1 00:00:03,590 --> 00:00:04,370 Hello, everybody. 2 00:00:04,730 --> 00:00:05,840 Welcome back to the courts. 3 00:00:06,200 --> 00:00:10,070 In the last lesson, we covered basics of flowchart and solved a few problems. 4 00:00:10,550 --> 00:00:13,010 Today, we will solve a few different types of problem. 5 00:00:13,310 --> 00:00:16,350 And with the help of those problem, we will learn a new concept. 6 00:00:16,790 --> 00:00:18,400 So let us start today's class. 7 00:00:19,040 --> 00:00:25,860 So the problem statement is so the problem with treatment is you have to read to no E and the. 8 00:00:26,120 --> 00:00:28,060 And you have to print it as D. 9 00:00:28,400 --> 00:00:31,400 And you have to print five. 10 00:00:32,380 --> 00:00:32,950 DOMS. 11 00:00:34,460 --> 00:00:35,280 Of deform. 12 00:00:36,610 --> 00:00:46,060 A plus B, A plus duty, A plus to be A plus 40 and A plus 50. 13 00:00:47,750 --> 00:00:51,780 So let us first solve this problem in the most easiest and the simplest way. 14 00:00:52,790 --> 00:00:56,900 I will start my program and then I will read. 15 00:00:56,960 --> 00:00:59,120 Do no read. 16 00:00:59,210 --> 00:00:59,410 E. 17 00:01:00,070 --> 00:01:00,530 andI. 18 00:01:02,850 --> 00:01:04,320 And then I will print. 19 00:01:06,060 --> 00:01:06,780 A place de. 20 00:01:10,370 --> 00:01:12,620 Now, I will print a plus 2D. 21 00:01:18,290 --> 00:01:20,420 Now, I will print a plus 30. 22 00:01:25,170 --> 00:01:29,150 Now I will print a place for me. 23 00:01:30,420 --> 00:01:35,700 And finally, I will bring to my last home, which is a plus five. 24 00:01:37,950 --> 00:01:39,390 No way work is over. 25 00:01:40,170 --> 00:01:40,470 I will. 26 00:01:40,640 --> 00:01:40,960 Anyway. 27 00:01:42,440 --> 00:01:48,750 Program, so let us revise again what we have done, so the Brownlow's treatment was you have to read 28 00:01:48,840 --> 00:01:54,890 numbers A and B and you have to print five times of deform A plus D plus two, DTD four and five. 29 00:01:55,520 --> 00:01:58,160 So what I did, we start our program. 30 00:01:58,530 --> 00:02:04,080 Then we do numbers A&E and we have printed the five times and then we have another program. 31 00:02:04,880 --> 00:02:08,960 So I hope by this time you might have noticed something strange with this approach. 32 00:02:09,380 --> 00:02:12,020 And if you didn't, then I have a question for you. 33 00:02:12,410 --> 00:02:13,880 So my question is very simple. 34 00:02:14,360 --> 00:02:16,880 What do you think of what might be the problem with this approach? 35 00:02:17,300 --> 00:02:19,490 I'm telling you this a problem with this approach. 36 00:02:19,610 --> 00:02:21,350 And you have to tell me what is the problem? 37 00:02:22,100 --> 00:02:23,720 Take your time and try to think. 38 00:02:25,180 --> 00:02:26,520 OK, let me give you a hint. 39 00:02:26,980 --> 00:02:29,640 In this case, I am printing just only five of them. 40 00:02:30,460 --> 00:02:32,170 So this approach is working fine. 41 00:02:32,620 --> 00:02:33,850 No problem at all. 42 00:02:34,390 --> 00:02:36,940 But what if we have to print one million item? 43 00:02:37,750 --> 00:02:38,890 Will this approach work? 44 00:02:39,850 --> 00:02:42,070 Would you use this approach to print one million item? 45 00:02:43,090 --> 00:02:43,870 Obviously, no. 46 00:02:44,500 --> 00:02:45,820 So I hope you got the idea. 47 00:02:46,390 --> 00:02:48,310 Let's come back to the question that I asked you. 48 00:02:48,910 --> 00:02:50,350 What is the problem with this approach? 49 00:02:50,890 --> 00:02:52,180 Yes, you got it right. 50 00:02:52,540 --> 00:02:55,580 This approach is very time consuming and inefficient. 51 00:02:56,660 --> 00:02:59,660 But why this approach is time consuming and inefficient? 52 00:03:00,020 --> 00:03:01,220 The answer is very simple. 53 00:03:01,310 --> 00:03:03,470 We are doing the same work again and again. 