1 00:00:01,200 --> 00:00:02,880 Hey, guys, what's up? 2 00:00:03,240 --> 00:00:08,280 So today we are going to solve one more interesting problem, one more PADDON printing problem. 3 00:00:09,030 --> 00:00:15,450 So the rebels treatment is given and we have to print the falling pattern. 4 00:00:16,530 --> 00:00:18,600 So given then we have to print. 5 00:00:20,520 --> 00:00:26,040 We have to rent a falling pattern, so for any equals five. 6 00:00:26,100 --> 00:00:27,960 My pattern will be something like. 7 00:00:50,050 --> 00:00:56,440 So if you remember, we have already sold this type of problem and flowcharts or I think in some locals. 8 00:00:57,400 --> 00:00:59,620 So the logic was very simple here. 9 00:00:59,710 --> 00:01:05,590 The Valley of Fire is one here, the valley of fire is to the valley of phase three. 10 00:01:06,100 --> 00:01:09,280 The valley of high is full and the valley VLDL, phase five. 11 00:01:09,700 --> 00:01:11,110 So one thing is very clear. 12 00:01:11,560 --> 00:01:14,970 If the veil of and it's five, I have to print five arrows. 13 00:01:15,430 --> 00:01:15,620 OK. 14 00:01:16,030 --> 00:01:19,740 So I need an outer loop and this loop will run and times. 15 00:01:20,740 --> 00:01:24,790 So and time's outer loop. 16 00:01:25,780 --> 00:01:28,540 And first of all, I have to print spaces. 17 00:01:28,930 --> 00:01:29,560 So how I mean, it's. 18 00:01:29,860 --> 00:01:30,610 I have to print. 19 00:01:31,540 --> 00:01:32,470 I have to print. 20 00:01:32,890 --> 00:01:35,260 And minus I space's. 21 00:01:37,240 --> 00:01:39,730 OK, then I have to print values. 22 00:01:40,770 --> 00:01:45,130 Then I have to print values and how many will lose? 23 00:01:45,330 --> 00:01:46,110 I have to print. 24 00:01:47,340 --> 00:01:51,780 So I have to print the way minus one values. 25 00:01:53,160 --> 00:01:54,000 I have to print. 26 00:01:54,150 --> 00:01:54,870 You can see here. 27 00:01:54,900 --> 00:01:56,360 I have to print to I minus. 28 00:01:56,520 --> 00:01:59,040 When we lose the value of I is three. 29 00:01:59,610 --> 00:02:00,920 So two and two. 30 00:02:00,930 --> 00:02:02,070 Three minus one. 31 00:02:02,100 --> 00:02:03,000 That is five. 32 00:02:03,150 --> 00:02:04,790 So I have to print five. 33 00:02:04,800 --> 00:02:05,170 Raila's. 34 00:02:06,570 --> 00:02:13,730 OK, so first I will print and minus ibises and then I will print Douai, minus one may lose starting. 35 00:02:15,410 --> 00:02:17,120 From one. 36 00:02:17,660 --> 00:02:20,950 So I have to bring it to a minus when we lose, starting from one. 37 00:02:22,280 --> 00:02:28,100 And then after printing the entire rule, what I will do, I have to will do next line. 38 00:02:28,130 --> 00:02:30,800 So she yelled and line. 39 00:02:30,900 --> 00:02:32,960 Now this go to next line. 40 00:02:33,500 --> 00:02:35,120 So this is our logic. 41 00:02:36,250 --> 00:02:36,500 OK. 42 00:02:37,130 --> 00:02:39,710 So let us implement and C++. 43 00:02:45,630 --> 00:02:49,490 So let us name this file as number by 10. 44 00:02:49,800 --> 00:02:50,550 So a number. 45 00:02:53,590 --> 00:02:54,070 Burton. 46 00:03:08,010 --> 00:03:18,180 So what I have to do, I will first take and as input fundi, use it then since we have to print Androes, 47 00:03:18,390 --> 00:03:22,760 I need a loop and this loop children and times. 48 00:03:22,860 --> 00:03:24,090 So in Dich was when. 49 00:03:27,900 --> 00:03:31,230 While I is less than or equal to n 50 00:03:33,960 --> 00:03:34,970 I blessed, blessed. 