1
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OK, that was really difficult, but we have done it, we have calculated the electric field and the

2
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magnetic field for our Hatzius Dipole, so let's go ahead and discuss the results.

3
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So what we had considered is a time dependent current in an infinitesimally small wire.

4
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So basically we have here a tiny segment of an antenna and our results where this be field with the

5
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two terms and the electric field with these six terms here.

6
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And in both cases, we still have our -- time argument, which comes, of course, from the --

7
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potentials.

8
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So first of all, we can do something very simple.

9
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We can check if this result is equal to our results from electrostatic, where we have considered the,

10
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you know, the static dipole.

11
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And this we can do by considering considering a time independent dipole moment.

12
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So this means that pitot a zero and also P is zero.

13
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So this means we get a magnetic field of zero, which is, of course, clear because we have yeah,

14
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we have static electric charges and we just got an electric field with these two terms.

15
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And when we compare it to our previous results from Electrostatic, we see it's exactly the same result.

16
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That's really satisfying.

17
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I think because we had this difficult calculation.

18
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We have first had this difficult lecture on proving that the -- potentials are right.

19
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Then we had the difficult lecture on calculating the electric field and it turns out that's in the limit

20
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of time, independent type of moments.

21
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We get the same result as previously, which means we did a good job.

22
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And that is correct.

23
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But now, of course, our aim was not to calculate time independent problems, because then we could

24
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have done it in a much more simple way.

25
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Instead, we want to calculate time dependent on, for example, harmonically oscillating dipoles.

26
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And so what we can assume here is some some cosine dependence on the time or as you would typically

27
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do it, you write it down in terms of an exponential function with an imaginary argument.

28
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So you have your electric dipole moment at the time, zero, and then it oscillates and thus you do

29
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by multiplying such an E to the eye on McAtee, where Armacost the frequency of the oscillation.

30
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Now you can go ahead and calculate p dot and people dot dot is just minus eight times, oh my God,

31
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times this whole function and then for people that you do it one more time, so you get plus I square

32
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Iomega which plus square Omega's Square, which is of course minus Omega Square Times Pete.

33
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And now we can go ahead and take these and put them into B and E.

34
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So when we start with B what we get is the following we gets here is P in both cases and then of course

35
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here the different prefectures and you can see we have all we got of a C, and this is typically something

36
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that you introduce as a as the K vector, which is which was for example, for an electromagnetic wave,

37
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the so-called wave factor.

38
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Now what we must also consider is that we have in both cases here our P, which was P zero times E to

39
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the Omega T, but it's also really important to remember that this T argument is, in fact, not simply

40
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our T, but it's also has to take into account the retardation.

41
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So we have to write instead of t t minus are divided by C.

42
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So we get here I omega T minus, I only got T plus I Omega are divided by sea and this is our K.R. minus

43
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Omega T and this is something that you already know from our electromagnetic waves.

44
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So in some sense we get to hear again an electromagnetic wave, but it has some difficult space dependence

45
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and some difficult.

46
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Now, one other thing that you can do is you can introduce the wavelength of this of this wave.

47
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And this is just, you know, two pi, one of akei or vice versa as it's written down here.

48
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And what I have done here is I have ordered these terms with respect to their power.

49
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In a SO later, we can discuss the near field and the far field.

50
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So here we get as our sold for B that we have some unit vector along R and then the cross products of

51
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these terms and the vectorial orientation is along P0.

52
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All right, so we have the results for B, let's do the same thing for E!

53
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So here what we can can do or what we must do is we must take P dot and P double dots and put it in.

54
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So in all cases we get no P and we get these three factors here.

55
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So this is what we get here.

56
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You get the term four for these two, you get a term for these two.

57
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And here this one is for these two and you can see the prefectures minus I omegle divided by C and minus

58
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Omega squared, divided by C squared, because here we have C Square, here we have C, here we have

59
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nothing.

60
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All right, so now we once again take this expression for.

61
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So we get P0 in all cases.

62
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So yeah, this one also has to be p0 in fact, and then we pull out this exponential function and also

63
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have to consider the -- argument.

64
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So this is what we what we get, we get.

65
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Yeah, OK, we get the same thing as here, so nothing has really changed, but the only thing that

66
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I have changed is this term here, because this one looks exactly like this double, double, double

67
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vector product where we used to be a C minus C, a B rule.

68
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So we can write this one down as this one.

69
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So to make it just a bit more look more simple and a bit more beautiful, but it's actually not really

70
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that important, to be honest.

71
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OK, now we are almost done, the only thing that I want to do is I want to order these terms with respect

72
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to their powers and are just in the same way as we did for the magnetic field.

73
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So this means we have to replace all of these actors are with the unit, Victor E. R. and have to pull

74
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the legs are out of this vector.

75
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So what we get is we get basically the same thing, but we have pulled out the the RCA everywhere and

76
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have canceled them with our to the power of five.

77
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So now we got here on the R to the power of three because here we have these two hours, here we have

78
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these two hours and then the similar thing we can do for the other terms here.

79
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So we finally have arrived at the results for a harmonically oscillating electric dipole.

80
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And we have also ordered our terms with respect to the powers of R.

81
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So what this means is in the very close vicinity to our antenna, we have terms that are dominating

82
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which are these ones here.

83
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So it's just a single term.

84
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This is because for for, you know, in the vicinity we have an R that is very small.

85
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So this means that one of our to the power of free will be very large compared to these other two terms

86
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and also to these two terms.

87
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And then far away we have a small R, so this means here to terms with the power, um, our to the minus

88
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one, they dominate with respect to all of the other terms.

89
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So this means here we will mainly get these two terms.

90
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So what does it mean.

91
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So in the near field, alien blue, what we get is that the electric field dominates because the electric

92
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field is dominated by this term.

93
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And this is much larger than this term of the magnetic field, because here we have our to the power

94
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of two instead of three.

95
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And it also means that the electric field in the near field is rather similar to our dipole from electrostatic

96
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so that you can see here.

97
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So along the Z axis, we get a field profile that is pointing along the radio direction.

98
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So in this case, Homsi and especially close to the x y plane, we get a field that is pointing along

99
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this Edyta direction, which is here along this one.

100
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So in the near field, it looks rather similar to what we already know, and this is why you could also

101
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call it a very slowly oscillating dipole in the near field.

102
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Now, in the far field, it looks very different because here we have these two terms to dominate.

103
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And you can also or you can immediately see that in the far field, the electric field is perpendicular

104
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to the electric field.

105
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And also you can see that the electric field, as large as near the x y plane is because of this triple

106
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vector product here.

107
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And in the X Y plane, once again, like here, the electric field is pointing along the etha to the

108
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direction.

109
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The magnetic field is also largest near the XY plane, but it's pointing along the fire direction,

110
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as is indicated here.

111
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So this means in the far field, the majority of the energy is transmitted near or close to the X Y

112
00:10:14,700 --> 00:10:22,440
plane, and it turns out that the data point in Vector s, which is essentially a prefect at times to

113
00:10:22,440 --> 00:10:29,580
vector product of E and B, is pointing along the radial direction because the product of Edyta and

114
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if you feel if I is E r, which is to radial vector.

115
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So this means all of the energy is transferred along the radial direction close to the x y plane.
