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Hi everyone.



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So in this reader we will discuss that topic template.



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So I have written some code.



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First I will explain you the code.



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So I have created this class glass beer so I have a glass beer.



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So it has two private properties X and Y and both are in danger.



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So then we have public.



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So we have set text function.



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It will take X and I don't assign the value of x to this X..



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Right.



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And similarly we have ghettos and setters.



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So it is returning the value fix.



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Similarly this is set to y function.



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It will set the value of y.



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And similarly we have got Y function and it is going to return the value of a.



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So we have simple getters and setters.



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Now what I want to do so I want to create this beer glass.



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So this pane of glass has the type in videos so x and y out of type integers.



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Now what I want to do I want to create a beer a glass of double.



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So how can we do that.



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So I will create the glass buildable and inside that X and Y both will readable.



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So I will write Double X and I will write to double y.



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Basically I will copy paste all this thing here and instead of integer what I will write I will write



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double.



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So I will replace integer here by double.



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Similarly I will replace integer by double here and so on.



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So I will replace integer by double and I will replace integer by double.



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So just copy paste this code and change in digit to double because now X and Y are of type double.



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So now we have a big class of integer and appear a class of double.



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Now later I want to create one more class B in a class of character.



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So again what I will lose so Class B are character and again so what we have to do we will copy paste



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this entire class.



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We will copy paste this entire class and it will be straight here.



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Copy and paste it here.



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The only change that we have to do is basically I will replace in Deja by character.



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Everything else will remain the same.



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So what we are doing we are copy pasting the class and we are just changing the data type so you can



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see there is so much repetition of code.



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What is the difference between this class and this class and this class.



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So the only difference is of data type.



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Everything else is same sometimes the data type is in danger.



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Sometimes the type is double and sometimes the data type is character.



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So what we can do so we can avoid this.



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Copy pasting thing we can use templates



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we can use templates.



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So how we can use templates.



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So what we will do so here what we are writing in Deja X so what I will write.



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I will write the x.



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Similarly I will write Tevi so how we will read this line.



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So the meaning of this line is X is a variable of type.



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The Y is a variable of type.



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So just like we used write in pediatrics so X is a variable of type in digit.



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So similarly X is a variable of type Integer sorry exit a variable of type B and similarly Y is a variable



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of type B and modesty.



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So t is our temporary Nina type these are temporary integer type.



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Now this the value of t can be in danger.



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The value of t can buildable.



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It can be corrected it can be flawed it can be boolean anything right.



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So the value of t can be anything.



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Now what we do.



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So first let us do this.



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So what we have to do instead of writing this Integer i will write these similarly instead of writing



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this Integer i will write T.



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And similarly I have to replace integer by d every year.



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So what I have to do so we will replace we will replace this integer Bayati everywhere.



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Right.



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So let's do that.



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So this this is not in danger.



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This is T V entertaining T.



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And similarly VI is of type T and Y is of type T right.



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So now we do not have integer WS character anywhere.



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We only have t so the compiler will say hey I don't know.



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Okay.



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So compiler will say you are using T every year but if you will compile this file the compiler will



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give us error that it does not know modesty.



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So what we have to do.



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So I have to write a line template type name.



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So we have to write this line above class.



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So write this line above class.



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So let's do that



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template type m. and D.



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So now the compiler will not give us error because it knows that modesty.



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So these are template.



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So now the compiler will not give us error if we will try to run this file.



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Now how we can create the object of this a class.



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So how to create object to a simple simpleton in Texas be happy right.



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So what is appear to be so pure B.



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So you have this X and Y X and Y and both out of type T.



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So what will happen you will get an added Violet because compiler doesn't know what is the value of



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t.



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So you cannot create objects like this.



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So how we will create object be it.



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So we have to give the value of t.



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So I want you to be integer so I will write parent and B.



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So what will happen to the effect of this line.



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So again you have X and Y and now what will happen.



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So T is going to be replaced by integer.



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So these will be replaced by integer here.



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So you can see so here.



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The value of p is in danger.



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So we are passing integer to be so P will be replaced by integer everywhere in the code.



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So this is T.



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Now this will become integer.



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Similarly DST it will become integer and everywhere in the code.



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So T is going to be replaced by integer.



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So similarly this will become integer and this will become a teacher.



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And this will become integer.



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So this is this index for creating the objects now and this will be the condition X and Y both are now



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integers.



