1
00:00:00,120 --> 00:00:06,650
All right, so let us continue by calculating the force and to talk acting on a magnetic dipole.

2
00:00:08,190 --> 00:00:14,370
So please remember what happened for the electric dipole moment when we applied a constant electric

3
00:00:14,370 --> 00:00:14,760
field.

4
00:00:15,480 --> 00:00:22,050
So if this electric dipole was misaligned, we got two individual forces that compensated on average,

5
00:00:22,200 --> 00:00:29,910
but they allowed to reorient the electric dipole so that this dipole aligns with the constant electric

6
00:00:29,910 --> 00:00:30,300
field.

7
00:00:31,080 --> 00:00:35,490
And we had also derive the equations for this torque and for this force.

8
00:00:35,970 --> 00:00:40,830
And you could see when we have a constant electric field, then this gradient is zero, which is why

9
00:00:40,830 --> 00:00:42,080
the force is absent.

10
00:00:43,590 --> 00:00:47,600
Now, something very similar happens for the magnetic dipole moment.

11
00:00:47,970 --> 00:00:55,350
But first of all, we have to understand, we have to remind ourselves how the magnetic dipole moment

12
00:00:55,500 --> 00:00:56,490
is generated.

13
00:00:57,210 --> 00:01:03,780
And in the previous section, we have derived this magnetic dipole moment where we have considered a

14
00:01:03,780 --> 00:01:04,610
current loop.

15
00:01:04,830 --> 00:01:07,230
So we have circulating electrons.

16
00:01:07,260 --> 00:01:10,320
You see here in this plane, these electrons circulate.

17
00:01:10,330 --> 00:01:12,270
So there's a current circular current.

18
00:01:12,690 --> 00:01:20,070
And this magnetic dipole moment is given by the perpendicular vector that stands on this plane here.

19
00:01:20,280 --> 00:01:21,390
So by this vector and.

20
00:01:23,420 --> 00:01:30,620
So when we have these circulating electrons, you can see that, yeah, the electron itself is moving

21
00:01:30,620 --> 00:01:37,370
here along these directions and also T is always tangential to this to this circle here and here.

22
00:01:37,370 --> 00:01:39,270
It's pointing along the opposite direction.

23
00:01:39,650 --> 00:01:44,740
In fact, it's different for every every possible position on the edge of this disk here.

24
00:01:45,050 --> 00:01:51,320
But for simplicity, I will just discuss these two cases here and now since we have a moving charge.

25
00:01:51,710 --> 00:01:56,120
There is, of course, the Lawrence force because we also have this magnetic field everywhere.

26
00:01:57,350 --> 00:02:02,630
And if you think about it, the forces that will act on these electrons look like this.

27
00:02:03,350 --> 00:02:06,760
So this means they rotate this whole disc.

28
00:02:06,770 --> 00:02:11,870
So the trajectory of the electron or the current trajectory will be rotated.

29
00:02:12,470 --> 00:02:19,250
And therefore also this normal vector here will be rotated so that it aligns with the magnetic field.

30
00:02:19,760 --> 00:02:26,810
So this means like in the electric case, also here, the magnetic dipole moment aligns with this static,

31
00:02:26,990 --> 00:02:28,730
homogeneous magnetic field.

32
00:02:29,870 --> 00:02:35,900
And the equations that allow to describe this are also very similar compared to electrostatic.

33
00:02:36,560 --> 00:02:41,840
So it's just that we have to replace the electric dipole moment with the magnetic dipole moment.

34
00:02:42,770 --> 00:02:48,710
However, the derivation of these equations is a bit difficult, but also I think it's a bit of a bit

35
00:02:48,710 --> 00:02:52,850
boring because we know already that the same thing will happen as for electrostatic.

36
00:02:53,240 --> 00:02:55,100
So I will not go through this here.

37
00:02:55,610 --> 00:02:59,870
But as a hint, if you want to do it yourself, you have to consider the Lorentz force.
