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So far, we have talked about charges, Curran's fields and forces and the previous lecture, but one

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thing is missing, it's the energy because typically, for example, the classical mechanics, you can

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also solve physical problems using energy equations.

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For example, you can apply energy conservation laws where you transform potential energy into kinetic

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energy.

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So this is something we can also do for electrodynamics.

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And for this, we also need to Loren's force.

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So this is why I introduced it in the previous lecture.

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And once again, I really hope I did not confuse you too much.

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What I want to tell you is that the physicists in the 19th century could not derive this Lawrence force,

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but still used it.

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And this is how we want to handle the things in this course as well.

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We just want to use it here.

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So what we want to calculate here is energies and quantities that are related to energies, for example,

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to power, which is the energy generation or consumption over time.

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So the consumption rate.

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So this power W is equal to E of a T, as I just mentioned.

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And you can tell if you if you say the energy or the work that you need to apply is equal to the force

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times distance, then this becomes minus to four times the velocity.

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For example, consider such a geometry here when you want to pull some mass up a mountain.

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Then there were the power that you that you ordered, the energy that you consume.

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So that's the power which tells us the energy per second, for example, is equal to the force, so

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is proportional to the mass times, the velocity with which you are pulling.

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So if you are pulling faster than you require more power and if you're poor slower, then it's less

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power.

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Now, in our case, the force is the of course, the Lawrence force.

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So we have the power is equal to the negative charge of the particle times, the electric field, plus

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this vector product here.

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And then we have another velocity term.

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And now what's really interesting is we have two terms here.

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First one is minus cubed times.

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He taught V, but then we have another term which is proportional to the vector product of three times

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B and then scalar product with B.

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Now what happens here is that this or every every vector product of two vectors is always perpendicular

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to both of these vectors.

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So V times B is perpendicular to V, but when we then calculate the scalar product, we have to scale

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our product of two perpendicular vectors, which always is zero.

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So the second term does not contribute to the power and this is well known the power that there is no

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power consumption from magnetic fields.

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So we only need to consider the electric field contribution.

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Now, another quantity that we can introduce is the power density.

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This is our power minus Q e.V., but it's normalized to some volume.

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So it's we can also say it's the charge over the volume.

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So this is just a charge density.

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And now we have for you to charge density times the velocity.

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This is equal to a current density.

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So our power density, which is you could say the energy generation density is equal to minus the current

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density dot the electric field because it's a quantity that we will need in the following.

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Now, what I will do is I will once again consider a Maxwell equation, this time we take the equation

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that considers the rotation of the magnetic field is equal to this is actually a partial derivative

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of the electric field with respect to time.

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And then we have the currents as well.

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So the current itself is equal to these two terms.

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So I have just taken this turn, put it on the other side and you get something like this.

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Now, what we can do is we can multiply with a scale of product from the right hand side, so we multiply

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by the electric field.

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So we do it also on the right hand side, so here I have written this down and a bit of a different

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way.

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So the first term Epsilon zero idot times E can be written down like this to please follow along and

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see that this is really true.

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So what we have to do is we have to calculate a time derivative of each square.

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So what does that give us?

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It gives us two times E but don't forget the inner derivative gives us two times E times the time derivative

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of E, so it gives us in total Epsilon zero over two times, two times E times e dot.

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So absolute zero times.

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Eight times.

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So that's really the first term.

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Now, in the second term, we have this novela operator, which is basically the vector of partial derivatives,

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acting on B in terms of a rotation, but also it will act on it.

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So we have to apply we can apply a product rule.

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So what we can do is we can write this down in terms of two terms.

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So this is a bit more complicated, but you can really figure it out yourself if you write all of this

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down in terms of the components and you will see that it's equivalent to one of them zero times beat

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times to rotation of E, where at this time the novel operator only acts on E, and then we have heard

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this term, one of them use zero and then the divergence of this vector product of B.

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And so here you first have to calculate the the vector product and then calculate the divergence.

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OK, so what can we do here?

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What you can see here is the rotation of E!

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And if you think about a Maxwell equation, the rotation of E is equal to minus B dot.

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So we have here one over Muzio times B times B dot.

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So this is very similar to this one here.

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But we had E times e dot so we can use again such a trick, very write it down as to in terms of a derivative,

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with respect to time and some factors.

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And then we write here B square and not E Square.

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So I done this here we have now another term, the time derivative with respect to time, as I, as

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I said.

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And then we have these three factors which are in this case, one of them use zero and then one half.

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And if we calculate the time derivative of this P squared term here, we had two times B times B dot.

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So this gives us the two councils.

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With this two, we get A B and we get B dot, which is this one.

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And this one is actually minus B dot.

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But here's minus, here's A plus.

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So it really works out.

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And here we get another term which where we can just swap around the order.

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So if you swap the two terms of a vector product, it gives us a negative sign.

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So this makes it here.

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Plus the divergence of this term here and now we can identify the shape of this equation with a continuity

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equation.

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So we have some term here, some scalar that is equal to the time derivative of some scalar because

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E squared, B square, both scalars and another term, which is a divergence.

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So this one is a vector.

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So we have here this is just from the previous slide to last lines.

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We have here a continuity equation for the term minus J times E, which is our power density as we have

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established in the beginning of this lecture.

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So we have established a continuity equation for the energy density where we have here a source or sink

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term.

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So this is how power can be generated.

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This is proportional to the current density times eat.

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Then we have the energy density itself, which is this term here and where we have to act.

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That's the time derivative act on.

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So this is Epsilon Zero Square and then we have another term proportional to be square and then we have

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another term, which is this divergence here, which is the where does this as vector?

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Here is the energy current density.

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This is the pointing vector.

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And you could say this tells us along which direction energy is transferred.

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And we will use this pointing vector in the next main section where we will discuss electromagnetic

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waves.

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So I will come back to these results here.

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But what we have done in this lecture is we have taken and one of the Maxwell equations and have shown

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that it can be transformed to a continuity equation for the energy density.

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And this allowed us to establish several terms, for example, the pointing vector or the energy density

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and show how they relate to the electric and magnetic fields.

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For example, you can see the energy density is proportional to the sum of each square and B square,

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and the pointing vector, which gives us the direction of energy transfer, is perpendicular to the

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electric field and perpendicular to the magnetic field.

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Due to this vector product, you.