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Now I want X and Y should be double and not integer so what I will lose so when we are creating the



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object I will simply pass double instead of integer.



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So if all right pair double lets it be too.



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So what will happen.



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The value of p is going to be replaced by a double.



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So everywhere in the code.



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So this is going to be replaced by the will this be replaced by the will this be replaced by level replaced



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by double replaced by double and replaced mutable.



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So now what will happen.



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So you are x and y both are now double double X double y so you can see with the help of template with



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the help of template you do not need to copy paste the class you just need to pass that data type if



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possible then you will have x and y both double if you can also pass character you can pass anything



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so t can be anything you can pass character B three so it will happen X and Y are now characters.



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So the logic is very simple.



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The value that you are passing the value that we are passing.



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So T is going to be replaced by that value everywhere in the world.



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So let's write the code and let's check so let's write the code be it.



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Now these should be replaced by integer.



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So I am passing integer B1 and now it does give the value of x and y.



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So we'll call the function.



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So even dot syntax let's say the value is 1.



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Similarly even dot sent away the value is 2.



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And now let us also print the value so see out we will not get X and we will also print the value of



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life.



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So we cannot get away



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and now let's create a bit of a double.



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So I am creating a bit of a double letter the name is B2 so B2 dot surtax.



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Let's say one point seventy.



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Similarly we do that certainly let's say the value is to point to 1 and again it will also bring devalue.



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So you don't get X



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beauty art getaway.



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So what should be our output.



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So it's very simple.



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So you're creating a pair of integers so this is P1 and inside P1 both X and Y are of type integers



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then you're calling the function statics so set takes the value of these integer.



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So you are a passing integer 1 and 2.



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Right.



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So the value of x is when the valley of y is to the value of Y is true.



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And then you're calling the Gattex function.



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So get x.



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This is in danger.



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And similarly this is integer so it will return the value of x and then the value of y.



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So at this line my output should be 1.



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Then we have space.



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So 1 space 2.



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And similarly for this P2 what will happen.



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We have discussed already.



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So it will be double X and double y and everywhere in the code.



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So this deal is going to be replaced by double again.



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This tree is replaced by the will this be replaced by double.



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And also this tree is replaced by level.



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So this is double expendable right.



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So the logic is very simple.



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He is going to be replaced by double everywhere inside the code.



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And for this these replaced by integer everywhere.



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You have used the.



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It will be replaced by integer inside the code.



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Then you are calling the next function and get way function.



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So the value of X was one point seventy and the value of why was to point to one.



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So again your output should be one point seventy three then a space then two point two one.



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So let's see where that our logic is correct or not



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let's add in this file



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so you can see the output.



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I have one end to the value of x and y.



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And again I have the value of x and y one point seventy three and two point two one.



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So that's how it is working.



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Now similarly what you can do you can create you can also create pair of characters.



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So what you have to do be it off you will positively type your type character and be three.



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So in this case what will happen to be three so be three as X and Y.



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And this time the D replaced by characters.



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So this is character X and character y.



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And similarly you can set the value of x you can set the value of a you can call get X function and



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get way function and you can print the values of x and y.



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Now what I want.



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So I have two variables right.



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I have X and I m y.



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Now I want my X should be in danger and my Y should be double.



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So currently what do we have so I am writing if I will write B it often digits then both X and Y will



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become integer if I will pass if I will create objects like this pair of double notes.



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This is P1 and this is P2.



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So if I will pass double then both X and Y will become double.



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But what do I want.



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I want my X should be integer and my Y should be double.



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So how we can do that.



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So again it's very simple.



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So what we will do.



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So here we are using only one embedded in our day.



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What we will do we will use one model type.



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So I will write template X and sorry D X and v y so X is of type D Y is of type V and then will create



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object so will pass the value of the envy.



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So I will write like this year end and double



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B3.



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So what will happen this V.



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So this is going to be replaced by integer and V is going to be replaced by W.



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So let me write the code so that you will be able to understand to properly write



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instead of the X. We will use one more time Brady type little name is V so compiler doesn't know what



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is V so what do you do you will add this here.



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So type name is we know okay.



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So we have to type names the envy we are using to compute D and V so X is of type B VI is of type v



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perfect.



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So what do we have here.



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Yes X is of type T I will return t now VI is of type V and similarly for get Y Y is of type V so what



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I'm doing here.



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So X is of type T VI is of type V so x type T.



