1 00:00:00,590 --> 00:00:04,170 OK, so let us discuss the last problem of part two. 2 00:00:04,820 --> 00:00:06,170 So problem Lamberti. 3 00:00:09,350 --> 00:00:16,280 The problem statement is read in and print full length by 10. 4 00:00:20,020 --> 00:00:21,850 Brent following pattern. 5 00:00:23,770 --> 00:00:28,140 If the really of and is three, the pattern will look like this. 6 00:00:32,640 --> 00:00:37,200 If the value of and is too bad, then will look like this. 7 00:00:39,060 --> 00:00:44,520 And if the value of N is five, the better would look something like this. 8 00:00:59,870 --> 00:01:02,360 OK, so how we can solve this problem? 9 00:01:06,050 --> 00:01:08,210 If you look carefully, if the value of. 10 00:01:08,770 --> 00:01:09,150 T. 11 00:01:09,620 --> 00:01:11,050 I am printing three. 12 00:01:12,390 --> 00:01:15,880 If the value of Venice to I am printing doodles. 13 00:01:16,370 --> 00:01:20,380 If the value of wine is five, I am printing faithful's. 14 00:01:21,380 --> 00:01:28,490 So one thing is very clear here that I need a loop and this loop will run and times. 15 00:01:30,510 --> 00:01:33,560 Because we have to print Enda's is the value of. 16 00:01:33,750 --> 00:01:34,400 Is three. 17 00:01:34,680 --> 00:01:36,360 This look Willdan two times. 18 00:01:36,440 --> 00:01:39,820 If the value of N is to this look vildan two times. 19 00:01:39,870 --> 00:01:44,130 And if the value of an is five this look Willdan five times. 20 00:01:45,390 --> 00:01:46,850 OK, so let us revise. 21 00:01:47,210 --> 00:01:52,860 So the problem was I have to read and and we have to print following patterns over the value of ancestry. 22 00:01:53,390 --> 00:01:54,380 I have to print materials. 23 00:01:54,620 --> 00:01:56,500 If the value of I need to I have to print to. 24 00:01:56,740 --> 00:01:59,130 If the value of finance life, I have to print five rolls. 25 00:01:59,660 --> 00:02:02,230 So I told you that I need a loop. 26 00:02:02,660 --> 00:02:06,050 And this look, Willdan end times because we have to print. 27 00:02:06,170 --> 00:02:06,650 And those. 28 00:02:07,900 --> 00:02:08,080 OK. 29 00:02:08,190 --> 00:02:11,070 So how will this loop run and times? 30 00:02:11,400 --> 00:02:18,480 So I will use a variable eye which is initialized to one is I less than Noriko's two n. 31 00:02:20,450 --> 00:02:22,340 And I equals a plus one. 32 00:02:23,120 --> 00:02:28,220 So with the help of these three blogs, this loop will run end times. 33 00:02:29,520 --> 00:02:29,810 OK. 34 00:02:30,620 --> 00:02:31,940 And inside this loop. 35 00:02:32,420 --> 00:02:33,050 Each time. 36 00:02:33,350 --> 00:02:34,010 What will I do? 37 00:02:34,100 --> 00:02:35,000 I will print all. 38 00:02:37,300 --> 00:02:42,200 I'm putting myself each time this loop is running, I will print Arrow. 39 00:02:44,230 --> 00:02:44,480 OK. 40 00:02:45,240 --> 00:02:52,080 This loop is running and times, and each time I am printing, I do so in total I will be able to print 41 00:02:52,280 --> 00:02:52,780 Ando's. 42 00:02:53,370 --> 00:02:54,750 So the approach is very simple. 43 00:02:55,080 --> 00:02:58,570 This loop is ending and times and each time I am printing Adderall. 44 00:02:59,010 --> 00:03:01,470 So finally I will be able to print and lose. 45 00:03:02,640 --> 00:03:05,890 Now, the second problem, how to print a rule. 46 00:03:08,220 --> 00:03:09,360 How will I bring that to. 47 00:03:15,110 --> 00:03:20,380 So if you look carefully each time, I have to print different oral. 48 00:03:22,590 --> 00:03:27,820 Here, the value of I is three here, the value of AI is to value of to vilify one. 49 00:03:28,140 --> 00:03:34,470 So if the value if I is when I have to print just one star is the value of AI is do I have to print 50 00:03:34,760 --> 00:03:35,390 those stars. 