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Now that we have good qualitative understanding where the Maxwell's equations come from, I want to

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show you something different.

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So far we have introduced to Maxwell's equations in the differential formulation.

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So as you can see on the right hand side of these equations, there are quantities like the charged

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density or the magnetic fields or also E and J and all of these depend not only on the time, but also

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on the position vector.

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So what this means is if we look at one particular position vector, we can calculate also the left

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hand side of these equations and we can determine E and B, and so we know what E and B look like at

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this particular position vector.

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So it's something like a local formulation.

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However, we can also integrate over these equations and so we are not restricted to one particular

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position vector, but it's more like an integral formulation, like it's the same equation, but from

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a different point of view, so to say.

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So in this lecture, I want to show you how we can derive these four integral formulations of the Maxwell

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equations.

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And for this, we need two laws from mathematics.

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The first is divorce law.

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And this is actually quite difficult to derive.

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So I hope that it's sufficient for you that you just believe me that this is true from the mathematical

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side.

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And if not, you can look up proofs for this law on the Internet or in a textbook.

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But it is quite difficult.

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But here, I want to just just show you the result and want to explain to you what this equation means.

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So Gaza's law tells us that when we integrate over the divergence of some vector.

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So this is here, the integral over in Cartesian coordinates.

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This would be the X divided.

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So I just tried D.V., which is integral over the volume, and we integrate over some volume that we

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have defined.

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For example, it could be such a shape, but it could also be any other smooth shape.

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So that's a three dimensional integral.

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So did that Virgin's of this vector A is equal to the Vector eight itself, but now it's not a volume

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integral anymore, but it's an integral over the surface of this volume.

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So this is what I have noted here with this.

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And here the we integrate over this area element.

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So this D.

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S means or is characterized by such an element of the surface, and it is characterized, of course,

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by the absolute value of this element and a normal vector, which is always perpendicular.

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So you could say you have your your your vector field, which depends, of course, on on our on the

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position vector.

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So it can be different inside of this volume and on the surface of this volume.

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Now you calculate here the the scale of product with this vector A and this surface, which is essentially

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just the normal of the surface, then you integrate over the whole surface and it turns out that the

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left hand side is equal to the right hand side of this equation.

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So now that has used his theorem and apply it to our Maxwell's equations, because maybe you remember

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this, the first two Maxwell equations were divergences of E and B, so let us first take the divergence

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of E, which was equal to a constant times, the charge density row of R so we can rewrite this.

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We just multiply by Epsilon zero.

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So nothing really happened here.

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And then of course, since this is true for every position vector, we can just we can just integrate

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over our.

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So basically we integrate over the whole volume.

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So again, this could be any volume.

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As long as it's smooth, it could be a sphere.

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It could be a cube.

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Doesn't really matter here.

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It's true for any volume.

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And everything that is done here is just adding the integral.

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And I think you you know, this an integral.

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You could also think of some of this integral here at several different positions inside of the volume.

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And if you make these divi volumes very, very small, then this becomes the integral.

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So this is, I think, quite straightforward to understand what happened here.

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I have just introduced the integral because it is true for every position.

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So it must also be true for the integral.

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And now we apply the Gauss Theorem where we say, OK, let the right hand side does not really change,

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but the left hand side here, we change the divergence of E to E itself and we change the volume integral

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to the surface integral.

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And the right hand side, um, is the integral over the charged density.

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This is the same as here.

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And if you think about it, if we integrate over the density of our whole volume, then this is just

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the total charge in our volume.

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So we know that a surface integral of the electric field is equal to the absolute charged in our volume.

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B is the integral version of this differential maximal equation.

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Now for the electric field, it is very similar, but it's a bit more easy, actually, because the

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right hand side is zero in this case.

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So we do the same thing.

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We know that this is true for every position vector.

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So it must also be true for the integral.

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And now we can apply Goussis theorem here.

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So the divergence of view becomes just beat and the volume integral becomes integral over the surface

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area.

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So we have already derived two of the integral versions of the Maxwell equations.

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Now that is drive the other two.

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And for this we need a different mathematical law.

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And this is the Stokes law.

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So it is kind of similar to Kansas law, but also a bit different because here we do not have the diversions

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of a vector, but we have the rotation of a vector.

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And this whole integral is not a three dimensional integral of the volume, but it's a two dimensional

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integral of a some surface eight, for example, could be this one here.

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And so the two dimensional surface integral of this rotation of A becomes equal to the vector itself,

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integrated along the confining line.

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So does this align integral?

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You have this vector DL, which is always tangential to this area, eight so tangential to the confinement

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and you calculate here the the product of these two vectors and then you integrate over the closed loop.

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And if you do this, you will find that the left hand side is equal to the right hand side.

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So now we see here we have two dimensional integral over the rotation of a vector so that we can use

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this to formulate the integral version of the other two maximal equations, because there we have rotations

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of B and rotations of each.

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So first of all, and we'll just rewrite this a tiny bit.

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So I will just divide by Muzio.

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So nothing special happened here.

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And then we know that this is again true for every position.

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Makeda So it must also be true for an integral over these quantities.

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So we integrate over this one for this one and over this one.

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And in every case we integrate over the same area.

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And now we leave to the right hand side as it is.

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And we just use here stokes law because we have here a surface integral over the rotation of a vector.

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So this means it must be equal to the vector itself and the surface integral becomes an integral over

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the surrounding of the surface.

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So it's just a line integral.

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And the only other thing that I have done here is I have considered this integral over to current density.

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So it is just the total current in the area.

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A Those are our integral formulation for this maximal equation and for the electric field.

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It's very similar.

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We know that this is true for every position vector so we can integrate and this will remain true.

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And so now here we can apply Stokes law.

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So the rotation of E becomes E and this becomes a line integral.

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So this means we have derived the integral versions of these four different Maxwell's equations and

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we have come from a local definition of these relations to a global definition.

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And in the following lecture, I want to discuss both versions of these Maxwell's equations in more

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detail.

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And I want to show you how we can reestablish our well known results from the very first section of

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the scores, for example, the induction law, or also the umpire's law.