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And similarly when are calling get text function we are turning x of type T.



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So similarly VI is of type V and here the return type is v simple and also we have updated.



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So compiler will say Ah I don't know what s v.



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So I have added here type name V so now when we create the object.



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So I have to create objects like this why because I have to pass the value of B as well as the value



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of B.



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So first the value of t should be given.



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So the value of t is integer then you have to give the value of V.



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So this is V.



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So it is just like function.



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So in function function takes some arguments and when you want to call this function you have to pass



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the arguments and then the arguments will be passed in order right.



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So again we have two arguments here.



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The end V.



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So we are passing the value of first argument which is integer and the value of second argument is double.



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So let's do that.



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So this is this will not work because you have to pass to a lose.



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So combined out everything so you will write like this.



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Beer.



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What is the first value the value of x is in danger and the value of V is double.



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Let's see the name is B1.



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So what will happen now so B1 have two values X and Y.



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Now y x is of type in digit axis of type Integer and Y is of type double



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now similarly where do we look.



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We will call these tactics functions that way function and get taxing get way function.



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So let's do that so after creating the object so let's call the functions it takes and set way so be



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rendered set x so x is in D a right.



241

00:15:52,990 --> 00:15:59,270

So for example I am passing one point seventy and let's call do I.



242

00:15:59,490 --> 00:16:07,050

So we went out said wait and let's say I am passing one point seventy.



243

00:16:07,120 --> 00:16:11,580

Let us call the function get X and get way to devalue to get X



244

00:16:14,500 --> 00:16:15,940

and be rendered get to a



245

00:16:19,150 --> 00:16:22,830

So what should be on output so be when right.



246

00:16:22,840 --> 00:16:26,970

So we have between X and Y X was B.



247

00:16:27,010 --> 00:16:29,380

So initially we had the X and we y.



248

00:16:29,440 --> 00:16:30,850

So the value of these integer.



249

00:16:30,880 --> 00:16:34,000

So this is in danger and the value of V is double.



250

00:16:34,150 --> 00:16:35,650

So this is double.



251

00:16:35,650 --> 00:16:41,560

So we have integer X and double y now settings.



252

00:16:41,600 --> 00:16:42,880

So this should be in D right.



253

00:16:42,890 --> 00:16:48,240

But I am passing one point seventy so what will happen this one point seventy has to be type cluster.



254

00:16:48,260 --> 00:16:55,670

So implicit type casting will take place and I will store only 1 because X is of type Integer and Vi



255

00:16:55,670 --> 00:16:56,510

is of type double.



256

00:16:56,510 --> 00:16:57,260

So one point.



257

00:16:57,320 --> 00:17:02,120

So why the value of y you would be one point seventy three because values of type double since x is



258

00:17:02,120 --> 00:17:02,900

of type in danger.



259

00:17:02,930 --> 00:17:09,140

So implicit typecasting will take place and the value of x is 1 and the value of y is one point seventy



260

00:17:10,040 --> 00:17:15,670

and then I am bringing the value of x so one should be my one should be printed here and one point seventy



261

00:17:15,680 --> 00:17:17,030

should be printed here.



262

00:17:17,030 --> 00:17:20,080

So let's see the output should be one and one point seventy



263

00:17:25,550 --> 00:17:31,630

so you can see the value of x is 1 and the value of y is one point seventy.



264

00:17:31,730 --> 00:17:37,940

So implicit typecasting is taking place in case of X because X is of type Integer and you are passing



265

00:17:37,940 --> 00:17:41,660

the value w I think there should be warning here.



266

00:17:41,660 --> 00:17:45,290

Okay so there is no warning but if you're using a good compiler.



267

00:17:45,350 --> 00:17:47,400

So what you can get.



268

00:17:47,480 --> 00:17:52,700

So if you are using a good compiler sometimes you will get a warning that implicit type casting is taking



269

00:17:52,700 --> 00:17:53,690

place.



270

00:17:53,720 --> 00:17:55,620

So now what else can we do.



271

00:17:55,640 --> 00:17:59,980

So now what I want to do so I want to create a triplet.



272

00:18:00,710 --> 00:18:03,470

So I want to create a triplet



273

00:18:06,040 --> 00:18:13,750

and inside this triplet so it is obvious I will have three values let's say x y and z axis of Type D



274

00:18:13,870 --> 00:18:22,580

Y is of type V and Z is of type W and obviously I will have here a template.