54 00:03:03,500 --> 00:03:04,910 Basically, repetition is dear. 55 00:03:05,300 --> 00:03:06,590 You can see the repetition here. 56 00:03:06,920 --> 00:03:08,810 We are printing again and again and again. 57 00:03:08,990 --> 00:03:10,630 This is just repetition of the work. 58 00:03:11,090 --> 00:03:16,550 If we look carefully, I can express any of their time as E-Plus idee. 59 00:03:17,180 --> 00:03:25,850 If the value of AI is one, if I equals when my time is a plus D, if I equals to my thumb is a plus 60 00:03:26,050 --> 00:03:26,430 Dody. 61 00:03:26,930 --> 00:03:29,600 And similarly, if the value of AI equals five. 62 00:03:30,020 --> 00:03:32,630 My time is a plus five. 63 00:03:33,650 --> 00:03:39,860 So basically we have to print a plus idee and the value of I will vary from one to five. 64 00:03:40,190 --> 00:03:42,380 So there are two ways to change the values of AI. 65 00:03:43,910 --> 00:03:47,840 So I told you there are two ways to change the values of AI. 66 00:03:48,140 --> 00:03:51,590 So the first way is that we ourself manually change the value of AI. 67 00:03:52,250 --> 00:03:56,940 But the problem with this approach is what would you do if you want to print one million item? 68 00:03:57,410 --> 00:03:58,990 So this approach will fail. 69 00:03:59,780 --> 00:04:07,460 The second key is that we will write some logic in such a way that the value of I will change automatically. 70 00:04:08,800 --> 00:04:11,200 Our logic will look something like this. 71 00:04:12,560 --> 00:04:14,090 Initially, my eye will be one. 72 00:04:15,480 --> 00:04:17,880 Then I will check is a list tonight. 73 00:04:17,930 --> 00:04:18,630 Close to five. 74 00:04:19,230 --> 00:04:19,650 Yes. 75 00:04:19,740 --> 00:04:20,670 One is less than I. 76 00:04:20,750 --> 00:04:21,450 Close to five. 77 00:04:21,900 --> 00:04:23,010 The condition is true. 78 00:04:23,340 --> 00:04:25,170 If the condition is true, what will I do? 79 00:04:25,800 --> 00:04:28,100 I will print E-Plus idee. 80 00:04:29,520 --> 00:04:33,640 So in this case, E-Plus Duvel reprinted and after printing Ableist Idee. 81 00:04:34,500 --> 00:04:35,220 What will I do? 82 00:04:35,730 --> 00:04:39,930 I will increase the value. 83 00:04:42,320 --> 00:04:45,830 Off I buy when? 84 00:04:48,110 --> 00:04:53,440 So the new really, if I becomes to, then I will check the condition again is to let the necklace two. 85 00:04:53,440 --> 00:04:53,710 Five. 86 00:04:53,810 --> 00:04:55,510 Yes, 20 plus 80. 87 00:04:55,580 --> 00:04:55,880 OK. 88 00:04:55,940 --> 00:04:57,400 So E-Plus truly gets printed. 89 00:04:57,950 --> 00:04:59,750 Then everything is the value if I buy one. 90 00:05:00,050 --> 00:05:02,870 So the new value if I is three then I will check my condition again. 91 00:05:02,960 --> 00:05:04,490 Estela's then goes to five years. 92 00:05:05,080 --> 00:05:05,330 Ben. 93 00:05:06,380 --> 00:05:09,320 Now the new value if I is for is for less than it goes to five. 94 00:05:09,380 --> 00:05:09,770 Yes. 95 00:05:09,860 --> 00:05:10,490 Ben diatom. 96 00:05:11,810 --> 00:05:14,740 Increase the value of I buy went to the new value of I is five. 97 00:05:15,460 --> 00:05:17,620 Check the condition Fifers Latona goes to five. 98 00:05:17,710 --> 00:05:26,110 Yes Pendelton E-Plus finally incremental value if I buy one to the new value if I is six is six less 99 00:05:26,110 --> 00:05:27,070 done it goes to five. 100 00:05:28,360 --> 00:05:28,810 No. 101 00:05:29,110 --> 00:05:31,350 So the condition is false. 102 00:05:33,570 --> 00:05:34,410 So what will I do? 103 00:05:34,440 --> 00:05:35,700 I will come out of the loop. 104 00:05:36,120 --> 00:05:37,630 Or who can say exit from the loop? 105 00:05:37,680 --> 00:05:38,940 Or you can see break the loop. 106 00:05:41,600 --> 00:05:47,420 So to implement the logic, the thing we need is called a loop, or you can see a cycle. 