WEBVTT 00:01.240 --> 00:07.840 Hello, in this section, we will discuss about sex, so first of all, let us see what a said is. 00:09.760 --> 00:18.490 Asset is the type of data structure which contains multiple elements, these elements are unordered 00:18.640 --> 00:19.780 like dictionaries. 00:20.200 --> 00:27.010 They do not have any fixed position like lists, and also the elements have to be unique in nature. 00:27.820 --> 00:36.760 So here we have two sets, A and B in this particular picture, the set, it contains four values, 00:37.060 --> 00:44.260 one, two, five and six, while the Set B contains three and nine. 00:45.190 --> 00:47.230 Here's the set. 00:47.230 --> 00:50.620 A and B do not contain any common values. 00:51.550 --> 00:56.260 And the entire data is called a universe. 00:56.920 --> 01:01.180 A universe is contained of a lot of six. 01:02.970 --> 01:05.370 Now, let us see this particular image. 01:05.580 --> 01:09.320 So here we have said it can be very sick. 01:09.400 --> 01:11.280 It is a complete. 01:12.710 --> 01:20.440 Set of values which are present in be so set me contains value one, two, three, four and five miles 01:20.450 --> 01:20.840 set. 01:20.840 --> 01:23.600 It contains value for two and one. 01:24.810 --> 01:35.640 Because the values presenting are also present in being is actually a subset of B. Riley B because it 01:35.640 --> 01:46.320 is larger than E, and it has values from A, it is called a superset, please, not for a sect to be 01:46.320 --> 01:51.480 a superset of E, it should contain all the elements present in. 01:53.050 --> 02:00.700 Or for it to be a subset of all the elements presenting it should be a part of the. 02:01.930 --> 02:11.290 Now, let us see another example here, if we consider that envy and get the values, the job doesn't 02:11.480 --> 02:13.380 involve envy. 02:13.600 --> 02:15.700 It is called a union office. 02:15.700 --> 02:24.880 And if they are interested in the values which are common between A and B, they are called an intersection 02:24.910 --> 02:34.720 of A and B, in case we want to find out values which are present only in A and are not pleasant. 02:34.720 --> 02:46.940 And B, this is called a difference of A and B a semantic difference is a union of A and B, and we'd 02:46.960 --> 02:50.220 surprise the intersection of envy from it. 02:50.530 --> 02:51.070 So. 02:52.260 --> 02:58.200 Semantic difference is union of in B minus the intersection of. 02:58.240 --> 03:01.530 And now let us see this with data. 03:02.400 --> 03:06.300 So here we have to set the uncute. 03:08.170 --> 03:17.950 The union of the MQ will be having elements from the uncute, so the Union of the Amcu will have values 03:17.950 --> 03:29.170 nine three six eight to enforce an intersection of A and B. So here an intersection of the N. 03:29.170 --> 03:32.020 Q will contain only six. 03:33.270 --> 03:37.250 Because sex is the only value which is common between being and. 03:38.670 --> 03:50.790 Now let's find out the difference between A and B. So here the minus Q will be only nine and three because 03:50.790 --> 03:54.660 sex is the only element which is present in both of you. 03:54.930 --> 03:58.820 So the difference between the and will be nine and three. 03:59.250 --> 04:06.100 If we subtract B from Q, then the difference will be eight, two and four. 04:06.990 --> 04:13.170 So the values of B minus Q and Q minus B are entirely different. 04:15.310 --> 04:22.960 The values of symmetry of difference will be nine, three, four to eight. 04:23.140 --> 04:28.470 That is the union of being equal minus the value of six. 04:28.660 --> 04:35.770 So the entire set, except for the value which is common between the two, is called the symmetric difference. 04:36.850 --> 04:39.670 Now, let us see how we can hold this in. 04:42.200 --> 04:53.450 So let us list down the features of sex also so it will be unordered. 04:56.080 --> 05:01.450 It will have unique values. 05:05.840 --> 05:06.650 And. 05:08.520 --> 05:10.470 It can have elements. 05:12.680 --> 05:16.010 All different data. 05:18.050 --> 05:20.520 Now let us see what all operations could be done. 05:20.780 --> 05:29.600 We can add value, we can remove a value, we can do union of different sects. 05:30.110 --> 05:34.310 We can find out the intersection between the sets. 05:34.670 --> 05:36.500 We can find the difference. 05:40.480 --> 05:42.430 And the cement. 05:43.960 --> 05:44.630 Patrick. 05:47.780 --> 05:50.990 Difference between two six. 05:53.410 --> 05:58.030 Now, let us see how we will do that, so let us create two sets. 06:04.240 --> 06:05.620 So let us create. 