275

00:18:22,900 --> 00:18:31,490

So type name type empty called my type name type name V and type name W.



276

00:18:31,840 --> 00:18:34,840

So if I want to create a template.



277

00:18:34,930 --> 00:18:41,860

So these these are the three values the three variable x y and z so X is of type T values of type V



278

00:18:41,860 --> 00:18:43,330

and Z is of type W.



279

00:18:43,330 --> 00:18:46,530

And here we have defined what our TV and W.



280

00:18:46,660 --> 00:18:50,050

So how do we create the object of this triplet class.



281

00:18:50,050 --> 00:18:54,580

So for creating the object you will write something like this triplet you have to pass three values



282

00:18:54,580 --> 00:18:55,730

the value of B.



283

00:18:55,840 --> 00:19:01,070

So for example D integer let's say vs also integer and later the Blues also integer.



284

00:19:01,390 --> 00:19:07,270

And even so that is how you will create the object of triplet class.



285

00:19:07,420 --> 00:19:09,420

So what will be the effect of this line.



286

00:19:09,490 --> 00:19:15,420

So the effect is very simple X Y and Z all these three will be integer.



287

00:19:15,670 --> 00:19:21,500

Now here also if you want X and Y both should be in danger then instead of passing and comma that what



288

00:19:21,520 --> 00:19:25,210

you can do you can write in combined B1.



289

00:19:25,210 --> 00:19:26,320

So what will be the effect.



290

00:19:26,320 --> 00:19:31,290

So both X and Y both X and Y will be integer.



291

00:19:31,360 --> 00:19:32,020

In this case.



292

00:19:32,620 --> 00:19:36,930

So this is the problem statement that you want to create a tablet.



293

00:19:37,210 --> 00:19:41,300

So the problem statement is create a template with three values X Y and Z.



294

00:19:41,470 --> 00:19:44,760

And these are the B dare type TV and blue.



295

00:19:44,980 --> 00:19:46,690

But the problem is a little bit different.



296

00:19:46,690 --> 00:19:49,240

You cannot create this class.



297

00:19:49,240 --> 00:19:51,350

You have to use peer class.



298

00:19:51,490 --> 00:19:55,150

You have to use spin class to write this triplet class.



299

00:19:55,150 --> 00:19:59,440

So what I want to say here is I do not want to create a new class.



300

00:19:59,830 --> 00:20:05,600

I want to use Peri class to have three values I am a British myself.



301

00:20:05,830 --> 00:20:08,110

I do not want to create this triplet class.



302

00:20:08,920 --> 00:20:14,570

I want to use a class in such a way that this bitter class can act as a prepared class.



303

00:20:14,620 --> 00:20:21,070

So I want this of class to act as if it is a prepared class.



304

00:20:21,070 --> 00:20:24,520

So let's see how we can do that.



305

00:20:24,520 --> 00:20:31,580

So what will happen if you will write fear and mind and B.



306

00:20:31,990 --> 00:20:33,520

So what will happen.



307

00:20:33,520 --> 00:20:38,210

So I have two values x and y.



308

00:20:38,380 --> 00:20:45,250

This is X and this is why so X is of type Integer so this is in digit and Y is of type Integer.



309

00:20:45,280 --> 00:20:48,380

Now what will happen if I write like this bit.



310

00:20:48,460 --> 00:20:55,430

So this was your t and this was your V now what will happen if I write like this.



311

00:20:57,180 --> 00:21:05,210

Bit of deja combined Deja coma and Deja B.



312

00:21:05,430 --> 00:21:06,510

So what will happen.



313

00:21:06,510 --> 00:21:09,660

So we will take the help of this simple example.



314

00:21:09,660 --> 00:21:13,980

So the first value is deep and the second value is we.



315

00:21:14,010 --> 00:21:16,290

So this is the first value.



316

00:21:16,600 --> 00:21:20,590

So this is deep and this is the second value.



317

00:21:20,590 --> 00:21:29,650

So this is the So let's draw the diagram so this big B has two values X and Y.



318

00:21:30,570 --> 00:21:33,310

So this is X and this is why what is why.



319

00:21:33,330 --> 00:21:34,650

Why is it simply in danger.



320

00:21:34,740 --> 00:21:36,480

So why is it simply integer.



321

00:21:36,600 --> 00:21:37,520

What is x.