51 00:03:35,490 --> 00:03:38,660 If the value of AI is three, I have to print two stars. 52 00:03:39,090 --> 00:03:45,030 You can look here, also here I equals four here and I equals five and so on. 53 00:03:45,630 --> 00:03:46,710 Here I equals one. 54 00:03:46,980 --> 00:03:50,200 So if the value of AI is one, I have to print just one star. 55 00:03:50,250 --> 00:03:54,720 If the value of I used to I have to print two stars and if the value of AI is five, I have to print 56 00:03:54,750 --> 00:03:55,380 five stars. 57 00:03:56,460 --> 00:04:06,330 So for printing a rule, I need a loop and this loop will run eight times because you can see here if 58 00:04:06,330 --> 00:04:07,570 the value of AI is three. 59 00:04:07,700 --> 00:04:09,090 I am printing three stars. 60 00:04:09,880 --> 00:04:12,570 If the value of AI is two, I am printing two stars. 61 00:04:13,530 --> 00:04:16,220 If the real fight is won, I am printing one stars. 62 00:04:16,650 --> 00:04:21,750 So that is the reason I need a lube and this loop will run eight times. 63 00:04:22,690 --> 00:04:24,900 OK, so how will I run this loop by eight times. 64 00:04:25,290 --> 00:04:28,900 I will use a variable G which is initialized to one. 65 00:04:28,920 --> 00:04:29,700 Then I will check. 66 00:04:29,850 --> 00:04:31,770 Is G less than or equal to a. 67 00:04:33,280 --> 00:04:34,060 And J. 68 00:04:34,100 --> 00:04:36,010 Equals J plus one. 69 00:04:37,120 --> 00:04:42,280 So with the help of these three blogs, this loop will run eight times. 70 00:04:43,240 --> 00:04:43,550 OK. 71 00:04:43,840 --> 00:04:44,800 So let us revise. 72 00:04:45,160 --> 00:04:47,860 So the question was, I have to print oral. 73 00:04:48,190 --> 00:04:49,370 So how do I bring Durrow? 74 00:04:49,960 --> 00:04:53,860 So I told you, if you look carefully, if the value of history I am printing through Rose. 75 00:04:53,950 --> 00:04:56,080 If the value if I is true, I am printing to Rose. 76 00:04:56,110 --> 00:04:56,560 If the value. 77 00:04:56,560 --> 00:04:58,400 If I is when I am printing Wendle. 78 00:04:59,650 --> 00:05:00,930 So I need a loop. 79 00:05:02,200 --> 00:05:06,690 And this loop will run eight times, and each time I will print. 80 00:05:07,380 --> 00:05:08,490 I start OK. 81 00:05:08,920 --> 00:05:11,170 So each time I am printing, I start. 82 00:05:11,230 --> 00:05:13,060 And this loop is running eight times. 83 00:05:13,150 --> 00:05:16,240 So in total, I will be able to print I starts. 84 00:05:17,570 --> 00:05:23,660 I am repeating myself, each time this loop is running, I will print star and this loop is running 85 00:05:23,800 --> 00:05:26,940 eight times, so I will be able to print I starts. 86 00:05:28,010 --> 00:05:32,530 And how will I run this loop by at times with the help of these three blogs. 87 00:05:33,110 --> 00:05:35,690 I will be able to run this loop eight times. 88 00:05:36,680 --> 00:05:37,990 So let does the the flowchart. 89 00:05:43,450 --> 00:05:45,130 So I will start my flow chart. 90 00:05:49,420 --> 00:05:50,860 Then I will read an. 91 00:05:54,810 --> 00:06:00,090 And then I have to print Ando's, so I will use a variable play, which is initialized to one. 92 00:06:00,450 --> 00:06:03,770 Then I will check the condition is I. 93 00:06:04,200 --> 00:06:05,790 Less than articles to end. 94 00:06:08,670 --> 00:06:10,520 Now, if this condition is true. 95 00:06:13,040 --> 00:06:18,270 If this condition is true, that means I'm inside this loop and inside this loop. 96 00:06:18,410 --> 00:06:24,740 Each time I have to print a rule and we have discussed that for printing a rule, I need a loop. 97 00:06:25,040 --> 00:06:27,560 And this loop will run eight times. 