51 00:03:35,460 --> 00:03:41,220 So this loop will run and times and each time this loop is running. 52 00:03:41,280 --> 00:03:43,170 I have to print a year through. 53 00:03:44,150 --> 00:03:44,540 Okay. 54 00:03:44,910 --> 00:03:47,330 And for printing I year through. 55 00:03:47,670 --> 00:03:49,050 This is my logic. 56 00:03:49,740 --> 00:03:52,020 So this logic is for printing. 57 00:03:52,290 --> 00:03:53,240 Yet a rule. 58 00:03:54,060 --> 00:03:57,100 So first of all I have to print and minus I spaces. 59 00:03:57,630 --> 00:04:02,960 So I need a lube and this loop should run and minus one times. 60 00:04:03,630 --> 00:04:03,890 Okay. 61 00:04:04,500 --> 00:04:06,480 So let's do it. 62 00:04:07,590 --> 00:04:11,100 So I need a loop that will run and minus one times. 63 00:04:11,580 --> 00:04:16,150 So that us take a variable and count equals one. 64 00:04:17,160 --> 00:04:17,960 And how many times. 65 00:04:17,960 --> 00:04:20,460 And children and minus eight times. 66 00:04:20,550 --> 00:04:28,020 So while ground is less than articles two and minus I. 67 00:04:31,070 --> 00:04:36,320 So this loop is learning and minus times, and each time this loop is running. 68 00:04:36,410 --> 00:04:40,940 I have to print spaces, so I have to print spaces. 69 00:04:42,410 --> 00:04:44,480 So now I have printed special. 70 00:04:46,010 --> 00:04:51,130 What I have to do now, now I have to print values. 71 00:04:52,130 --> 00:04:55,970 I have to print values starting from one. 72 00:04:56,270 --> 00:04:57,920 So how many values I have to print? 73 00:04:58,100 --> 00:05:00,770 I have to print the way minus one may lose. 74 00:05:00,860 --> 00:05:08,450 That means I need a lube and this lube children to a minus one times. 75 00:05:10,210 --> 00:05:10,400 OK. 76 00:05:10,520 --> 00:05:13,190 So this look, children do y minus one times. 77 00:05:13,700 --> 00:05:15,750 And also I will need a variable. 78 00:05:16,130 --> 00:05:17,430 Let's call it value initially. 79 00:05:17,440 --> 00:05:18,520 Well it will be one. 80 00:05:18,800 --> 00:05:20,240 And value will be incremented. 81 00:05:20,780 --> 00:05:21,800 At each step. 82 00:05:23,260 --> 00:05:23,530 OK. 83 00:05:25,300 --> 00:05:27,130 Why my values initially when? 84 00:05:27,970 --> 00:05:30,220 Because you can see here. 85 00:05:30,690 --> 00:05:36,170 I have to start printing from one and then I really incremental I. 86 00:05:36,580 --> 00:05:38,710 Because then I have to print two. 87 00:05:38,800 --> 00:05:39,430 Then three. 88 00:05:40,210 --> 00:05:41,920 Then again, two and three and four. 89 00:05:41,920 --> 00:05:42,640 And then five. 90 00:05:43,030 --> 00:05:45,910 And how many values do I minus one values. 91 00:05:45,970 --> 00:05:47,030 So I need to do that. 92 00:05:47,030 --> 00:05:48,820 QUILLIAN do I minus one times. 93 00:05:50,020 --> 00:05:51,610 OK, cool. 94 00:05:52,750 --> 00:05:53,380 So. 95 00:05:55,750 --> 00:05:56,860 I need a loop. 96 00:05:57,430 --> 00:05:59,310 So let's call it J. 97 00:05:59,590 --> 00:06:01,600 So into J equals one. 98 00:06:02,530 --> 00:06:04,540 And I need a value. 99 00:06:05,040 --> 00:06:10,090 So initially value it equals one because I had to start printing from one. 100 00:06:10,900 --> 00:06:13,090 So how many times this loop should run? 101 00:06:13,810 --> 00:06:17,080 So this loop children the way minus one times. 102 00:06:17,770 --> 00:06:20,410 So the A minus one. 103 00:06:24,780 --> 00:06:25,600 G best. 104 00:06:26,470 --> 00:06:32,770 So this loop will run the way minus one times and each time this loop is running. 