322

00:21:38,280 --> 00:21:46,980

So X is of type B and D appear so again it is appeared and since it does appear it will have two values



323

00:21:47,190 --> 00:21:49,620

X and Y.



324

00:21:49,650 --> 00:21:52,040

Now what is the value of this X.



325

00:21:52,050 --> 00:21:53,480

So this is in Egypt.



326

00:21:53,670 --> 00:21:57,770

This is integer and what is the value of y.



327

00:21:57,900 --> 00:22:01,560

So why is also integer.



328

00:22:01,560 --> 00:22:09,030

So the effect of this line is basically your peer class will look no object will look something like



329

00:22:09,030 --> 00:22:09,950

this.



330

00:22:09,990 --> 00:22:13,010

So yes what you can do so what is T.



331

00:22:13,020 --> 00:22:15,810

These are temporary data type and you can replace T.



332

00:22:15,840 --> 00:22:18,640

Yes you can replace T with objects like this.



333

00:22:18,660 --> 00:22:21,180

So this is nothing it is just idea type right.



334

00:22:23,630 --> 00:22:27,910

So you can replace T with something like this user defined your type.



335

00:22:27,950 --> 00:22:29,690

So this is user defined their type.



336

00:22:29,690 --> 00:22:32,820

So you can replace T with the user defined your type also.



337

00:22:32,900 --> 00:22:34,760

Now my question is what I want to do.



338

00:22:35,630 --> 00:22:37,090

So now we have three values right.



339

00:22:37,100 --> 00:22:38,030

So this is the first one.



340

00:22:38,060 --> 00:22:42,900

This is the second value and this is the third value so I am able to store three values.



341

00:22:43,160 --> 00:22:46,250

Now what I want to do I want to write 10 here.



342

00:22:46,250 --> 00:22:47,320

I want to write 10 here.



343

00:22:47,330 --> 00:22:50,840

I want to write 20 here and I want to write party here.



344

00:22:50,840 --> 00:22:52,660

So how can we do that.



345

00:22:52,700 --> 00:22:55,880

So the object the name of the object is B.



346

00:22:56,250 --> 00:23:01,790

So putting party here is very simple what I will do so I will write like this.



347

00:23:01,840 --> 00:23:07,130

B DOT said we beat out Saturday and I will pass the value today.



348

00:23:07,600 --> 00:23:09,910

So today will be placed here.



349

00:23:09,940 --> 00:23:14,770

Now the question is how to put pen here and how to put 20 here.



350

00:23:14,770 --> 00:23:21,640

So what I will do B Dot said X so this is X right.



351

00:23:21,640 --> 00:23:26,020

So I am calling the function settings now set X function what it takes as input.



352

00:23:26,020 --> 00:23:29,990

So if you can see where is set x rays yes.



353

00:23:30,160 --> 00:23:32,110

So this is a static function.



354

00:23:32,110 --> 00:23:34,700

It takes input D and what is P.



355

00:23:34,840 --> 00:23:41,650

These appear these appear so you cannot give values Ten Commandments No this is wrong.



356

00:23:41,650 --> 00:23:45,620

Why this is wrong because now do the type is.



357

00:23:46,210 --> 00:23:47,970

So you have to pass a appear.



358

00:23:48,040 --> 00:23:49,620

You have to pass up period.



359

00:23:49,630 --> 00:23:51,800

So what I will do I will create one more bit.



360

00:23:52,000 --> 00:23:55,070

So let's create one more beer.



361

00:23:55,720 --> 00:24:00,030

So beer and combined went into combined.



362

00:24:00,060 --> 00:24:05,510

Because I have to put pen into India and let's say the name is before.



363

00:24:05,560 --> 00:24:14,250

Now before that surtax has been and before that Saturday is 20.



364

00:24:14,260 --> 00:24:15,310

So what is before.



365

00:24:15,330 --> 00:24:20,470

So P four has two values X and Y X and Y.



366

00:24:20,910 --> 00:24:25,820

X is of type in Deja VI is of type Integer we are calling the functions are text to the value of 10.



367

00:24:25,830 --> 00:24:29,700

So then the liberals today are calling the value you are calling the function set way and they will



368

00:24:29,690 --> 00:24:34,860

use 20 so twenty will replaced here and now let's rewrite dysfunction.



369

00:24:34,860 --> 00:24:41,110

So be DOT said X so this is X and what it takes.