98 00:06:30,200 --> 00:06:30,470 OK. 99 00:06:31,360 --> 00:06:36,970 So for running the loop, I at times I am using a variable G which is initialized to one, then I will 100 00:06:36,970 --> 00:06:41,380 check is g less than or it goes to a. 101 00:06:42,780 --> 00:06:47,430 Now, if this condition is true, I have to print stutt. 102 00:06:51,250 --> 00:06:52,870 Jay, it goes deep, less than. 103 00:06:54,980 --> 00:06:57,230 And then check the condition again. 104 00:07:00,980 --> 00:07:01,280 OK. 105 00:07:01,340 --> 00:07:05,750 So this loop is running eight times and each time I am printing, I start. 106 00:07:06,380 --> 00:07:08,900 So in total, this loop will print. 107 00:07:09,290 --> 00:07:10,490 I starts. 108 00:07:11,760 --> 00:07:13,830 And if this condition is false. 109 00:07:15,910 --> 00:07:20,740 So if this condition is false, that means I have printed Windrow. 110 00:07:24,970 --> 00:07:27,450 Now I have to go to next to line. 111 00:07:28,240 --> 00:07:29,890 So Brent backslash. 112 00:07:29,960 --> 00:07:33,600 And so this is a command for going to next line. 113 00:07:34,480 --> 00:07:37,030 And then I will increase the value of fire by one. 114 00:07:38,440 --> 00:07:40,330 And then I will check the condition again. 115 00:07:42,660 --> 00:07:44,400 So why I'm writing this statement. 116 00:07:46,200 --> 00:07:51,150 If you look carefully after printing this rule, I have to go to next line. 117 00:07:51,510 --> 00:07:54,180 Similarly, after printing this rule, go to next plane. 118 00:07:54,240 --> 00:07:56,730 After printing this rule, I have to go to next line. 119 00:07:58,530 --> 00:08:01,770 So this loop is printing VENDEL. 120 00:08:02,010 --> 00:08:05,330 And after printing this rule, I have to go to next line. 121 00:08:05,430 --> 00:08:07,470 That's why I'm using this statement. 122 00:08:08,370 --> 00:08:09,680 And then I will say, listen. 123 00:08:09,810 --> 00:08:11,520 And then I will check the condition again. 124 00:08:12,390 --> 00:08:17,880 So this loop is running eight times and each time I am printing, I start. 125 00:08:18,570 --> 00:08:27,900 So in total, I will be able to print ice stars and my outlook is running and times and each time I 126 00:08:27,900 --> 00:08:28,440 am printing. 127 00:08:29,040 --> 00:08:33,930 So I will be able to print Ando's if this condition is false. 128 00:08:35,040 --> 00:08:40,080 That means I have rendered all my end those and my work is over now. 129 00:08:40,170 --> 00:08:42,270 So I will end my program. 130 00:08:44,150 --> 00:08:47,450 OK, so let us understand this flowchart with the help of an example. 131 00:08:51,610 --> 00:09:05,770 OK, so let's say the value of an is three start root and I equals one, so I equals one is one less 132 00:09:05,770 --> 00:09:06,580 than I goes to three. 133 00:09:06,640 --> 00:09:07,780 So the condition is true. 134 00:09:08,380 --> 00:09:09,160 You will come here. 135 00:09:09,610 --> 00:09:10,480 J equals one. 136 00:09:10,870 --> 00:09:11,200 Okay. 137 00:09:11,410 --> 00:09:12,620 J equals one. 138 00:09:14,630 --> 00:09:19,280 Then he will check the condition is one less than Ocus to into the condition is true. 139 00:09:19,340 --> 00:09:21,250 You will start August. 140 00:09:21,310 --> 00:09:22,610 I am writing my output here. 141 00:09:23,880 --> 00:09:27,470 So I am printing start increase the value of G. 142 00:09:27,530 --> 00:09:29,810 By one to the new value of J is two. 143 00:09:31,550 --> 00:09:33,770 And then you have to check the condition again. 144 00:09:34,580 --> 00:09:35,670 So is to list. 145 00:09:35,670 --> 00:09:37,840 Then I goes to one to the condition is false. 