1 00:00:02,390 --> 00:00:03,080 Hello everyone. 2 00:00:03,080 --> 00:00:09,350 So in this video we will learn about operator overloading operator overloading means that we can extend 3 00:00:09,380 --> 00:00:15,860 the functionality of the existing operators such that it will work for our user defined classes also. 4 00:00:15,950 --> 00:00:19,150 So in the last session we created this friction class. 5 00:00:19,160 --> 00:00:21,080 Now what I want is. 6 00:00:21,080 --> 00:00:23,000 So our aim is very simple. 7 00:00:23,000 --> 00:00:28,150 What we want is EF 3 is EF 1 plus EF 2. 8 00:00:28,160 --> 00:00:29,690 I want to do something like this. 9 00:00:30,200 --> 00:00:33,650 So currently if we will ride this treatment then this treatment is wrong. 10 00:00:33,650 --> 00:00:34,220 Why. 11 00:00:34,250 --> 00:00:41,750 Because the plus operator is not defined for our affection class but if I will write in C is A plus 12 00:00:41,750 --> 00:00:42,560 B. 13 00:00:42,980 --> 00:00:44,320 Then this line is right. 14 00:00:44,380 --> 00:00:44,940 Why. 15 00:00:44,990 --> 00:00:50,390 Because this plus operator is defined internally for doubles and for integers. 16 00:00:50,410 --> 00:00:50,650 Okay. 17 00:00:50,690 --> 00:00:51,800 So this line is wrong. 18 00:00:51,800 --> 00:00:52,350 Why. 19 00:00:52,370 --> 00:00:55,830 Because the plus operator is not defined for our fictional class. 20 00:00:56,100 --> 00:00:57,420 Salary is very simple. 21 00:00:57,440 --> 00:00:59,460 We wanted to make this line book. 22 00:00:59,630 --> 00:01:01,850 We wanted to make this treatment work. 23 00:01:02,060 --> 00:01:02,560 Okay. 24 00:01:02,570 --> 00:01:06,830 So what we want is we want to extend the functionality of this plus operator. 25 00:01:07,010 --> 00:01:12,860 We want to extend the functionality of this plus operator so that this press operator can work for our 26 00:01:12,860 --> 00:01:14,400 function class. 27 00:01:14,420 --> 00:01:17,630 Now this process is called operator overloading. 28 00:01:17,660 --> 00:01:18,260 Okay. 29 00:01:18,260 --> 00:01:21,230 So now we have to learn how to overload operator. 30 00:01:21,350 --> 00:01:24,200 So let us see this added function. 31 00:01:24,320 --> 00:01:28,960 So how we would call this added function we will call it with the help of an object. 32 00:01:29,060 --> 00:01:33,420 So if one dot Ed and then the argument will pass affliction F2. 33 00:01:33,440 --> 00:01:36,410 So what it will do it will add two numbers. 34 00:01:36,430 --> 00:01:41,170 One it will add two fictions f1 plus F2 and it will store that is our then F1. 35 00:01:41,750 --> 00:01:42,220 Okay. 36 00:01:42,290 --> 00:01:44,090 So this is what this code will do. 37 00:01:44,900 --> 00:01:48,740 Now let us first change the functionality of this add function. 38 00:01:48,740 --> 00:01:50,210 So what this area functions will do. 39 00:01:50,270 --> 00:01:55,840 It will add two fractions f1 plus F2 and it will stored the desert in New Fiction. 40 00:01:55,910 --> 00:01:59,760 It will create the new function and it will return new friction. 41 00:01:59,780 --> 00:02:09,800 So how we will call this function friction F3 we will call this add function f dot add and it will big 42 00:02:09,820 --> 00:02:11,140 F to his argument. 43 00:02:11,160 --> 00:02:14,000 Okay so this is our aim currently. 44 00:02:14,030 --> 00:02:18,400 Let us change let's first change the functionality of the add function. 45 00:02:18,410 --> 00:02:24,080 Okay so what desired function will do it will create a new function F3 and it will return the new friction 46 00:02:24,200 --> 00:02:26,930 F1 and F2 both will remain unchanged. 47 00:02:27,460 --> 00:02:27,950 Okay. 48 00:02:28,040 --> 00:02:29,210 So how can we do this. 49 00:02:29,540 --> 00:02:32,310 So let's see. 50 00:02:32,390 --> 00:02:37,610 So first of all let us copy this function okay. 51 00:02:37,630 --> 00:02:40,070 So let's make change in this function only. 52 00:02:40,070 --> 00:02:41,810 So what will the return type. 53 00:02:41,810 --> 00:02:47,440 Now the return type will be a fraction because we will done a new fraction okay. 54 00:02:47,480 --> 00:02:53,340 So currently what we are doing here is I am changing the numerator and denominator affection F1. 