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Let us now go ahead and talk about more difficult operations, so here we will discuss the multiplication

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and division of complex numbers and how this works using the polar representation of a complex number.

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So the multiplication of a complex number is not so difficult if you just do it straightforwardly by

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writing down the two numbers.

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So you have the real part, imaginary part, real part, imaginary part of the two numbers.

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And so the result is that you have to calculate your four terms.

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You have to calculate X times, you plus X times V.I. plus Y times you, plus Y times the eye.

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So the only thing that may be a bit tricky here is the term Y times by eight times VI.

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So what we get here is why V Times Square and I square.

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It is of course minus one.

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So this means this product here, y Times VII becomes actually a real part because I square is minus

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one, which is a real number.

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So we get as the real part x2.

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Minus five.

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And then there's the imaginary part.

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We get the other two terms, we get X, times V plus you times Y.

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Now, the next thing we want to do is to calculate the quotient of two complex numbers.

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So what we have to do is we have to take the first numbers one and have to multiply by a reciprocal

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number.

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So here we first have to find out what is the reciprocal of a complex number.

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And it's not that straightforward.

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But instead, we have to use a trick.

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We have to multiply by one and instead of one, we write seastar, seastar divided by seastar.

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So this is here, the complex conjugate, where you change the sign of the imaginary part of the number.

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And so we have learned in the previous lecture that Z Times the star is equal to the absolute value

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of C squared.

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And the absolute value of C squared is, of course a real number because the absolute value is a real

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number.

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So this, in fact, here is the real part squared plus the imaginary part squared.

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And then on top here we have a complex number.

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So this is a perfectly fine, complex number.

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We can write down all of this mathematics here.

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And so we get X minus Y times I, which is seastar divided by X squared plus Y square, which is this

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one here, as I mentioned previously.

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And then if you really want to split it up into the real into the imaginary part, you write it down

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like this.

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So the real part is the real part of the first number.

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Yeah, part of the number divided by the absolute value squared minus the imaginary part times.

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I divide it by the absolute value squared of the number.

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OK, so now that we have the reciprocal of the number we can calculate Z two divided by zero one.

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So here I have used again U plus V for a real imaginary part of C two and X and Y for the real and imaginary

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parts obviously you want.

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And now we can just use this relation here for one over each one.

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So we have this one and we have to multiply with you plus V times I.

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So we will get in all terms the denominator X squared plus Y square, which is the absolute value square

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of C1 and you we will get four terms.

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So these are of course these terms here and the only difficult term is probably V times I times minus

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Y times I.

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And so this gives us V Times Y and I square and then another minus one minus sine.

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And so since I square is minus one and we have this minus sine here we get here the positive sign and

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we get this entry as a real part.

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So this is what the quotient looks like.

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So now we can go ahead and look at what this looks like in the complex plane.

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So what we will we write down is, first of all, we write down to two complex numbers.

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Let's go ahead.

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We have Z.

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One is equal to one plus three times I and we have the two is equal to minus two plus PI.

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And then we take our equation for the multiplication so we can write down the one times C two is equal

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to.

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And no, I will not really rely on this equation.

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I will just show you how I would do it.

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First, let's write down these two numbers.

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Just copy them from here and then minus two plus one times.

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I know you calculate the four terms first to calculate one times, minus two, which is minus two,

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then you calculate one times I, which is I, then we have three times I times minus two, which is

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minus six I and then we have the last term, which is three times I, times I and I.

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Square is minus one.

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So we get minus three and now we can take the real parts which are minus two and minus three.

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So we get minus five and here we get one times I minus six times I which is minus five times I.

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And you would also get this if you would just try to use this formula.

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But I rather prefer do it like this.

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So now we can look at what this vector looks like.

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So here we have now our new vector Z one times Z two.

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So that is in fact really difficult to.

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Yeah.

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To think about what how we can get to this vector by by a simple vector operations.

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And in fact, it's not really possible because this is not a sum, not a subtraction, it's a product.

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And calculating the product of two vectors is not really that simple.

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We have to dot product, which is a scalar number, so not a vector.

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And we have the vector product which works just in three dimensional space.

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And what in this case point out of the plane.

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So how do we get this vector?

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Let's come back to this later when we have to pull our representation.

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But first, let us go ahead and calculate the quotient Ziyuan divided by Z2, so please don't be confused

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here.

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I used different nomenclature for Ziemann and Z2.

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So here's you want as you plus V.I., which was previously easy to.

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So what we need first is this, this absolute value square X squared plus Y squared.

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So this is the absolute value of C two square.

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And just for your information, we can also write down the real value of C two squared plus imaginary

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part of C two square.

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And so this is minus two square, which is four plus one square one.

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So we get five here and now we can write C one divided by C two is equal to one over five.

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Then we need these two terms, which are the products of the real parts and the imaginary parts.

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So we get one times minus two plus three times one, then we get plus I.

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And first we must calculate X times of V, which is the real part of C, two minus two times three.

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So this is minus six and then minus the other term, which is then just one times one.

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So we get one of a five

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um minus two, plus three is one and each here for the imaginary part we get minus six, minus one is

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minus seven.

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So we have C one divided by two is one over five as three apart and minus seven over five as the imaginary

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part.

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And this means in the complex plane, our vector is now here.

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And once again, it's really difficult to see how this vector is related to the two initial vectors.

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And we will find out now how they are related.
