1 00:00:02,090 --> 00:00:03,680 Hey, guys, what's up? 2 00:00:04,040 --> 00:00:08,180 So today we will learn how to pass any dual function. 3 00:00:08,930 --> 00:00:11,240 Okay, so this is the topic for today's class. 4 00:00:11,630 --> 00:00:14,420 How to pass at is indoor function. 5 00:00:15,570 --> 00:00:16,760 So let's see the goal. 6 00:00:18,060 --> 00:00:21,330 So I even named this filer's biasing idea to functions. 7 00:00:21,990 --> 00:00:27,920 So let us first take how many number of elements are there in entity the scene. 8 00:00:28,020 --> 00:00:32,770 And now let us make NRD offsides. 9 00:00:32,980 --> 00:00:38,220 And now let us take and loses input. 10 00:00:38,430 --> 00:00:38,920 So forward. 11 00:00:38,970 --> 00:00:40,440 And I equals zero. 12 00:00:41,360 --> 00:00:43,620 I illest and n a plus. 13 00:00:43,620 --> 00:00:43,980 Plus. 14 00:00:46,760 --> 00:00:48,660 So in a off I. 15 00:00:52,470 --> 00:00:57,320 OK, so what we do is let us create a brain function that will print. 16 00:00:58,230 --> 00:01:00,420 So I have a brain function. 17 00:01:00,840 --> 00:01:03,890 So what brain function will take it will take a. 18 00:01:04,170 --> 00:01:05,520 Which is Eddie as input. 19 00:01:10,430 --> 00:01:11,460 No, no, that's right. 20 00:01:11,480 --> 00:01:17,250 Brain function here so that you don't die will be wired because brain function will not return anything. 21 00:01:17,280 --> 00:01:19,590 It will just print the content of the edit. 22 00:01:20,820 --> 00:01:25,920 So you have to write and a if you will write into it means an integer. 23 00:01:27,030 --> 00:01:28,350 So you have to write like this. 24 00:01:28,590 --> 00:01:29,820 This means any. 25 00:01:31,380 --> 00:01:33,300 And now you have to just print. 26 00:01:33,750 --> 00:01:36,990 So for printing what I have to do, I will just I did already. 27 00:01:38,010 --> 00:01:42,750 So Ford and I equals zero. 28 00:01:58,360 --> 00:02:03,890 So this isn't normal logic, but that above, which will bring the content of the ERRY, but here I 29 00:02:03,900 --> 00:02:09,250 am using a variable and so I have to take the size of the eddy as well. 30 00:02:10,010 --> 00:02:11,320 So similarly, I will print. 31 00:02:11,410 --> 00:02:14,970 I will pass the size of the eddy as input. 32 00:02:15,550 --> 00:02:15,780 Okay. 33 00:02:15,910 --> 00:02:16,930 So this is important. 34 00:02:17,410 --> 00:02:20,010 We have to also pass the size of the areas in Bertolli. 35 00:02:20,170 --> 00:02:20,650 Function. 36 00:02:25,110 --> 00:02:31,530 So there are five elements and the elements are two, four, five, six and three. 37 00:02:32,670 --> 00:02:34,380 So the values are getting printed. 38 00:02:34,590 --> 00:02:37,880 So this print function is printing the content of the eddy. 39 00:02:40,320 --> 00:02:41,570 Now, let this come into doubt. 40 00:02:42,420 --> 00:02:48,240 So now what we want to do is we want to find the sum of all the elements of the eddy. 41 00:02:49,400 --> 00:02:50,440 OK, so let's do it. 42 00:02:51,490 --> 00:02:56,680 So what this function will return, this function will are done, some of the elements. 43 00:02:56,740 --> 00:02:59,110 So this function will be done and integer value. 