55 00:02:53,780 --> 00:02:57,890 So let's come on down this called. 56 00:02:57,920 --> 00:03:06,010 So what we have to do we have to create a new friction and then we will return that friction so friction 57 00:03:06,160 --> 00:03:08,640 f new let's name it f new. 58 00:03:08,710 --> 00:03:09,970 So what will be the numerator. 59 00:03:10,450 --> 00:03:14,360 So numerator will be and new him and the denominator will be LC. 60 00:03:15,130 --> 00:03:15,700 Okay. 61 00:03:15,760 --> 00:03:22,510 So what will happen at this line Batam at base constructively be called and now object will be created. 62 00:03:22,510 --> 00:03:23,020 Okay. 63 00:03:23,170 --> 00:03:32,040 So Batman tries to construct that called and now our object is ready okay. 64 00:03:32,310 --> 00:03:35,910 So after doing this we have to call simplify function. 65 00:03:35,910 --> 00:03:40,830 So currently if so currently the simplify means this it'll simplify. 66 00:03:40,830 --> 00:03:46,640 So this simplify function is being called on F1 so we have to change it. 67 00:03:46,640 --> 00:03:50,240 What we will do we will write f new DOT. 68 00:03:50,270 --> 00:03:50,930 Simplify. 69 00:03:51,390 --> 00:03:53,340 Okay so the new objective new. 70 00:03:53,390 --> 00:03:59,780 So the new function if new will get simplified and then we will have done this new friction so redone 71 00:03:59,780 --> 00:04:00,970 done. 72 00:04:01,430 --> 00:04:02,530 F new. 73 00:04:02,540 --> 00:04:03,390 Okay. 74 00:04:03,410 --> 00:04:05,960 So this is all that we have to do. 75 00:04:06,020 --> 00:04:06,250 Okay. 76 00:04:06,260 --> 00:04:08,020 So let's test our code. 77 00:04:08,060 --> 00:04:12,530 So currently we have these two factions friction F1 and friction F2. 78 00:04:13,550 --> 00:04:16,160 Okay so let's make a friction F3 79 00:04:20,440 --> 00:04:24,790 so this friction F3 is the addition of F1 and F2. 80 00:04:25,540 --> 00:04:31,980 So F1 not add and we will give F too okay. 81 00:04:32,200 --> 00:04:36,850 So now let us Sprint F1 F2 150 so F1 dot print 82 00:04:39,970 --> 00:04:41,000 after dark print 83 00:04:43,830 --> 00:04:50,230 and similarly F three dart print. 84 00:04:50,290 --> 00:04:51,680 Now let's turn our program. 85 00:04:51,700 --> 00:04:53,760 So first we will compile this file. 86 00:04:54,250 --> 00:04:57,250 And now we will run this file okay. 87 00:04:57,260 --> 00:04:58,630 So there is something wrong here. 88 00:05:07,110 --> 00:05:08,980 And it was not declared in the scope. 89 00:05:08,980 --> 00:05:09,270 Okay 90 00:05:27,870 --> 00:05:28,070 okay. 91 00:05:28,080 --> 00:05:29,360 So now let us on this file 92 00:05:32,740 --> 00:05:33,850 and now we will run this way 93 00:05:39,150 --> 00:05:42,850 so we can see here the value of have fun and F2 remains unchanged. 94 00:05:42,870 --> 00:05:47,190 And this is how it is and F3 which is the addition of friction F1 and F2. 95 00:05:48,210 --> 00:05:51,980 Okay so now what I want. 96 00:05:52,110 --> 00:06:00,420 So our aim is very simple what I want to do is I will create a new function function f word. 97 00:06:01,360 --> 00:06:07,510 So I want to create a new friction friction effort and I will write F1 plus F2. 98 00:06:07,510 --> 00:06:10,530 And the result will be theme is friction F3. 99 00:06:10,670 --> 00:06:13,280 Okay so I want the same functionality. 100 00:06:13,330 --> 00:06:18,220 So this plus operator will do exactly the same work which the add function needs to do. 101 00:06:19,030 --> 00:06:19,540 Okay. 102 00:06:19,630 --> 00:06:25,720 So the functionality will be same but I want to use plus operator instead of this add function. 103 00:06:25,780 --> 00:06:28,680 Okay so let's see in code how to do this. 104 00:06:29,050 --> 00:06:29,950 Okay. 105 00:06:34,530 --> 00:06:36,300 So let's copy their function 106 00:06:43,740 --> 00:06:47,550 so what I did is I only just copied their function. 