107 00:05:48,930 --> 00:05:50,870 So basically, there are three parts of a loop. 108 00:05:52,470 --> 00:06:01,320 So the first part is initialise the second Pardo's condition and the third parties update. 109 00:06:03,080 --> 00:06:04,190 So in the above case. 110 00:06:05,660 --> 00:06:06,690 I equals one. 111 00:06:07,340 --> 00:06:09,470 This is known as nasalization. 112 00:06:10,820 --> 00:06:12,160 This is the first part of a loop. 113 00:06:12,650 --> 00:06:14,630 Second part is to check the condition. 114 00:06:14,660 --> 00:06:16,790 So this is condition. 115 00:06:18,770 --> 00:06:20,540 And the third parties update. 116 00:06:20,780 --> 00:06:22,520 So this is update. 117 00:06:22,730 --> 00:06:24,320 We are updating the value of Ibai. 118 00:06:24,440 --> 00:06:24,710 When? 119 00:06:25,780 --> 00:06:28,320 So let us see, how does a loop look? 120 00:06:29,620 --> 00:06:30,280 How does. 121 00:06:31,990 --> 00:06:32,630 I loop. 122 00:06:35,150 --> 00:06:35,570 Look. 123 00:06:36,910 --> 00:06:38,970 So the first part is initialise. 124 00:06:40,180 --> 00:06:41,470 So I really wish lay something. 125 00:06:43,010 --> 00:06:45,620 The second part is to check the condition. 126 00:06:47,180 --> 00:06:48,500 Here we have it condition. 127 00:06:49,130 --> 00:06:55,070 If the condition is true, if the condition is true, then I will do some book. 128 00:06:56,520 --> 00:07:00,900 I will do some work, and after doing the book, I will update. 129 00:07:04,440 --> 00:07:10,260 After updating, I will check my condition again, if the condition is Viento, I will again do some 130 00:07:10,260 --> 00:07:13,050 work and then update that will check the condition again. 131 00:07:13,530 --> 00:07:16,500 If the condition is again through, then I will do some work again. 132 00:07:16,800 --> 00:07:20,810 Then I will update and then I will check the condition if the condition is false. 133 00:07:23,500 --> 00:07:25,790 Then I will exit or you can see. 134 00:07:26,120 --> 00:07:27,110 I will break my loop. 135 00:07:27,830 --> 00:07:28,730 Okay, great. 136 00:07:29,000 --> 00:07:32,270 Let us draw the flowchart for this problem using loops. 137 00:07:32,900 --> 00:07:34,310 So I will start my program. 138 00:07:36,210 --> 00:07:40,530 Then I will read two numbers, A and B. 139 00:07:42,260 --> 00:07:44,450 Now, the first part of Loop is to initialize. 140 00:07:44,780 --> 00:07:46,160 So I'm taking a variable. 141 00:07:46,520 --> 00:07:48,610 Let the name of the variable is a. 142 00:07:49,190 --> 00:07:51,890 So the variable AI is initialized to one. 143 00:07:53,120 --> 00:07:55,970 Now the next part of the loop is to check the condition. 144 00:07:56,690 --> 00:07:59,730 Sam checking is a list. 145 00:07:59,950 --> 00:08:00,860 Noriko's to five. 146 00:08:03,620 --> 00:08:06,140 So, yes, one is less than I did close to five. 147 00:08:06,770 --> 00:08:07,370 What will I do? 148 00:08:07,400 --> 00:08:08,510 The condition is true. 149 00:08:09,950 --> 00:08:11,750 Let's say I'm taking another variable. 150 00:08:12,230 --> 00:08:15,030 Dum dum equals a plus. 151 00:08:15,670 --> 00:08:16,970 I in two days. 152 00:08:19,150 --> 00:08:22,660 So the value of AI is one and time equals A plus D. 153 00:08:23,320 --> 00:08:24,100 Now what will I do? 154 00:08:24,130 --> 00:08:25,060 I will print them. 155 00:08:27,380 --> 00:08:32,290 So plus D will be printed after branding the them after doing the work. 156 00:08:32,350 --> 00:08:33,070 We will update. 157 00:08:33,490 --> 00:08:36,040 So I equals a plus one. 158 00:08:36,550 --> 00:08:38,200 And then I will check my condition again. 