370

00:24:41,200 --> 00:24:46,300

So it takes a bit as input and we will pass this bill before.



371

00:24:46,750 --> 00:24:50,320

So I will pass before here.



372

00:24:50,320 --> 00:24:56,500

So I am passing before here and what is before and so before is this simple P an X and Y.



373

00:24:56,560 --> 00:24:57,220

So what will happen.



374

00:24:57,220 --> 00:24:59,860

These two values 10 and 20 will get copied.



375

00:24:59,980 --> 00:25:03,430

So 10 will be placed here and twenty will be placed here.



376

00:25:03,670 --> 00:25:08,010

So that's how we will be able to put 10 and 20 here.



377

00:25:08,060 --> 00:25:13,800

Now if you want to print the value so I want to print the value.



378

00:25:13,840 --> 00:25:19,490

So in order to print the value so be dot let's say you want to print 30.



379

00:25:19,500 --> 00:25:20,440

So it is very simple.



380

00:25:20,440 --> 00:25:25,430

You will simply call the function get Y and Gateway function will return.



381

00:25:25,470 --> 00:25:29,000

We saw Gateway function earlier than we and we is in danger.



382

00:25:29,030 --> 00:25:31,000

So this is v v as in digit.



383

00:25:31,030 --> 00:25:34,100

So the output will be then sorry output and retard.



384

00:25:34,180 --> 00:25:37,900

Now I want to print 10 and 20 also.



385

00:25:37,900 --> 00:25:43,030

So if I will call the function and get X if I will call the function get x.



386

00:25:43,050 --> 00:25:49,650

So this is good check function it will return to and modesty so D is a bit off and Deja common.



387

00:25:49,980 --> 00:25:55,030

So this thing is going to return me a bit.



388

00:25:55,210 --> 00:25:59,930

So this beer will be returned to me and I want to print the value of x.



389

00:25:59,970 --> 00:26:06,240

So what I will do I will write get X so the output will return.



390

00:26:06,420 --> 00:26:15,680

And similarly if I want to print divide I lose a b dart get X so get X it will return me appeared so



391

00:26:15,680 --> 00:26:21,500

it is going to return a bit and I want to end of that pier I want to access the value of y so I will



392

00:26:21,500 --> 00:26:23,470

call get Y.



393

00:26:24,080 --> 00:26:25,790

So the output will be n here.



394

00:26:26,720 --> 00:26:29,480

Okay so that's how everything is working.



395

00:26:29,480 --> 00:26:33,290

So now let's command out everything and let's write the code for this one



396

00:26:38,170 --> 00:26:39,760

so let's come and don't have anything



397

00:26:44,950 --> 00:26:48,490

and let us it is the screen also we will write the code from fresh



398

00:26:53,320 --> 00:26:53,640

okay.



399

00:26:53,650 --> 00:26:54,810

So I want to use.



400

00:26:54,830 --> 00:27:01,300

So the problem statement was you want to use PID so that it can behave as a template by triplet behaving



401

00:27:01,300 --> 00:27:04,330

means you guys you will be able to store three values.



402

00:27:04,330 --> 00:27:07,540

So with the help of a glass you against all three values like this.



403

00:27:07,540 --> 00:27:07,980

So.



404

00:27:08,050 --> 00:27:08,420

Beer.



405

00:27:08,420 --> 00:27:09,410

Beer and.



406

00:27:10,460 --> 00:27:12,580

And so this is the value of the.



407

00:27:12,610 --> 00:27:14,690

And this is the value of me.



408

00:27:14,830 --> 00:27:20,710

Let's say the name of the object this be and let us set the value of y first.



409

00:27:20,830 --> 00:27:25,080

So certainly the value was tardy as decided.



410

00:27:27,640 --> 00:27:31,390

And now it will do so we have to create a beer first.



411

00:27:31,420 --> 00:27:33,670

So let's give it one more beer.



412

00:27:33,670 --> 00:27:51,110

So beer in Deja in Deja let's call it temp and temp dart sceptics the value is 10 so temp.



413

00:27:51,540 --> 00:27:56,800

Not certainly the value is 20.



414

00:27:56,900 --> 00:27:58,340

And what do we do now.



415

00:27:58,460 --> 00:28:09,290

So be not stocks this set X function it will take as input and I am passing temp so now my beard is



416

00:28:09,290 --> 00:28:09,890

ready.



417

00:28:09,890 --> 00:28:12,530

So what I have to do I have to print the values now.