107 00:06:47,550 --> 00:06:49,320 Now how to use operator overloading. 108 00:06:49,320 --> 00:06:51,600 So first we have to write the keyword operator. 109 00:06:53,010 --> 00:06:54,740 So operator is the keyword. 110 00:06:54,840 --> 00:06:58,620 And then you have to write the operator which you want to overload. 111 00:06:58,620 --> 00:07:00,510 So we want to overload plus operator. 112 00:07:00,510 --> 00:07:01,500 So without space. 113 00:07:01,500 --> 00:07:01,860 Right. 114 00:07:01,920 --> 00:07:04,160 Plus okay. 115 00:07:04,400 --> 00:07:05,720 So that's all. 116 00:07:05,750 --> 00:07:07,660 You only have to do this much work. 117 00:07:07,780 --> 00:07:10,090 Everything the functionality will remain the same. 118 00:07:10,100 --> 00:07:14,570 You just change the function name to operate a keyword and then plus. 119 00:07:14,590 --> 00:07:14,860 Okay. 120 00:07:14,870 --> 00:07:21,020 So no need to do anything extra so that it's cleared and the friction function effort 121 00:07:24,560 --> 00:07:27,960 to function F4 will be EF 1 plus 2. 122 00:07:28,010 --> 00:07:30,150 So if one plus EF 2. 123 00:07:30,990 --> 00:07:33,120 Okay now let's turn our file. 124 00:07:33,410 --> 00:07:36,380 So first we will run this one. 125 00:07:36,380 --> 00:07:38,610 And now we will win this fight. 126 00:07:39,320 --> 00:07:39,700 OK. 127 00:07:39,710 --> 00:07:42,260 So we forgot to print before. 128 00:07:43,130 --> 00:07:49,100 So let's print a foot F4 dot print now do it's and this will 129 00:07:52,560 --> 00:07:59,850 so we can see here F4 is also five by four solver code is working so we can see here it is very easy 130 00:07:59,850 --> 00:08:00,750 to overload operator. 131 00:08:00,780 --> 00:08:02,760 Now let's see how it is working. 132 00:08:02,790 --> 00:08:03,320 Okay. 133 00:08:08,630 --> 00:08:09,500 So we'll see this line. 134 00:08:09,500 --> 00:08:22,540 What will happen if when dot Ed EF 2 so this EF 1 will go in this this keyword of the add function and 135 00:08:22,540 --> 00:08:24,670 this EF 2 is posties argument 136 00:08:27,350 --> 00:08:27,920 OK. 137 00:08:28,060 --> 00:08:32,520 Now see this line EF 1 plus EF 2. 138 00:08:32,820 --> 00:08:35,150 Now a brand on the left hand side of the operator. 139 00:08:35,200 --> 00:08:37,610 This will go in this function. 140 00:08:37,610 --> 00:08:45,920 This keyword of the dysfunction and F2 will go in the argument okay. 141 00:08:46,020 --> 00:08:52,350 So the left hand side or brand will go in this and the right hand side argument will go in the argument 142 00:08:52,890 --> 00:09:00,280 and which function it will call it will call the function operator plus operator plus function will 143 00:09:00,280 --> 00:09:01,350 be called. 144 00:09:01,360 --> 00:09:10,120 So this will contain F1 and F2 will be biased s argument to this function operator plus function. 145 00:09:10,220 --> 00:09:14,320 Okay so now let us overlord multiply operator also. 146 00:09:14,340 --> 00:09:22,280 So what I want is I will create a new fraction function EF 3 and this friction EF 3 will be the multiplication 147 00:09:22,280 --> 00:09:24,080 of 2 friction F1 and F2. 148 00:09:24,680 --> 00:09:27,050 So we will overload this much space operator. 149 00:09:27,110 --> 00:09:35,620 So this EF 1 will go in this and EF 2 will be passed is argument similar to this similar to our function. 150 00:09:35,660 --> 00:09:36,100 Okay. 151 00:09:36,230 --> 00:09:41,420 We do not need to parse two arguments we just need to pass one argument because the better one will 152 00:09:41,420 --> 00:09:43,040 go in this. 153 00:09:43,040 --> 00:09:45,650 Okay so let this overlord multiply operator 154 00:09:48,840 --> 00:09:55,440 so this is want to pay operator so what we let it down type it and type will be fraction because we 155 00:09:55,440 --> 00:10:00,540 will create a new friction and then we will return that friction so we don't have really friction then 156 00:10:01,080 --> 00:10:01,740 the keyword. 