in the text format you will take six bytes so 117 00:07:47,470 --> 00:07:53,650 each digit will take one byte so you will take six bytes here and you are taking only four bytes here. 118 00:07:54,220 --> 00:08:02,480 So it's a binary files are taking less space in binary files are faster now the only advantage that 119 00:08:02,540 --> 00:08:06,080 text file have is basically the added human leader table. 120 00:08:06,080 --> 00:08:12,080 So this is the only advantage the text file not having that they are human leader table and binary files 121 00:08:12,090 --> 00:08:17,390 are basically machine readable rest everything binary files will win. 122 00:08:17,530 --> 00:08:24,720 So binary files are Foster and binary files are taking less space and I want this text file has is basically 123 00:08:24,780 --> 00:08:29,260 we can understand them and we can not understand designed to be filed. 124 00:08:29,460 --> 00:08:32,840 So that is all about the text and the binary file. 125 00:08:33,600 --> 00:08:35,530 So I will see you in the next video by.