105 00:06:33,160 --> 00:06:36,250 What I have to do, I have to seek out value. 106 00:06:37,300 --> 00:06:40,240 And also I have to increment value. 107 00:06:40,570 --> 00:06:41,890 Because next time. 108 00:06:42,940 --> 00:06:47,170 Because next time after I will do a loop under after two to live enter. 109 00:06:48,030 --> 00:06:48,300 Okay. 110 00:06:48,670 --> 00:06:51,060 So I have to incrementally value also. 111 00:06:53,350 --> 00:06:59,650 Now at this point of time I have printed I yet through Vendel has been printed completely. 112 00:07:00,040 --> 00:07:03,560 So I will go to next line and we're going to next line. 113 00:07:03,580 --> 00:07:05,800 We will write C out and line. 114 00:07:06,770 --> 00:07:08,600 But this is the complete logic. 115 00:07:09,830 --> 00:07:10,700 You can see the gold. 116 00:07:18,460 --> 00:07:22,150 OK, so let us test our program for different values of an. 117 00:07:24,900 --> 00:07:26,610 So here is there is an error. 118 00:07:27,900 --> 00:07:28,110 OK. 119 00:07:28,200 --> 00:07:30,850 So it will be Duplass best and then semicolon. 120 00:07:32,190 --> 00:07:35,190 OK, now let us run our program. 121 00:07:39,350 --> 00:07:41,380 Suppose the value of end is three. 122 00:07:42,740 --> 00:07:44,160 So output is correct. 123 00:07:45,850 --> 00:07:48,280 Now, I suppose they're really off. 124 00:07:48,380 --> 00:07:49,190 And is. 125 00:07:50,310 --> 00:07:50,850 Five. 126 00:07:53,970 --> 00:07:56,010 So output is correct. 127 00:07:57,100 --> 00:07:57,360 OK. 128 00:07:59,210 --> 00:08:00,290 You can see the gaudier. 129 00:08:06,280 --> 00:08:09,510 So first of all, our logic was I have to print Androes. 130 00:08:10,810 --> 00:08:16,900 So this look I equals one, I less than less to win and I plus plus this with the help of these three, 131 00:08:16,990 --> 00:08:19,900 my local children and dimes, because we have to print Ando's. 132 00:08:21,600 --> 00:08:26,820 Then we have decided that we will print and minus I species. 133 00:08:27,890 --> 00:08:31,880 So canticles one countless dingo's to end minus eight and count plus plus. 134 00:08:32,150 --> 00:08:39,350 So this loop will go on and minus eight times and each time I am printing Speace correct. 135 00:08:40,490 --> 00:08:47,640 After that, we decided that we have to print the way, we have to print the way minus one values. 136 00:08:48,260 --> 00:08:51,200 So I need a loop there to learn the way minus one times. 137 00:08:51,830 --> 00:08:57,260 So in the Jaquiss one J less tangles to do a minus one and G plus plus. 138 00:08:57,770 --> 00:09:03,350 So at Delp of these three this loop will run the way minus one times and we have decided that we will 139 00:09:03,350 --> 00:09:07,490 start printing Relu starting from one, then two, then three and so on. 140 00:09:08,090 --> 00:09:14,450 So for that reinitialize to a variable value which is initially one and each time we are printing this 141 00:09:14,450 --> 00:09:21,590 value and each time we had incrementing the value by one and after printing the entire rule, I will 142 00:09:21,590 --> 00:09:22,850 go to the next line. 143 00:09:22,880 --> 00:09:24,260 So see out and Lane. 144 00:09:25,010 --> 00:09:26,810 So this is the complete logic. 145 00:09:28,390 --> 00:09:30,660 OK, so this problem was easy. 146 00:09:31,970 --> 00:09:33,320 So this is it for this video. 147 00:09:33,560 --> 00:09:34,430 Thanks for watching.