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So in this lecture, we will introduce to Victor potential, which is somewhat similar to the electrostatic

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potential, and also we will derive an equation for the vector potential, which is a bit similar to

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the song equation from Electrostatic.

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So first, let us consider a quick recap of the electrostatic potential in electrostatic.

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So there we have considered this Maxwell equation where the rotation of the electric field is zero.

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And this led us to the possibility to introduce this electrostatic potential, because when we have

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the rotation of a gradient, this is always zero.

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So since we have this Maxwell equation here, this means that we will always have the possibility to

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express this electric field in terms of a gradient of some function.

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And also we could immediately understand that this electrostatic potential fire has certain properties.

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For example, we could add any possible constant without changing the physics.

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So this means that the electrostatic potential cannot really be a measurable quantity.

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But only differences in the electrostatic potential can be measured and the gradient can be measured

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because this is the electric field.

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Now, in Agneta Static's, we have the Maxwell equation that the divergence of the magnetic field is

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zero and not the rotation.

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So this again allows us to introduce a new potential, which we call the vector potential.

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And it has the probability that it's now are or the magnetic field has not a property, that it's the

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rotation of this vector potential, because this time we have the divergence of a rotation of a vector.

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And this identity is always zero for every vector.

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So it's the same logic, just like in a different order.

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So we know that the divergence of the magnetic field is zero.

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This means we must have the possibility to express the magnetic field in terms of a rotation of some

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other vector field.

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Now, since this magnetic field is expressed as the rotation of a this Eigg has no special properties,

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one of them is that the vector potentially can be shifted by any gradient of a function so we can introduce

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a new vector potential and it's the old vector potential plus the gradient of some function.

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And this function can even depend on the position vector.

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And while this means we have two different vector potentials, they will both give rise to the same

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magnetic field, which you can see in this quick calculation, because here we will get the idea, the

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rotation of A and then the other term, which is related to this one here.

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So we have to rotation of the gradient of chi.

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And so the rotation of a gradient of a circular function is always zero.

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So this means this B is equal to the old B.

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So again, this means that this vector potential, just like the electrostatic potential, is not really

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a measurable quantity.

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It's more that the rotation of this quantity can be measured because this is the magnetic field.

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Now we have again, like an electrostatic the possibility to tackle our problems in a different way,

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so instead of directly calculating it or B, we can first calculate fine or A and then from these properties

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can calculate B and by the gradient or by the rotation, respectively.

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Now, what what other advantage does it have to introduce such a vector potential?

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So we have introduced this vector potential and we can now use the other next equation.

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So here we have the rotation of the magnetic field is basically determined by the currents or by the

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current density of our.

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So this means if we take this relation here and put it in, we have the rotation of the rotation of

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A is equal to zero times J of our.

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Now we can use an identity, so that's really something you should practice yourself and please be warned,

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it's kind of difficult to show.

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So you should go ahead and consider all of the three components individually.

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Best would be you take the left hand side, write down what it is, you take the right hand side.

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So first this term, then this term and write down what it is.

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And then you will see that both of these sides are equal.

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So you will see that the rotation of the rotation of any vector must not be the vector.

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Potential can be really any vector that is are dependent is equal to the gradient of the divergence

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of the same vector minus the lab class operator acting on the vector and know something kind of difficult

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will happen.

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Or we will have to.

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Yeah.

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Do something difficult or something unintuitive.

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So I have already told you that this vector potentially can be shifted by any gradient of a function.

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So this means we can take our old vector potential and add gradient of some function which will give

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us a new vector potential.

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And we are allowed to do this because this does not change to physics, because this does not change

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the magnetic field.

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B And in particular, this means we always have the chance to choose a gauge.

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So it shows a gradient of chi in the way that the divergence of eight is zero.

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So maybe you can think of it like this.

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You first of all, calculate some vector potential A that fulfils this relation so that its rotation

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is the magnetic field.

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But then you figure out, OK, it's divergence is not zero.

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So what do you do then is you choose a function chi whose gradient is exactly the minus sign of this

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divergence of a and so your new AI has a divergence of zero.

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So that's something that's, as I mentioned, is a bit unintuitive.

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It's just a very clever trick.

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So it's not something to be worried about because probably the first physicist who has ever done it

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took many days or even weeks or month to figure this out.

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It's very it's really a very clever trick that we are using now.

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So we take our freedom to gauge our vector potential, to gauge it in such a way that the divergence

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of A is zero.

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So we are allowed to do this.

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But why should we do this?

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The answer is we do this because then this term here becomes zero.

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So this means this rotation of the rotation of A is then just minus the plus operator acting on a so

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we can write, mindful of how separate of A is equal to this one, or we write it like this.

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And now if you remember the same equation from electrostatic, this equation looks kind of similar.

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So here we had the lipless operator acting on five is equal to minus a constant times row of R.

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So it's basically the same thing, just a different constant and it's a vector equation.

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So here we have three components of this equation and here we have a scalar differential equation.

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So what we can do now is we can solve the equation for every individual component and the solution will

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look just like the solution for the equation.

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So we can take all of our results from electrostatic and carry it over to Manado Static's.

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So that's really the reason why we have considered this difficult looking trick here, where we have

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chosen a gauge such that the divergence of eight is zero.

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So here all the magic happens because this allows us to simplify our.

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Yeah, our differential equation for a in such a way that it looks like the differential equation for

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the electrostatic potential, and this allows us to carry over all of the old results.

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So one more comment before I continue with the next lecture is that it's not necessary to do this trick.

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We do not have to use a gauge so that the divergence of A is zero.

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But if we don't do this, we will get this additional term here that also would appear here in this

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equation.

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So if we do not choose such a very clever gauge, then our differential equation for a looks more difficult

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and then it would be more difficult to solve it because then we would have to start again from scratch

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and we could not carry over our old results from electrostatic.

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And this is why I've considered it here so that we now know the solutions from our previous calculations.