146 00:09:39,420 --> 00:09:47,770 Windrow has been printed and you have to go to next plane, so I will come here next plane and you are 147 00:09:47,770 --> 00:09:50,860 doing is the value if I buy one or the new value if I is to. 148 00:09:54,520 --> 00:10:00,160 And then you will check the condition again is to list an order close to three. 149 00:10:00,250 --> 00:10:01,390 So the condition is true. 150 00:10:01,510 --> 00:10:04,180 You will come here J equals one. 151 00:10:04,290 --> 00:10:04,630 OK. 152 00:10:06,920 --> 00:10:11,840 Check the condition again is when Lester goes to do to the condition is true. 153 00:10:11,900 --> 00:10:12,650 You will come here. 154 00:10:13,390 --> 00:10:14,550 Brent, start okay. 155 00:10:17,150 --> 00:10:20,300 Engage the value of the observance or the new value of JS to. 156 00:10:21,910 --> 00:10:25,220 The condition, again, is to let them I what to do. 157 00:10:25,360 --> 00:10:26,320 The condition is true. 158 00:10:27,170 --> 00:10:27,910 Brent Astar. 159 00:10:28,180 --> 00:10:28,510 Okay. 160 00:10:30,580 --> 00:10:35,920 And give them a little gem Evans, when you live J.s three and then you have to check the condition 161 00:10:35,920 --> 00:10:36,220 again. 162 00:10:36,550 --> 00:10:38,440 So is three less than goes to do? 163 00:10:38,790 --> 00:10:38,970 No. 164 00:10:39,250 --> 00:10:40,300 The condition is void. 165 00:10:42,030 --> 00:10:42,750 What will you do? 166 00:10:42,840 --> 00:10:44,670 You will go to New Line. 167 00:10:44,760 --> 00:10:45,000 OK. 168 00:10:45,120 --> 00:10:46,110 Now I will come here. 169 00:10:47,850 --> 00:10:48,640 Now what will you do? 170 00:10:48,660 --> 00:10:51,840 You will increase the value if I buy one to the new value of AI is three. 171 00:10:52,650 --> 00:10:54,570 So I equals three. 172 00:10:55,050 --> 00:10:57,000 And then you will check the condition again. 173 00:10:57,420 --> 00:10:59,640 So is three less than ogles to treat? 174 00:10:59,700 --> 00:11:00,570 The condition is true. 175 00:11:00,630 --> 00:11:02,180 You will come here J. 176 00:11:02,220 --> 00:11:02,730 Question. 177 00:11:02,790 --> 00:11:03,100 Okay. 178 00:11:03,360 --> 00:11:05,130 J equals when. 179 00:11:06,570 --> 00:11:10,180 Then I will check is one less than I goes to three. 180 00:11:10,450 --> 00:11:11,680 Yes, the condition is true. 181 00:11:11,740 --> 00:11:17,230 You will print Stata and gives the year by events when new value of JS to. 182 00:11:19,130 --> 00:11:21,290 And then you have to check the condition again. 183 00:11:21,680 --> 00:11:24,010 So is to list then articles close three. 184 00:11:24,860 --> 00:11:25,050 Yes. 185 00:11:25,090 --> 00:11:25,970 The condition is true. 186 00:11:26,060 --> 00:11:29,810 You will start again and give them a live J by one. 187 00:11:30,290 --> 00:11:31,840 So I live j.s three. 188 00:11:32,320 --> 00:11:33,710 I will check the condition again. 189 00:11:34,070 --> 00:11:37,790 So is t less than Noriko's to treat the condition is again through. 190 00:11:38,080 --> 00:11:39,380 You will print one more stop. 191 00:11:40,540 --> 00:11:42,230 Now will you increase their LFG by one. 192 00:11:42,260 --> 00:11:43,130 So anyway, live J. 193 00:11:43,520 --> 00:11:44,540 J will become four. 194 00:11:44,960 --> 00:11:47,750 So is for less than was two three. 195 00:11:48,140 --> 00:11:49,570 No, the condition is false. 196 00:11:49,580 --> 00:11:52,730 So if the condition is false you will go to new line. 197 00:11:53,390 --> 00:11:53,720 Okay. 198 00:11:54,830 --> 00:11:57,180 Next line and you will increase the value of five. 199 00:11:57,510 --> 00:11:59,880 So the new value of EI is four. 200 00:12:01,190 --> 00:12:03,460 And then you will check the condition again. 