157 00:10:01,800 --> 00:10:07,130 Operator And then the operator which we want to overload. 158 00:10:07,140 --> 00:10:17,020 So we want to multiply operator so multiply what it will take it will take a function as input function 159 00:10:17,060 --> 00:10:25,780 F2 and then what we will do we will calculate the numerator and denominator so in the numerator which 160 00:10:25,780 --> 00:10:34,990 is f one numerator or we can write this at a numerator multiply the numerator of f one Saudi multiple 161 00:10:34,990 --> 00:10:36,190 numerator of F2. 162 00:10:36,190 --> 00:10:42,930 So after nought numerator similarly it describes with their denominator so denominator is. 163 00:10:43,380 --> 00:10:54,750 Do I mean it drove F1 or we can write this letter denominator multiply by the denominator of F2. 164 00:10:54,800 --> 00:10:59,770 Okay so now let us create new friction which we will have done. 165 00:10:59,850 --> 00:11:07,620 So friction let's name it f new so the numerator will be N and their denominator is d again copy constructor 166 00:11:07,710 --> 00:11:13,140 sorry again parameters construct that will be called here and then we have to call simplify function. 167 00:11:13,140 --> 00:11:13,400 Okay. 168 00:11:13,410 --> 00:11:15,450 So the functionality will remain the same. 169 00:11:15,450 --> 00:11:17,180 We are falling this only. 170 00:11:17,340 --> 00:11:19,890 Okay so the function level doing the same. 171 00:11:19,890 --> 00:11:22,020 Now we have to call simplify function. 172 00:11:22,020 --> 00:11:24,780 We have to call simplify function on the new object. 173 00:11:24,840 --> 00:11:25,730 F new. 174 00:11:25,740 --> 00:11:27,890 So we have to write f new DOT. 175 00:11:27,900 --> 00:11:35,170 Simplify if you will simply write simplify then that means this to simplify simplify function we got 176 00:11:35,180 --> 00:11:42,900 called on F1 but we have to call on f new so after simplifying we will have done f new. 177 00:11:43,190 --> 00:11:45,290 Okay so that's all we have to do. 178 00:11:45,590 --> 00:11:46,430 So what will happen 179 00:11:50,870 --> 00:11:59,890 when we will write fiction F3 is F1 multiply F2. 180 00:11:59,890 --> 00:12:04,290 So the left hand open and the first print will go in this. 181 00:12:04,450 --> 00:12:11,940 So this numerator means F one dart numerator what we can write this at a numerator and this F2 will 182 00:12:11,970 --> 00:12:15,550 go in the argument okay. 183 00:12:15,630 --> 00:12:22,390 So this is how we overload multiply or pretend so this is how we overload multiply Roberta. 184 00:12:22,390 --> 00:12:29,560 Now let us try to overload one more operator which is equal to equal to so I know what we want is I 185 00:12:29,560 --> 00:12:32,290 want to overload this operator equal equal operator. 186 00:12:32,410 --> 00:12:34,470 So what this equal equal operator will do. 187 00:12:34,570 --> 00:12:42,220 I will give two fractions F1 and F2 and if the two factions are equal I will print equal if the two 188 00:12:42,220 --> 00:12:45,420 factions are not equal then I will print not equal. 189 00:12:45,820 --> 00:12:53,440 So in the main function in the main program the syntax will be if friction F1 equals equals friction 190 00:12:53,490 --> 00:13:01,340 F2 then we will see out equal otherwise they are not equal. 191 00:13:01,400 --> 00:13:10,150 So in the S and the else part we will write not equal okay. 192 00:13:10,410 --> 00:13:11,820 So where do the return type. 193 00:13:11,820 --> 00:13:16,610 Okay so first of all this thing will go into this function. 194 00:13:16,620 --> 00:13:20,280 This key word of the function and F F2 will go in the argument 195 00:13:23,560 --> 00:13:27,880 and which function we will call we will call the function with the name operator equal equal. 196 00:13:28,720 --> 00:13:32,850 Okay so let's say in code. 197 00:13:32,890 --> 00:13:39,310 So first of all what will the return type return type will be bool because we will return true or false. 