1 00:00:03,610 --> 00:00:04,240 Hello, guys. 2 00:00:04,330 --> 00:00:05,490 Welcome back to the calls. 3 00:00:05,890 --> 00:00:10,820 So I felt that the last blast was a little bit boring as we only discussed tutee materials. 4 00:00:10,940 --> 00:00:12,430 Glass is going to be interesting. 5 00:00:12,790 --> 00:00:17,110 So today we'll learn more about flowchart and we'll solve a few problem. 6 00:00:17,620 --> 00:00:21,280 So we've already discussed in beef about flowchart in the last lesson. 7 00:00:21,550 --> 00:00:22,870 We will continue from that. 8 00:00:23,350 --> 00:00:26,260 OK, so what is a flowchart? 9 00:00:26,650 --> 00:00:36,820 So I have told you that it is a diagrammatic or you can see a pictorial representation of the steps 10 00:00:37,270 --> 00:00:42,760 that V for Lord to solve a problem. 11 00:00:44,020 --> 00:00:46,930 And we show these steps and boxes of various shapes. 12 00:00:47,970 --> 00:00:48,240 OK. 13 00:00:48,700 --> 00:00:51,930 So let us discuss about components of a flowchart. 14 00:00:53,020 --> 00:01:04,930 So if we have Overlordship, so it represent initialised or a Terminator example start, then we have 15 00:01:05,240 --> 00:01:06,290 belowground shape. 16 00:01:06,820 --> 00:01:12,100 So it represent input and output, input or output. 17 00:01:12,610 --> 00:01:14,350 For example, read. 18 00:01:14,590 --> 00:01:22,100 And then we have a rectangle shape and represent process. 19 00:01:22,770 --> 00:01:26,560 An example led I equals one. 20 00:01:28,450 --> 00:01:32,830 Then we have Diemen Chip represent a condition. 21 00:01:33,630 --> 00:01:35,410 You can see our decision. 22 00:01:36,640 --> 00:01:40,030 Let's talk about example is a good. 23 00:01:40,120 --> 00:01:40,720 Then do. 24 00:01:43,270 --> 00:01:45,250 Then we have arrows. 25 00:01:48,010 --> 00:01:55,660 And then we have connectors, so why are connectors used, for example, your flowchart is very big 26 00:01:55,720 --> 00:01:57,870 and it is not fitting in a single page. 27 00:01:58,150 --> 00:02:02,110 So with the help of Connectors, we can continue our flowchart from the next page. 28 00:02:02,710 --> 00:02:04,150 So I have a question for you. 29 00:02:04,450 --> 00:02:10,390 The question is, processa is running in both these cases, whether you are taking input or are giving 30 00:02:10,390 --> 00:02:16,000 output, audio output in something processor run in both these cases. 31 00:02:16,630 --> 00:02:18,730 So why I am having the friendship. 32 00:02:19,750 --> 00:02:20,950 The answer is very simple. 33 00:02:21,490 --> 00:02:24,400 This is known as reading process. 34 00:02:25,490 --> 00:02:31,370 We're doing process and this is known as active process. 35 00:02:32,150 --> 00:02:36,710 So in the vetting process, if the user is not getting their input, you can't proceed ahead. 36 00:02:37,160 --> 00:02:40,690 So in other words, we can say it depends upon use. 37 00:02:40,690 --> 00:02:43,880 It depends on user. 38 00:02:44,660 --> 00:02:49,970 And it doesn't depend on user. 39 00:02:50,300 --> 00:02:52,070 So that's why we have the friendship. 40 00:02:52,700 --> 00:02:54,080 OK, great. 41 00:02:55,790 --> 00:02:57,820 So that was all theory about flowchart. 42 00:02:58,130 --> 00:03:01,700 Now we will solve your problems to get a better understanding of flowchart. 43 00:03:03,390 --> 00:03:09,210 So problem number one, I read Principal I. 44 00:03:10,520 --> 00:03:15,500 Time and Brent, simple interest. 45 00:03:16,310 --> 00:03:17,930 We have to draw the flowchart for the same. 46 00:03:18,380 --> 00:03:20,160 OK, so let us draw the flowchart. 47 00:03:23,390 --> 00:03:25,790 So I will start by flowchart. 48 00:03:26,960 --> 00:03:31,640 Then I have to read three numbers B, R and D, principle rate and time. 49 00:03:32,240 --> 00:03:42,000 So read principal rate and time, B, R and D are variables in which I will store the value of principal 50 00:03:42,020 --> 00:03:43,910 rate and time given by user. 51 00:03:44,600 --> 00:03:52,680 Then I have to calculate the simple interest, which is it goes to B multiply are multiplied by D or 52 00:03:52,680 --> 00:03:53,720 divided by a hundred. 