44 00:03:00,010 --> 00:03:06,880 So intenser equals, let's say the name of the function is some what it will do. 45 00:03:07,030 --> 00:03:10,400 It will take as input and also the size of the eddy. 46 00:03:10,780 --> 00:03:11,790 Do I date of the 80. 47 00:03:12,220 --> 00:03:17,950 So this is important because if we don't know the value of n how we will do that with the. 48 00:03:18,700 --> 00:03:20,310 So that I don't type of dysfunction is. 49 00:03:20,470 --> 00:03:26,260 And because we have to retain the same name of the functionalism, it will take Eddie. 50 00:03:26,400 --> 00:03:26,570 So. 51 00:03:26,600 --> 00:03:27,310 And Eddie. 52 00:03:28,780 --> 00:03:31,060 And it will also take the size of the Eddie. 53 00:03:33,130 --> 00:03:34,510 Now we know how to find this out. 54 00:03:34,510 --> 00:03:34,900 The Eddie. 55 00:03:35,890 --> 00:03:38,290 So and answer is initially zero. 56 00:03:38,380 --> 00:03:40,990 We have to initialize our answer with zero. 57 00:03:41,050 --> 00:03:43,660 Otherwise it will contain garbage. 58 00:03:43,900 --> 00:03:46,410 You know, we just have to hydrate. 59 00:03:46,540 --> 00:03:48,700 So four and I equals zero. 60 00:03:48,770 --> 00:03:51,010 I less than an A plus. 61 00:03:51,010 --> 00:03:54,580 Plus, we will add the current value to my answer. 62 00:03:54,610 --> 00:03:58,110 So answer plus equals eight of a.. 63 00:03:59,220 --> 00:04:00,550 Now this is all that we have to do. 64 00:04:00,580 --> 00:04:06,760 Finally, after calculating this, um, we will return that sum to the calling function, which is mean. 65 00:04:07,900 --> 00:04:09,430 And after getting the sum here. 66 00:04:09,490 --> 00:04:10,630 After getting the answer. 67 00:04:11,140 --> 00:04:12,460 What I will do, I will. 68 00:04:12,780 --> 00:04:13,760 Brent Sum. 69 00:04:13,950 --> 00:04:14,240 Brent. 70 00:04:14,480 --> 00:04:14,860 Answer. 71 00:04:18,890 --> 00:04:20,390 OK, so let's test out program. 72 00:04:22,110 --> 00:04:24,240 So in some coma. 73 00:04:27,310 --> 00:04:28,050 So I'm dining. 74 00:04:28,210 --> 00:04:29,780 Sorry, head will be answered. 75 00:04:34,030 --> 00:04:37,630 So there are, let's say, three elements, Nedry and elements are 120. 76 00:04:38,160 --> 00:04:39,100 So I'm out four days. 77 00:04:39,280 --> 00:04:41,470 My some of the elements are six. 78 00:04:42,760 --> 00:04:48,240 If there are, let's say, five elements and the elements are one, two, three, four and five, four 79 00:04:48,240 --> 00:04:49,710 or five and let's say when. 80 00:04:50,730 --> 00:04:53,690 So I produce four degree 34 plus five. 81 00:04:53,710 --> 00:04:54,850 Thirty nine plus one. 82 00:04:55,180 --> 00:04:58,090 Forty, forty two and forty three. 83 00:04:59,650 --> 00:04:59,860 OK. 84 00:04:59,920 --> 00:05:03,790 So this is how we will pass Eddie to the function. 85 00:05:04,120 --> 00:05:06,130 So we have to pass two things first. 86 00:05:07,480 --> 00:05:08,650 So we have to pass two things. 87 00:05:08,650 --> 00:05:13,360 First, that Eddie and second, the size of the area because we have to ideato the Eddie. 88 00:05:14,950 --> 00:05:24,340 Now, the most important thing they are going to discuss is Eddie, are always biased. 89 00:05:25,620 --> 00:05:27,750 By their friends. 90 00:05:30,670 --> 00:05:33,210 So Ed is always passed by the fence. 91 00:05:33,340 --> 00:05:34,930 So what is the meaning of this statement? 