201 00:12:03,860 --> 00:12:07,070 So is for less than or equal to three. 202 00:12:07,370 --> 00:12:07,730 No. 203 00:12:08,450 --> 00:12:10,690 Four is not less than a cost to three. 204 00:12:11,150 --> 00:12:12,360 So the condition is void. 205 00:12:13,370 --> 00:12:15,620 You will reach here and you will end up program. 206 00:12:15,980 --> 00:12:17,210 So my output is this. 207 00:12:19,350 --> 00:12:21,890 Which is hundred percent correct for any quiz. 208 00:12:22,410 --> 00:12:22,710 Three. 209 00:12:23,850 --> 00:12:25,320 So let us revise what we have done. 210 00:12:27,580 --> 00:12:32,480 So the problem statement was, I have to read and and we have to print the following button. 211 00:12:32,980 --> 00:12:36,760 So if any equals to I am printing doodles if N equals five. 212 00:12:36,820 --> 00:12:38,050 I am printing five floors. 213 00:12:38,140 --> 00:12:41,120 And if and equals three, I am printing Titos. 214 00:12:42,460 --> 00:12:49,660 So one thing is crystal clear here that I need a loop that will run end times because we have to print 215 00:12:49,910 --> 00:12:51,870 those is the value of ministry. 216 00:12:51,970 --> 00:12:57,060 This love will end two times if the value of this to this loop will burn two times if the value of Venezuela. 217 00:12:57,100 --> 00:13:02,580 This look within five times and inside this loop I have to print double. 218 00:13:04,910 --> 00:13:09,710 So each time I am branding arrow and outer loop is running end times. 219 00:13:10,010 --> 00:13:12,560 So in total I will be able to print and lose. 220 00:13:13,420 --> 00:13:15,380 So the first part of this problem is over. 221 00:13:15,800 --> 00:13:16,610 Now the second part. 222 00:13:18,220 --> 00:13:20,060 How to print a room? 223 00:13:20,930 --> 00:13:21,820 Then I told you. 224 00:13:21,880 --> 00:13:24,580 If we look carefully here, if I is three. 225 00:13:24,640 --> 00:13:29,300 So if the value of history I'm printing three stars, if the value of AI is two and printing to start. 226 00:13:29,410 --> 00:13:32,580 If the value of AI is when I am printing just one star. 227 00:13:33,460 --> 00:13:37,990 That means I need a loop and this loop will run eight times. 228 00:13:38,050 --> 00:13:41,310 And inside this loop each time I will print star. 229 00:13:41,950 --> 00:13:45,970 So each time I am printing a star and the outer loop is running eight times. 230 00:13:46,060 --> 00:13:49,200 So in total I would be able to print isobars. 231 00:13:50,230 --> 00:13:55,480 And how will I run this loop by four times with the help of these three blogs, I will be able to run 232 00:13:55,480 --> 00:13:56,590 this loop eight times. 233 00:13:57,100 --> 00:14:00,400 And for running the loop end times, I will use a variable eye. 234 00:14:00,850 --> 00:14:04,060 And with the help of these three blogs, I will be able to run this loop. 235 00:14:04,120 --> 00:14:04,690 And times. 236 00:14:07,290 --> 00:14:09,650 And this is our very simple flu, Jack. 237 00:14:10,410 --> 00:14:13,150 So let's take another example to understand this flowchart. 238 00:14:13,830 --> 00:14:15,180 So let's say and it goes to. 239 00:14:16,590 --> 00:14:19,860 So you start read and I equals one. 240 00:14:20,670 --> 00:14:22,470 So I equals one. 241 00:14:23,630 --> 00:14:24,560 So is. 242 00:14:25,780 --> 00:14:29,290 One less than I got to do for the condition is true, you will come here. 243 00:14:30,100 --> 00:14:35,800 Then Jaquiss one against a Jaquiss one you will check the condition is one less than Agosta. 244 00:14:35,800 --> 00:14:37,800 When the condition is true, we will bring it to start. 