418

00:28:12,950 --> 00:28:17,670

So let's print the values so let's see out



419

00:28:20,410 --> 00:28:24,330

be dart get x.



420

00:28:24,610 --> 00:28:30,070

So it will return me up here and of that bet I want to access the x value.



421

00:28:30,070 --> 00:28:32,610

So print x God get x.



422

00:28:33,010 --> 00:28:33,700

Similarly



423

00:28:37,180 --> 00:28:40,640

again call B dot get x.



424

00:28:40,660 --> 00:28:45,100

So it is going to return me a bit and of that bit I want to exist.



425

00:28:45,100 --> 00:28:52,830

The y values so get Y and now and again do so we can print 30.



426

00:28:52,830 --> 00:28:54,930

So for printing that 30 what will I do.



427

00:28:54,930 --> 00:28:56,460

So be dot get Y



428

00:29:01,410 --> 00:29:07,740

Okay so let's first run of a code and let us first run this file and then we will brighten what is happening



429

00:29:11,540 --> 00:29:16,610

so you can see the output is 10 20 and 30.



430

00:29:16,640 --> 00:29:18,850

So this is all that we have wanted.



431

00:29:18,860 --> 00:29:21,910

So this this is the correct output 10 20 and 30.



432

00:29:21,980 --> 00:29:27,540

And now let's see how everything is working let's write a novel code.



433

00:29:27,970 --> 00:29:29,430

So yes.



434

00:29:29,500 --> 00:29:30,750

So this is B.



435

00:29:31,000 --> 00:29:34,790

Okay so create an object.



436

00:29:34,790 --> 00:29:37,240

So this B has two things X and Y.



437

00:29:37,760 --> 00:29:41,760

So this is your X and this is your way.



438

00:29:41,930 --> 00:29:46,200

Okay so X is this appeared.



439

00:29:46,400 --> 00:29:51,910

So if you remember we have d x and v vi so VI is in danger.



440

00:29:51,920 --> 00:29:58,820

So this is simply deja and X is B and D again appeared so again appear.



441

00:29:58,820 --> 00:30:03,960

That means you will have again X and Y.



442

00:30:04,220 --> 00:30:08,120

So this is your x and this is your right.



443

00:30:08,440 --> 00:30:10,850

And both out of indigent integer and Deja.



444

00:30:10,900 --> 00:30:15,190

So this is also in Egypt and this is also integer fine.



445

00:30:15,490 --> 00:30:17,470

So be that set the value function.



446

00:30:17,470 --> 00:30:20,360

So this is set to y you are passing today.



447

00:30:20,380 --> 00:30:24,230

So what will happen 10 will be present here.



448

00:30:24,250 --> 00:30:24,900

Simple.



449

00:30:25,240 --> 00:30:33,360

You are creating at the appeared temp so let's create and then better temp so this temp will have x



450

00:30:33,360 --> 00:30:33,690

and y.



451

00:30:33,720 --> 00:30:39,060

So this is temp and this is B.



452

00:30:39,190 --> 00:30:41,710

So this is temp right in deja A.J..



453

00:30:41,740 --> 00:30:46,870

OK so this is in danger and this is all turned Deja now.



454

00:30:46,940 --> 00:30:53,650

Settings you are passing ten so ten was replaced here said Dwight you are passing 20 so now 20 is presented



455

00:30:54,610 --> 00:31:00,680

so you are calling B dot site X. So this is B This was b so B Dart said x.



456

00:31:00,760 --> 00:31:08,040

So that means this thing and this thing requires a b it as input it requires Hep B it is input and you



457

00:31:08,040 --> 00:31:16,020

are passing temp so temp is up here so you are passing this be a hard copy assignment operator will



458

00:31:16,020 --> 00:31:16,680

be called here



459

00:31:19,640 --> 00:31:26,180

okay so internally copy assignment operator will be called and these two values 10 and 20 will be copied.



460

00:31:26,330 --> 00:31:29,840

So 10 will be copied here and 20 will be copied here.



461

00:31:29,840 --> 00:31:34,940

So internally we are calling the copy assignment operator to copy these two values 10 and 20.



462

00:31:34,970 --> 00:31:42,650

So now 10 is presented and 20 is present here then you are calling B dot get X so b don't get X it will



463

00:31:42,650 --> 00:31:43,700

return you appear.