159 00:08:38,530 --> 00:08:41,890 So I equals I plus one means incremented the value if I buy one. 160 00:08:42,220 --> 00:08:48,580 Or you can see I equals I plus one means calculate this part and copy this part into this part. 161 00:08:49,330 --> 00:08:54,880 So first we really will read outages and will add the value of outages will go into Elitch's. 162 00:08:55,270 --> 00:08:57,790 So simply the value of I will increase by one. 163 00:08:57,820 --> 00:08:59,210 So this is the only way if I. 164 00:08:59,980 --> 00:09:01,690 And this will be new value. 165 00:09:03,100 --> 00:09:06,040 So a new value if I is two is to less than close to five. 166 00:09:06,190 --> 00:09:06,670 Yes. 167 00:09:07,150 --> 00:09:13,510 Through time equals plus truly printed them a plus truly incremental value if I went to the new value 168 00:09:13,510 --> 00:09:14,440 of a three. 169 00:09:14,980 --> 00:09:16,360 So it's three less than it goes to five. 170 00:09:16,460 --> 00:09:16,810 Yes. 171 00:09:17,110 --> 00:09:20,450 True democracy two duplicity gets printed. 172 00:09:20,860 --> 00:09:25,120 Similarly a plus for they will get printed as similarly a plus five will get printed. 173 00:09:25,180 --> 00:09:28,480 So the new elif I will become six is six less than it goes to five. 174 00:09:28,540 --> 00:09:29,530 So the condition is no. 175 00:09:30,950 --> 00:09:32,100 False, you can see false. 176 00:09:32,510 --> 00:09:36,480 So if the condition is false and I have rendered all their thumbs. 177 00:09:38,780 --> 00:09:41,510 My work is over now and I will end my program. 178 00:09:43,610 --> 00:09:47,270 And here you can see the loop on against this cycle. 179 00:09:48,110 --> 00:09:51,020 So this approach is way better than our previous approach. 180 00:09:51,320 --> 00:09:51,620 Why? 181 00:09:52,190 --> 00:09:57,020 Because if you want to print one million items, I only need to change just one thing. 182 00:09:57,380 --> 00:09:58,700 That is the condition. 183 00:09:59,880 --> 00:10:00,750 So what will I do? 184 00:10:01,290 --> 00:10:06,000 I will write her one million and one million items will be printed. 185 00:10:07,050 --> 00:10:08,640 So this approach is very efficient. 186 00:10:09,420 --> 00:10:10,380 Okay, great. 187 00:10:11,070 --> 00:10:14,910 So today we learned a new concept called Loop with the help of one problem. 188 00:10:15,240 --> 00:10:18,150 Do not worry if we are facing difficulty in understanding loops. 189 00:10:18,420 --> 00:10:19,920 This is completely normal. 190 00:10:20,120 --> 00:10:25,530 Initially, everyone faces difficulty in understanding loops and in fact, you should consider it in 191 00:10:25,530 --> 00:10:26,250 a positive way. 192 00:10:26,580 --> 00:10:31,590 It is a positive sign that you are learning new things which are challenging and difficult to understand. 193 00:10:32,700 --> 00:10:36,330 As far as I remember when I was learning about lubes. 194 00:10:36,780 --> 00:10:42,270 It took me nearly two days in understanding how I look and why we need loop. 195 00:10:43,080 --> 00:10:47,370 So if you understood just 30 percent of this lesson, you are way ahead of me. 196 00:10:48,090 --> 00:10:54,210 In the next class, we will be solving many questions based on loops because loops are very, very important 197 00:10:54,840 --> 00:10:57,180 and we will be using loops throughout this course. 198 00:10:57,720 --> 00:11:02,040 And I want to make sure that working off loops is crystal clear in your mind. 199 00:11:02,250 --> 00:11:05,450 So if you have any doubt, then first voice the next redo. 200 00:11:05,580 --> 00:11:09,030 And I am pretty sure that all of your doubts will be resolved. 201 00:11:09,660 --> 00:11:10,950 And if you still have doubts. 202 00:11:11,220 --> 00:11:12,270 Feel free to reach me. 203 00:11:12,420 --> 00:11:14,040 I will be more than happy to answer. 204 00:11:14,760 --> 00:11:16,390 So I hope you enjoyed Redistributor. 205 00:11:17,010 --> 00:11:18,420 I will see you in the next room today. 206 00:11:18,750 --> 00:11:21,740 Till then, enjoy C++ and thanks for watching.