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Let us start a section by driving the wave equation, so in the previous section, we have introduced

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the Maxwells equation and now we want to consider these equations in a vacuum.

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So what does that mean?

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Vacuum means we have no charges and no currents.

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So both of these quantities will be zero.

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So what you can see will happen is there is some kind of symmetry in the electric and magnetic fields

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because now both the divergence of E and the divergence of B will be zero and the rotation of E will

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be proportional to the time derivative of B and vice versa, because this term is zero and this term

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is zero.

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So we have these four Maxwell equations.

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And also something I will introduce in the following is the speed of light, which is actually this

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factor here, the square root and then the power of minus one.

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So let's take our whiteboard here and I want to show you how we can derive the wave equation for E and

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also for B based on these maximal equations.

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So let us take this maximal equation here.

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The rotation of E is equal to the time derivative of B and A minus sign.

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So this is what is written here and here.

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So of course what we can do is we can multiply a KNOBLER operator from the left using a vector product

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and the equation is still true.

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So we have the rotation of the rotation of E is equal to the rotation of minus the time derivative of

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B, so we can now do is we can switch around these two derivatives.

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Is something you can basically always do if you here you have the derivative with respect to the coordinates

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and to you with respect to the time.

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So these are independent properties coordinates.

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So you can switch around these derivatives so we can write down that this is equal to minus the time

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derivative of the rotation of B.

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Now you can see here we have the rotation of B so we can take the second Maxwell equation.

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The rotation of B is equal to this prefectly here, which is equal to one of the C Square.

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And then we have the time derivative of E.

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And since we have here already another time derivative, this is equal to the second derivative of E

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with respect to the time.

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OK, so here you can see I have still these three factors, and here I have introduced a velocity of

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light.

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So we have here an equation.

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The rotation of the rotation of E is equal to minus one of a C square and then the second derivative

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of E with respect to time.

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Now, this is almost the Maxwell equation, sorry, almost a wave equation, but we need one more thing.

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We need to transform this first term here and here.

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We use something, some relation using these Nabala operators, which is true for every vector field.

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So this is not a particular relation for E, but it is true for every vector.

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So the rotation of the rotation can be expressed as this gradient of the divergence minus a dollar plus

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operator of each.

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So if you don't believe me, write down this equation in all of the coordinates, X, Y and Z, and

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then you will see that you can transform it to this expression here now.

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So so far, this is true for every week, as I said, and now we use a special property of the electric

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field.

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So here you can see we have the divergence of E and we know from the Maxwell's equations that the virgins

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of E is zero.

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So we are left only with this term here.

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And this is something where it's really important that we consider vacuum, because if we would not

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be in a vacuum, then this term you would not be equal to zero, because then we would have here a term

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proportional to the charged density.

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And then this whole derivation of the WAF equation would not be true.

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But since we consider here a vacuum, we have now that this term is equal to that one here and also

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it is equal to minus the plus operator of E!

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So we can write down this term is equal to this term.

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So this is our wave equation.

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Now, to find a solution, it's most easy to use only a one dimensional problem, so then this class

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operator here becomes just the second derivative with respect to the coordinate, let's say X.

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So we have here one of a C squared, the second derivative of E with respect to time, minus the second

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privative of E with respect to the coordinate, X is equal to zero and now we can guess the solution.

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So the solution will be some cosine or sine function or more general and exponential function with an

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imaginary argument here.

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So the solution is some vector is zero times this exponential function e to the power of AI and then

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here we have omega T minus the scale of product of a vector K and a vector.

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So in the following we will learn what these quantities Omega and K are.

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But so far they are just coefficients.

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So if we calculate the second derivatives, you will see that since this is here in E function and an

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exponential function, this exponential function will remain and we will just get the derivative.

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So for this term here, we will get a square which is minus one, and then we will have Omega Square.

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And for this term here we get a square and then we get K Square.

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And as I mentioned in the following, we will relate Omega and K to see and then we will understand

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what Omega and K are.

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But as you can see, this is an exponential function within an imaginary argument.

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So the real part, as you probably know, is then a cosine function and it is fluctuating in time and

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it is fluctuating in the coordinated R, so it is a wave and this is an electromagnetic wave.

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And as it turns out, this is light because we are now in a vacuum, which means we have no charges,

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we have no currents.

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So this is the assumption that we put into these maximal equations here.

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So the only thing that we can have is light, because light is not a charge and is not a current.

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It's just photons and it's just some excitation in forms in terms of an electromagnetic wave.

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So this is the wave equation for light in vacuum and this is the solution for the electric field.

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Next, we want to find the same equation and a similar solution for the magnetic field.

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And this is actually a nice exercise for you to see if you really understood what we did on the previous

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slide.

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So I think it would be best if you would pause the video now and take a sheet of paper and a pen and

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write down a very similar derivation of the wave equation for beep.

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But of course, I will now show you also the solution.

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So what you have to do is you once again have to consider here this Maxwell equation.

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So we have the rotation of P is essentially you the time derivative of E with some perfecta.

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So we have this one here.

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And once again we can switch around these two derivatives, which I have done here.

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And now we see that this is the rotation of E, which is essentially the time derivative of be so we

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can get another time derivative.

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And here the vector field of work, the field of B.

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So this is the first term that we want to have.

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And now the second term.

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First of all, we use this vector identity, which gives us these two terms here.

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And then we see that we have here the divergence of B, which is zero, which is true generally not

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only in vacuum.

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So we have that these two terms here are equal.

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And this gives us the wave equation for B, which looks exactly the same as for E, and therefore our

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solution will be the same.

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But to please note that B zero can still be a different vector to e0.

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But like the electric field, also the magnetic field is an electromagnetic wave.

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It fluctuates in time and in the coordinates.

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And then the following section we will determine the dispersion relation.

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And I want to show you what Omega means and what K means.
