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So let us now analyze the solution from the previous lecture in more detail, what we will establish

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here is the dispersion of relation.

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We will be able to relate these quantities, Omega and Kate, that I've introduced into previous lecture.

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And also in this lecture, we will talk briefly about WAF packet's.

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So the solution from the previous lecture was that the electric field and the magnetic field are both

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electromagnetic waves.

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So these are exponential functions with imaginary arguments and we have a fluctuation in time t and

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in the coordinate R and these equations where the solution of this differential equation here.

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So this is the wave equation for E and the wave equation for P.

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So what we must do to determine the relation of Omega and K, we must just take this equation, the

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solution here and put it into the equation.

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So what I've done is I've just given you the solution and basically we made an ANZAAS that solves this

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equation.

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So now let's check if it is really a proper solution.

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And also we will be able to determine these coefficients.

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So let's take this equation for E!

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And put it into this wave equation for E, what we will get is from this term we will get one over C

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Square.

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And then we have here the second derivative with respect to time, this gives us a square and omega's

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square.

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And then, of course, E zero times E to the I and so on.

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So this is this term here multiplied by this.

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And also we must of course, calculate here it is not class operator.

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So once again, it's maybe more easily to go to one dimension where this lipless operator just becomes

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the second derivative of respect to, let's say, X, and then we have here K times X.

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So what we will get as the the river Tife will get minus I times K Square.

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So this is this one here and then of course the whole term here, which stays because when you differentiate

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in the exponential function it will just stay the exponential function.

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So this is the what we get when we take this term and put it into the wave equation.

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And we know that this must be equal to zero.

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So we can just divide by this term here.

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And we now know that this bracket here must be equal to zero.

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Most of what you will see is you can also take the solution for B, put it in here and you will get

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a very similar relation where you can divide by zero times as exponential function.

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So you will get the very same relation we get.

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In both cases that I Omega's square of a C Square is equal to this term here, minus K Square.

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So of course we know what I square is.

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It is minus one.

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So let's simplify all of these minus signs here so we get minus a square of a C square and here we get

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a plus sign because here we have a minus and then we get another minus from the square.

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So we know that Omega is equal to plus or minus C times K, so Y plus or minus because we have this

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square here.

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So this is the dispersion relation of the electromagnetic wave.

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And as it turns out, we know that C is the velocity of light and we can interpret K as a wave vector.

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So this is like the two pi over the wavelength of the electromagnetic wave and we have Omega, which

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is essentially two pi over the period of this fluctuation of the electromagnetic wave.

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So we have the frequency that is linearly related to the wave factor and this proportionality constant

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here is the velocity of light.

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And also we know that we get a positive and a negative sign here.

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So it means that also we can write it in a different way.

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We can write down that K is equal to plus minus Omega oversea.

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So it means that the key vector can be oriented along two different directions, you could say.

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So it means the wave can propagate forwards and backwards.

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And in fact, this relation here is not restricted to only fixed.

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Constant is C, but you can just scale Omega and you can scale K.

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So when you take some, for example, light from the sun and you analyse it, you will see that for

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every portion of this light.

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So to see you, this relation is true.

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Omega is always linearly related to the way Vector K, but the light consists of many, many waves that

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all have different frequencies and have different weigh factors.

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These are the different colors of light.

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So for example, red light has different by a factor than blue light.

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And also they have different frequencies.

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But of course they always have the same velocity.

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But what this means is that the most general solution of the wave equation is not just a single wave,

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as I've written down here, but it's superposition of many waves.

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So let's take these waves here, which are, for example, for electric field zero times this exponential

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function and and add them up for different characters.

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And this is what I have done here, so adding up different characters since K is a is not a discrete

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quantity, but a continuous quantity.

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It's not a sum, but it's an integral part.

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We well, we do not add up different waves, but where we integrate over these waves with respect to

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K and then we have here another function which tells us by which amount the different waves with a different

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way factors contribute to our total wave.

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So in general, the light is a wave packet's that is the superposition of many different individual

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waves that are characterized by one particular K vector and by one particular frequency Omega.

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And this distribution function or test is a weight function, F of K can be considered the full year

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transform of this function here.

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So what is what this means is that when you know the different contributions in the way of packages,

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for example, you know that when you analyze light from the sun and tells you it consists to five percent

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out of light with a way effect or K one and five percent out of line with the character K two and so

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on, then you know exactly what your total wave looks like.

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So the information about this distribution function is sufficient for knowing the whole function because

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it is just a different representation.

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It is the four year transform of this function here.

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Now we know about this person relation of light and also about WAF packet's, so please don't worry

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if this last part was a bit too theoretical for you in the next lecture, things will become more simple

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again.

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And I want to show you what an electromagnetic wave looks like and how the wave vector K is oriented

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with respect to E and also to be.