53 00:03:54,260 --> 00:03:58,370 Essay is also a variable which will store the value of simple interest. 54 00:03:58,880 --> 00:04:01,590 Then we have to print simple interest. 55 00:04:02,840 --> 00:04:04,570 So we have printed the simple interest. 56 00:04:04,850 --> 00:04:05,810 Our work is over. 57 00:04:06,170 --> 00:04:07,520 Now we will end our program. 58 00:04:07,880 --> 00:04:10,040 So and so. 59 00:04:10,040 --> 00:04:11,180 This will be the flowchart. 60 00:04:11,510 --> 00:04:13,040 So let us advise what we have done. 61 00:04:13,340 --> 00:04:18,380 So the question asked us to read, principal read and time and print simple interest. 62 00:04:19,130 --> 00:04:20,480 So we start our program. 63 00:04:20,930 --> 00:04:22,280 Then we read two numbers. 64 00:04:22,340 --> 00:04:23,480 Principal rate and time. 65 00:04:23,780 --> 00:04:29,120 B, R and D are three variables which will store the value of principal date and time given by user. 66 00:04:29,570 --> 00:04:34,100 Then calculating why simple interest using this formula, then printing my simple interest. 67 00:04:34,490 --> 00:04:36,650 Now, at this point of time, my work is over. 68 00:04:36,740 --> 00:04:38,090 So I'm ending my flowchart. 69 00:04:38,780 --> 00:04:39,020 Okay. 70 00:04:39,110 --> 00:04:39,860 So let us all. 71 00:04:39,950 --> 00:04:40,670 And the problem. 72 00:04:44,080 --> 00:04:45,250 So problem number two. 73 00:04:46,360 --> 00:04:48,610 So the question is, I have to read a five. 74 00:04:48,690 --> 00:04:51,970 No, I read five. 75 00:04:52,000 --> 00:04:52,350 No. 76 00:04:53,560 --> 00:04:59,690 And printed their average print, their average. 77 00:05:00,730 --> 00:05:02,800 So I have to draw the flowchart for the same. 78 00:05:03,520 --> 00:05:03,800 OK. 79 00:05:04,300 --> 00:05:05,350 So what will I do? 80 00:05:05,920 --> 00:05:07,780 First of all, I will change the color of my pen. 81 00:05:08,550 --> 00:05:10,390 And then I will start my program. 82 00:05:12,500 --> 00:05:12,700 OK. 83 00:05:12,810 --> 00:05:14,040 So I have to read five numbers. 84 00:05:14,220 --> 00:05:19,660 OK, read A, B, C, D, a.. 85 00:05:20,050 --> 00:05:22,470 Let ABC these are my five numbers. 86 00:05:23,280 --> 00:05:24,120 At ABC. 87 00:05:24,210 --> 00:05:27,270 ABC, the other variables that will store the value of five numbers. 88 00:05:27,480 --> 00:05:29,830 Then I will calculate my average using the formula. 89 00:05:30,660 --> 00:05:37,050 A plan B plus C plus D plus E and whole divided by five. 90 00:05:38,010 --> 00:05:39,600 So I have calculated my average. 91 00:05:39,750 --> 00:05:45,480 Now it's time to print the average print average. 92 00:05:46,050 --> 00:05:48,390 So at this point of time, my work goes over. 93 00:05:48,660 --> 00:05:49,360 Now I will. 94 00:05:49,620 --> 00:05:50,540 My flowchart. 95 00:05:52,020 --> 00:05:53,700 So let us revise what we have done. 96 00:05:54,000 --> 00:05:56,370 So the question was we have to read a five number. 97 00:05:56,400 --> 00:05:57,840 And we have to print the average. 98 00:05:58,230 --> 00:05:59,370 So I start my program. 99 00:05:59,670 --> 00:06:00,770 I read five numbers. 100 00:06:00,870 --> 00:06:01,930 ABC, the E! 101 00:06:02,130 --> 00:06:04,320 And then I calculated my average averages. 102 00:06:04,400 --> 00:06:08,310 Also variable here that is storing the value of average than printing average. 103 00:06:08,390 --> 00:06:09,870 Then I'm ending way program. 104 00:06:10,590 --> 00:06:11,580 Okay, great. 105 00:06:12,450 --> 00:06:14,980 So let us discuss the last probably of this lesson. 106 00:06:15,690 --> 00:06:17,310 So problem number three. 107 00:06:18,780 --> 00:06:25,770 So the problem statement is we have to print largest off three numbers given by user. 108 00:06:27,130 --> 00:06:28,390 So let us know that flowchart. 109 00:06:30,890 --> 00:06:32,410 So I will start my flow chart. 110 00:06:33,780 --> 00:06:35,340 Then I have to read the tea numbers. 111 00:06:35,940 --> 00:06:37,860 Let ABC be the tea. 112 00:06:37,860 --> 00:06:41,010 No lead A, B and C.. 113 00:06:41,920 --> 00:06:42,200 OK. 114 00:06:44,310 --> 00:06:45,570 So first time checking. 