464

00:31:43,820 --> 00:31:50,510

So this part is going to return you appear and of that page you want to X is the value x so get X you



465

00:31:50,510 --> 00:31:53,170

will call you and get in.



466

00:31:53,330 --> 00:31:56,930

So that's how N is getting printed here then we have space.



467

00:31:57,020 --> 00:31:58,940

So again be dot and get x.



468

00:31:59,000 --> 00:32:02,890

So this is X again you will get up here.



469

00:32:03,120 --> 00:32:04,880

So again you will get up here.



470

00:32:04,910 --> 00:32:10,590

So this is a bit and then you are calling get Y functions so this is 20.



471

00:32:10,590 --> 00:32:14,280

So that's how it guarantees getting printed here and this is very simple.



472

00:32:14,490 --> 00:32:15,320

Bedard get.



473

00:32:15,360 --> 00:32:17,240

So be dot get Y.



474

00:32:17,310 --> 00:32:19,260

So today will be printed here.



475

00:32:19,350 --> 00:32:24,040

So that's how your output becomes so 10 then 20 and then 30.



476

00:32:24,060 --> 00:32:27,240

So then then space 2010 spaced happy.



477

00:32:27,360 --> 00:32:30,580

So that's how everything is working.



478

00:32:30,630 --> 00:32:42,360

So now for example if you want to create a triplet such that the first value is in digit the second



479

00:32:42,360 --> 00:32:50,620

value let's say is double and that total value is related to so you want to create a place like this.



480

00:32:50,620 --> 00:32:52,210

So what will be this index



481

00:32:55,670 --> 00:33:05,660

now if you want you can pass this bit as b or you can pass this bit as we so let's hear.



482

00:33:05,780 --> 00:33:09,050

So the first rule losing digits I am passing and beach ahead.



483

00:33:09,180 --> 00:33:11,630

Now the second value I have to pass.



484

00:33:11,900 --> 00:33:14,800

So I will look club these two for example I am loving these two.



485

00:33:14,810 --> 00:33:16,640

So this too will become a beer.



486

00:33:16,650 --> 00:33:23,220

So beer what is the first value double and what is the second value character.



487

00:33:23,600 --> 00:33:23,960

Right.



488

00:33:23,960 --> 00:33:25,040

Simple.



489

00:33:25,070 --> 00:33:26,830

And this is B.



490

00:33:26,960 --> 00:33:36,390

So what will happen where will the effect of this line again you will get two values X and Y X and Y.



491

00:33:36,550 --> 00:33:39,510

X is integer so x is in it.



492

00:33:39,520 --> 00:33:41,580

So right now is a peer.



493

00:33:41,650 --> 00:33:43,840

So this is appeared again.



494

00:33:43,870 --> 00:33:48,340

I will have two parts x and y two the first is double.



495

00:33:48,490 --> 00:33:52,300

So here you have double and the second is character.



496

00:33:52,390 --> 00:33:54,040

So here you have Gary.



497

00:33:54,190 --> 00:33:56,620

So this is how everything is working.



498

00:33:56,680 --> 00:33:57,460

Now one more thing.



499

00:33:57,490 --> 00:34:02,000

So this is a nesting right so you can do many levels of nesting.



500

00:34:02,020 --> 00:34:02,290

Okay.



501

00:34:02,300 --> 00:34:05,880

So so you can do as many levels of nesting as you want.



502

00:34:05,890 --> 00:34:08,180

So this is one level of nesting right.



503

00:34:08,200 --> 00:34:10,660

So this is first level of nesting.



504

00:34:10,660 --> 00:34:16,560

So speaking from my own experience you will never acquire listing of second level or more.



505

00:34:17,920 --> 00:34:20,160

So the first level nesting is more than enough.



506

00:34:20,170 --> 00:34:22,050

So this is more than enough.



507

00:34:22,180 --> 00:34:23,490

This is more than enough.



508

00:34:23,500 --> 00:34:26,080

So first level of nesting is good enough.



509

00:34:26,290 --> 00:34:32,410

You will never encountered a problem in which you need to use second level of nesting or mode.



510

00:34:33,370 --> 00:34:36,140

So this is all in templates.



511

00:34:36,220 --> 00:34:39,040

So if you have any doubt in templates you can ask me.



512

00:34:39,070 --> 00:34:41,060

OK so this is it from this video.



513

00:34:41,230 --> 00:34:41,650

Thank you.