92 00:05:34,960 --> 00:05:35,450 Let's see. 93 00:05:38,600 --> 00:05:40,040 So, for example. 94 00:05:41,560 --> 00:05:43,210 If I will change the value. 95 00:05:44,230 --> 00:05:45,080 So let's see. 96 00:05:45,250 --> 00:05:47,380 I am changing the value of the first element. 97 00:05:48,100 --> 00:05:50,110 Let's say the value is five. 98 00:05:51,010 --> 00:05:52,720 So this value will be changed. 99 00:05:53,530 --> 00:05:55,350 Now, I am printing daddy first. 100 00:05:55,590 --> 00:05:55,920 Daddy. 101 00:05:57,160 --> 00:05:59,080 And after calculating Lissome again. 102 00:05:59,080 --> 00:05:59,580 Vendetti. 103 00:06:00,490 --> 00:06:04,470 So print a comma and. 104 00:06:07,150 --> 00:06:07,440 OK. 105 00:06:08,530 --> 00:06:09,610 So let's come it out. 106 00:06:12,750 --> 00:06:16,400 So what we did is we just changed the first reilley of the area. 107 00:06:18,480 --> 00:06:24,840 Suppose there are five elements in the array and the elements are one, two, three, four and five. 108 00:06:26,820 --> 00:06:29,070 So you can hear the element was one. 109 00:06:29,250 --> 00:06:35,400 Now, the first element has become five because I have written I have changed the zero index value of 110 00:06:35,400 --> 00:06:36,420 zero equals five. 111 00:06:37,170 --> 00:06:37,380 OK. 112 00:06:37,520 --> 00:06:41,240 That is are always passed by reference one more time later. 113 00:06:41,400 --> 00:06:44,250 There is only one element and that element is three. 114 00:06:45,750 --> 00:06:48,170 So first we will do the normal print three. 115 00:06:48,270 --> 00:06:51,720 And after we call the sum function, some function will change the value to five. 116 00:06:51,750 --> 00:06:53,160 Then five is getting printed. 117 00:06:53,910 --> 00:06:54,590 So let's see. 118 00:06:57,320 --> 00:06:58,410 So what is happening here? 119 00:06:58,860 --> 00:07:04,160 First, you are calling brain function, brain function will normally print the content of the array, 120 00:07:04,620 --> 00:07:06,240 then you're calling the function some. 121 00:07:06,690 --> 00:07:10,170 Some function is changing the value of a of the zero. 122 00:07:11,340 --> 00:07:13,920 OK, and then you are again printing, Eddie. 123 00:07:17,030 --> 00:07:24,140 So this is normal input that I am printing of zero, then I'm calling some function what some function 124 00:07:24,140 --> 00:07:24,620 will do. 125 00:07:24,980 --> 00:07:28,490 It will change the value of a of zero to 123. 126 00:07:29,060 --> 00:07:34,550 And finally, after calling the function some, I am printing the value of a zero again. 127 00:07:38,410 --> 00:07:45,730 So let's say there are five elements in the area and the elements are one, four, five, three and 128 00:07:45,730 --> 00:07:46,240 six. 129 00:07:47,830 --> 00:07:50,320 So the first value of zero. 130 00:07:50,590 --> 00:07:51,670 You can here you can see. 131 00:07:52,810 --> 00:07:57,340 So if zero is one and a Odilo becomes a 123. 132 00:07:59,710 --> 00:08:02,140 OK, so why it is so. 133 00:08:02,470 --> 00:08:05,620 Because it is are passed by their friends. 134 00:08:06,340 --> 00:08:06,630 OK. 135 00:08:08,240 --> 00:08:10,160 So if you have any doubt, feel free to ask. 136 00:08:10,610 --> 00:08:11,870 So this is it for this video. 137 00:08:12,410 --> 00:08:12,950 Thank you.