245 00:14:38,060 --> 00:14:38,250 OK. 246 00:14:38,410 --> 00:14:42,490 So I am printing stuff and then you will increase the value of J by one. 247 00:14:42,730 --> 00:14:44,300 So the new value of J will become do. 248 00:14:45,130 --> 00:14:46,950 And then you will check the condition again. 249 00:14:47,470 --> 00:14:50,680 So is two less than articles two also the condition is false. 250 00:14:51,190 --> 00:14:56,830 I have printed when I'm Tyrel I have to go to a new line, so I will go to next line. 251 00:14:57,460 --> 00:14:59,100 So now you will increase the value of five. 252 00:14:59,110 --> 00:15:05,230 I want to show the new value of I is two and then I will check the condition again is to list Anglo's 253 00:15:05,230 --> 00:15:10,670 to two for the condition is true j.s again one then you will check the condition again. 254 00:15:11,290 --> 00:15:12,790 So is one less than I goes to. 255 00:15:12,790 --> 00:15:19,080 When the condition is true, you will again being tested and then you will increase the value of J by 256 00:15:19,080 --> 00:15:20,920 one to the new valy of J will become do. 257 00:15:20,920 --> 00:15:24,250 Then you will change the condition again and the condition will again be true. 258 00:15:24,610 --> 00:15:29,140 You will print against that and you will engage the role of thereby once when you will, you will become 259 00:15:29,140 --> 00:15:35,200 three and you have printed this entire drawer and then you will go to a new line. 260 00:15:35,950 --> 00:15:39,310 You will engage the earlier five events of the new value of I will become three. 261 00:15:40,390 --> 00:15:42,910 And similarly, this condition will become false. 262 00:15:43,240 --> 00:15:49,900 And then you will enter program and the output will be this, which is under percent correct for N equals 263 00:15:50,160 --> 00:15:50,340 two. 264 00:15:51,100 --> 00:15:56,950 So this problem requires use of two loops, one loop inside and the loop. 265 00:15:57,370 --> 00:16:02,760 So this inner loop is running eight times and each time I am printing, I start. 266 00:16:02,830 --> 00:16:06,210 So in total I am printing Istar Sarah. 267 00:16:08,710 --> 00:16:09,000 OK. 268 00:16:09,880 --> 00:16:11,250 And the outer loop. 269 00:16:12,600 --> 00:16:18,480 Is running and times and each time I am printing Vendel. 270 00:16:18,930 --> 00:16:21,810 So in total I will be able to print Androes. 271 00:16:23,480 --> 00:16:25,490 So I hope you have understood this problem. 272 00:16:25,670 --> 00:16:29,060 We will be printing many such patterns in our future lessons. 273 00:16:29,630 --> 00:16:32,120 So this problem should be crystal clear in your mind. 274 00:16:32,420 --> 00:16:36,560 That is why we need to lose here how this loops are working. 275 00:16:37,220 --> 00:16:43,550 So my advice to you is take out your pen and paper and try to do the flowchart on your own. 276 00:16:44,620 --> 00:16:48,790 Take few different values often and try to understand how this loops are working. 277 00:16:49,870 --> 00:16:53,500 So finally, congratulations on finishing all the six problems. 278 00:16:53,770 --> 00:16:55,090 You have done a great job. 279 00:16:55,930 --> 00:16:59,140 So if you have any doubt in any question, feel free to ask. 280 00:16:59,520 --> 00:17:01,490 In the next class, we will learn pseudocode. 281 00:17:03,430 --> 00:17:04,090 Pseudo. 282 00:17:05,940 --> 00:17:09,470 Called the next class will be focused on pseudocode. 283 00:17:09,780 --> 00:17:11,430 So I hope you enjoyed today's tutorial. 284 00:17:11,550 --> 00:17:12,840 I will tune an extra story. 285 00:17:13,030 --> 00:17:14,550 Till then, enjoy C++.