198 00:13:39,310 --> 00:13:45,430 So bool what will the name first of all we have the right operator keyword then the name of the operator 199 00:13:45,520 --> 00:13:46,770 which we want to overload. 200 00:13:46,780 --> 00:13:49,380 So we want to hold equal call operator. 201 00:13:49,810 --> 00:13:57,100 So it will take one function as input function F two because the first function will go in this and 202 00:13:57,100 --> 00:13:59,590 then we have to return either true or false. 203 00:13:59,770 --> 00:14:05,050 So render two functions are equal when the numerator and denominator both Harry Kewell then we can say 204 00:14:05,050 --> 00:14:12,010 the functions are equal Okay so numerator and denominator both will be equal then we will say the two 205 00:14:12,010 --> 00:14:19,690 factions are equal so when numerator of f one consequence numerator of f F2 206 00:14:23,260 --> 00:14:32,140 and denominator has to be equal so denominator of f one equals equals denominator of F. 207 00:14:32,190 --> 00:14:37,510 So afterward denominator OK. 208 00:14:37,750 --> 00:14:43,550 So so this condition will either be true or this condition will either be false. 209 00:14:43,570 --> 00:14:46,450 So accordingly we will return true or false. 210 00:14:46,450 --> 00:14:48,250 Okay so that's all. 211 00:14:48,250 --> 00:14:52,140 Now let's end this way okay. 212 00:14:52,150 --> 00:14:53,320 So there is something wrong 213 00:14:58,940 --> 00:14:59,160 okay. 214 00:14:59,170 --> 00:15:05,630 So there's a spelling mistake. 215 00:15:05,750 --> 00:15:06,930 Now this is right. 216 00:15:06,960 --> 00:15:10,200 Let's compile the file okay. 217 00:15:10,220 --> 00:15:13,240 So now we will test our multiplying operator. 218 00:15:13,290 --> 00:15:13,740 And now what. 219 00:15:13,740 --> 00:15:14,800 Equal equal operator. 220 00:15:14,910 --> 00:15:26,220 Okay so we have to test two things so let's make let's create a friction friction a five which is the 221 00:15:26,220 --> 00:15:31,670 multiplication of F1 friction and F2 friction. 222 00:15:31,740 --> 00:15:32,650 Okay. 223 00:15:32,730 --> 00:15:33,580 And F five. 224 00:15:33,580 --> 00:15:34,140 BROADBENT 225 00:15:37,530 --> 00:15:40,920 And now we have the best outward equal equal or greater. 226 00:15:40,980 --> 00:15:45,070 So if F1 equals equals F2 227 00:15:48,760 --> 00:15:51,670 C out equal 228 00:16:00,870 --> 00:16:01,620 it's not equally 229 00:16:10,220 --> 00:16:10,490 okay. 230 00:16:10,500 --> 00:16:12,300 So let's all let's say now fighting. 231 00:16:17,020 --> 00:16:20,130 So this is our safety and this is I want a full. 232 00:16:20,500 --> 00:16:24,660 And this is our EF 5 so EF 5 is no duplication of a friend of 2. 233 00:16:24,670 --> 00:16:26,410 So I hope Don said is right. 234 00:16:26,470 --> 00:16:28,660 And then and finally off to an article. 235 00:16:28,660 --> 00:16:32,160 So that's why our output is not equal. 236 00:16:32,260 --> 00:16:37,180 So if I write F when equal equal F1 then that would put will be equal. 237 00:16:37,200 --> 00:16:39,630 Okay so let's see. 238 00:16:39,640 --> 00:16:43,390 So this time output is equal because F1 is different. 239 00:16:43,390 --> 00:16:45,310 Both sides seem okay. 240 00:16:45,460 --> 00:16:47,190 So that's how V O Lord our operator. 241 00:16:47,980 --> 00:16:50,030 So our work is not done here. 242 00:16:50,050 --> 00:16:54,220 Our work is not done here yet because we have to do some optimization. 243 00:16:54,310 --> 00:16:54,720 Okay. 244 00:16:54,790 --> 00:16:56,480 So what kind of optimization. 245 00:16:56,500 --> 00:17:02,700 So if you remember this add function this add function is taking F2 by reference and it will took constant 246 00:17:02,700 --> 00:17:03,420 reference. 247 00:17:03,430 --> 00:17:06,220 So first of all biodefense why we need to biodefense. 248 00:17:06,490 --> 00:17:11,910 So to avoid calling copy construct but because we do not need to call copy constructor and write constant. 