115 00:06:46,870 --> 00:06:50,670 Is eager to then be and eager to Danzy. 116 00:06:51,430 --> 00:06:56,560 So there are two cases, either this condition will be true or this condition will be false. 117 00:06:56,980 --> 00:07:01,440 If this condition is true, that means is the largest number. 118 00:07:01,960 --> 00:07:02,190 OK. 119 00:07:02,290 --> 00:07:03,100 So I will brentley. 120 00:07:04,730 --> 00:07:05,290 Brent A. 121 00:07:08,710 --> 00:07:12,760 Now, the second situation can be this condition is false. 122 00:07:13,150 --> 00:07:15,700 That means it is not the largest number. 123 00:07:16,300 --> 00:07:19,690 Will check for B is bigger than A. 124 00:07:21,230 --> 00:07:23,180 And bigger than see again. 125 00:07:23,800 --> 00:07:28,000 There are two cases in this conditional withdrawal or this condition will be false. 126 00:07:28,400 --> 00:07:32,540 If this condition is true, that means B is the largest number. 127 00:07:32,570 --> 00:07:33,470 So I will print to be. 128 00:07:35,880 --> 00:07:38,660 And the second situation can be this condition is false. 129 00:07:39,680 --> 00:07:41,630 That means B is not the largest number. 130 00:07:41,990 --> 00:07:45,140 So at this point of time is not the largest number. 131 00:07:45,540 --> 00:07:47,090 B is not the largest number. 132 00:07:47,930 --> 00:07:50,960 That means C is the largest number. 133 00:07:51,320 --> 00:07:54,170 OK, so make Pentagram shape because we are printing. 134 00:07:56,260 --> 00:07:56,520 OK. 135 00:07:57,100 --> 00:08:02,560 So it is not the largest number being not the largest number, and that means seas, the largest number. 136 00:08:03,070 --> 00:08:05,460 So we have done what the question asks us to do now. 137 00:08:05,830 --> 00:08:06,590 And our program. 138 00:08:06,740 --> 00:08:06,940 So. 139 00:08:06,940 --> 00:08:07,300 And. 140 00:08:09,090 --> 00:08:12,600 Similarly, after printing, we we have to end our program. 141 00:08:13,110 --> 00:08:14,580 And similarly, after printing. 142 00:08:15,240 --> 00:08:17,260 We have to end our program. 143 00:08:17,460 --> 00:08:18,990 So let us revise what we have done. 144 00:08:19,440 --> 00:08:23,130 So the question was, we have to bring the largest of three numbers. 145 00:08:23,520 --> 00:08:30,570 So I start my program item three, number A, B and C word that ABC, ABC are three variables that will 146 00:08:30,570 --> 00:08:32,000 store the value of T number. 147 00:08:32,490 --> 00:08:32,770 Okay. 148 00:08:33,270 --> 00:08:34,380 So first time checking. 149 00:08:34,530 --> 00:08:39,810 So first of all, I check is eager then B, if this condition is true then it means ethologist numbers. 150 00:08:39,810 --> 00:08:40,470 I am printing. 151 00:08:40,650 --> 00:08:42,120 And then I'm ending my program. 152 00:08:42,690 --> 00:08:44,400 If this is not true, that means it is not. 153 00:08:44,400 --> 00:08:49,530 The largest number that I am checking for me is B the largest number in this condition will be true 154 00:08:49,620 --> 00:08:50,940 or this condition will be false. 155 00:08:51,000 --> 00:08:54,150 If this condition is true, I am printing B and ending my program. 156 00:08:54,750 --> 00:08:56,190 Whatever the condition is false. 157 00:08:56,650 --> 00:09:01,530 If this condition is false, I will only reach here if it is not the largest number. 158 00:09:01,620 --> 00:09:02,390 B is not the largest. 159 00:09:02,390 --> 00:09:04,320 Just no automatically means. 160 00:09:04,440 --> 00:09:05,440 C is the largest number. 161 00:09:05,490 --> 00:09:08,070 So I am printing C and then I'm ending my program. 162 00:09:08,550 --> 00:09:10,310 So we solve three problems truly. 163 00:09:10,890 --> 00:09:14,610 If you have any doubt, you can ask me that you in this section in the next class. 164 00:09:14,640 --> 00:09:18,390 We will continue flowchart and learn new concept with the help of your problems. 165 00:09:18,780 --> 00:09:20,310 I hope you enjoyed this story. 166 00:09:20,700 --> 00:09:21,790 I will see you in the next material. 167 00:09:22,080 --> 00:09:23,760 I will then enjoy C++. 168 00:09:24,090 --> 00:09:24,870 Thanks for watching.