249 00:17:12,340 --> 00:17:16,450 So we need a constraint to avoid illegal changes in F too. 250 00:17:16,520 --> 00:17:18,580 Okay. 251 00:17:18,830 --> 00:17:20,060 This is our plus operator. 252 00:17:20,080 --> 00:17:20,380 Okay. 253 00:17:20,390 --> 00:17:24,760 So here we have to read and optimization question defense. 254 00:17:24,860 --> 00:17:27,550 Now can we do optimization so this is multiply. 255 00:17:27,590 --> 00:17:29,740 And operator multiply. 256 00:17:29,750 --> 00:17:33,410 So here we should pass by reference. 257 00:17:33,710 --> 00:17:34,060 Okay. 258 00:17:34,080 --> 00:17:41,410 Constant reference because we do not need to call copy constructor here and also we want to avoid illegal 259 00:17:41,420 --> 00:17:42,180 changes. 260 00:17:42,200 --> 00:17:42,480 Okay. 261 00:17:42,500 --> 00:17:44,140 So that's why constant offense. 262 00:17:44,150 --> 00:17:51,810 And similarly we want to avoid calling copy constructor and we want to avoid any legal changes so question 263 00:17:51,840 --> 00:17:53,340 reference. 264 00:17:53,500 --> 00:17:56,910 Okay so no one more thing. 265 00:17:56,980 --> 00:18:00,710 Now we have now we know about constraint functions also. 266 00:18:00,730 --> 00:18:01,000 Okay. 267 00:18:01,000 --> 00:18:06,040 So what that constraint functions constraint functions are does function that will not change the property 268 00:18:06,040 --> 00:18:07,570 of the current object. 269 00:18:07,570 --> 00:18:08,190 Okay. 270 00:18:08,390 --> 00:18:10,570 That will not change the property of the current object. 271 00:18:10,660 --> 00:18:12,790 So let's say this function equal equal. 272 00:18:12,820 --> 00:18:16,020 So will this function change the property of f 1. 273 00:18:16,120 --> 00:18:16,450 Okay. 274 00:18:16,480 --> 00:18:19,010 So no it is not changing the property. 275 00:18:19,120 --> 00:18:21,310 So this function is a constraint function. 276 00:18:21,340 --> 00:18:24,430 So Mark this function is a constraint function. 277 00:18:24,430 --> 00:18:24,960 Okay. 278 00:18:25,120 --> 00:18:27,400 Now let's say this function and multiply function. 279 00:18:27,400 --> 00:18:30,480 So this multiply function changes the property of the current object. 280 00:18:30,550 --> 00:18:34,080 So the current object is F1 no object which is calling the function. 281 00:18:34,660 --> 00:18:36,330 So numerator and denominator. 282 00:18:36,340 --> 00:18:37,780 No it is not changing. 283 00:18:37,780 --> 00:18:39,820 It is creating a new friction. 284 00:18:39,820 --> 00:18:40,050 Okay. 285 00:18:40,060 --> 00:18:44,670 So this function is qualified to be a constraint function. 286 00:18:44,700 --> 00:18:46,620 Now let's see this multiply function. 287 00:18:46,620 --> 00:18:50,980 So this multiplied function is changing the numerator and denominator of the current object. 288 00:18:51,000 --> 00:18:54,240 So this multiply function is not a constant function. 289 00:18:54,240 --> 00:18:57,910 Let's see the plus function the operator plus function. 290 00:18:57,930 --> 00:19:03,870 So this function is creating a new function and it is changing the properties of the new fractions. 291 00:19:03,870 --> 00:19:07,310 It is not changing the properties of the current object. 292 00:19:07,350 --> 00:19:07,880 Okay. 293 00:19:08,010 --> 00:19:09,320 We have commented it out. 294 00:19:09,720 --> 00:19:13,710 It is not changing the properties of the current object since it is not changing the properties of the 295 00:19:13,710 --> 00:19:14,460 current object. 296 00:19:14,460 --> 00:19:21,500 This is also a constant function and similarly this is also not changing the properties. 297 00:19:21,580 --> 00:19:23,530 So this is also a constraint function 298 00:19:32,580 --> 00:19:35,010 so everything is working fine. 299 00:19:35,160 --> 00:19:35,610 Okay. 300 00:19:35,730 --> 00:19:41,700 So in this video we only ordered three operators plus multiply and equally call operator in the next 301 00:19:41,700 --> 00:19:44,430 session we will overload somewhat operators. 302 00:19:44,460 --> 00:19:45,070 Okay. 303 00:19:45,270 --> 00:19:45,690 Thank you.