06:07.270 --> 06:18.470 A steady and steady the values were set and said B will be, let us say we will create it by creating 06:18.580 --> 06:25.390 daily basis and inside these gaudy places we will put in the values which we wanted to have. 06:25.400 --> 06:29.710 So let us say it has value a. 06:31.800 --> 06:32.400 We. 06:36.370 --> 06:37.240 Hi. 06:39.690 --> 06:40.350 S.. 06:43.040 --> 06:47.150 D and let me have high. 06:49.340 --> 06:50.150 Ex. 06:53.410 --> 06:54.130 Why? 06:56.400 --> 07:00.490 Said and let us increase the number of common values. 07:01.110 --> 07:06.170 So let us have see also this one and let us have. 07:14.730 --> 07:19.890 And in this one, let us have the values X as. 07:21.360 --> 07:23.090 So let us run this. 07:23.480 --> 07:30.210 So here we can print tea so you can see it has all the values which we have created. 07:30.480 --> 07:40.490 Now let's see the type of E so the type of E said, let us try to add multiple values. 07:40.560 --> 07:44.550 So let let's try to add more X and more. 07:45.330 --> 07:53.940 So if you do this and let us see, the E will contain only one occurences of these values, no value 07:53.960 --> 07:55.200 will be repeated. 07:56.370 --> 08:03.840 Now, let us see how we can use different operators, so let us say we want to find out if a particular 08:03.840 --> 08:05.570 value is present in an sec. 08:06.060 --> 08:07.530 So let us check if. 08:10.210 --> 08:10.660 A. 08:11.830 --> 08:13.060 Is present in. 08:15.320 --> 08:15.630 Set. 08:17.030 --> 08:19.950 So when we done this, we get through as an answer. 08:20.210 --> 08:22.790 Now let us try another scenario. 08:23.720 --> 08:27.080 Let us check if he is present in a. 08:28.060 --> 08:29.980 So it gives back false. 08:32.370 --> 08:37.860 Now, let us say we want to add another value to our set so we can do that by. 08:38.880 --> 08:39.750 Steg. 08:41.040 --> 08:42.510 B Q are. 08:46.780 --> 08:51.190 And we want to do it so we will see a dot on. 08:55.080 --> 08:55.800 EQR. 08:57.060 --> 09:02.830 So we just want to add you are to the city and let us check again. 09:03.270 --> 09:11.550 So here you can see the value here has been added and there is no specific ordinance, so it just got 09:11.550 --> 09:12.150 added. 09:13.040 --> 09:20.040 At some position now, let us try to remove a particular value. 09:20.060 --> 09:28.220 So let's say we want to remove a particular value so we can save a dot and lose. 09:31.920 --> 09:39.600 Hi, so we are just trying to remove hi from this and then we'll print it so you can see we have successfully 09:39.600 --> 09:41.310 removed high from. 09:43.450 --> 09:50.560 Now, let's see if we want to trade on top of the set, then we can simply use for loop so we can say 09:50.560 --> 09:55.960 for Vul or any Weeble in the safety. 09:57.670 --> 09:59.400 And we can see Brent. 10:00.660 --> 10:01.290 Well. 10:03.480 --> 10:11.280 So it has printed the volumes I'm here, you can see that, although that is as it seems like there 10:11.280 --> 10:17.720 is an order present every time we print visitors printing A, B, C, D in alphabetical order. 10:17.940 --> 10:24.980 But when we actually try to trade on top of this particular set, the volumes are coming out randomly. 10:26.490 --> 10:28.840 So now let's try another thing. 10:29.250 --> 10:36.990 So let's try to do a union of these values, so for doing an onion, you can say let's create a new 10:36.990 --> 10:43.890 sexy and we can see is equal to a union. 10:46.190 --> 10:57.540 The latest princi, so here you can see when we did a union of A and C, it just gave the entire list 10:57.540 --> 11:06.450 of values that are present in and the world and combined it together and created the sexy for us. 11:06.600 --> 11:16.980 And you can see all the other values, C, D and X were common in A and B, but still the sexy does 11:16.980 --> 11:19.260 not contain multiple occurrences of this. 11:19.270 --> 11:21.840 There is only one occurrence of these values. 11:23.030 --> 11:31.780 Now, in case we want to find out an intersection, we can simply see a DOT intersection. 11:34.290 --> 11:34.740 B. 11:35.900 --> 11:43.520 And you can see we got the intersection values of A and B, which is C, V and X, which were common 11:43.520 --> 11:44.870 values, which we created. 11:46.250 --> 11:56.740 Now, in case you want to check, if a particular set is a subset of another set so we can use is subsid, 11:56.930 --> 12:01.970 so let us try to check if a dot is. 12:04.860 --> 12:11.370 Subset of B. So when you run this, you get a fall. 12:11.410 --> 12:14.110 So this means that is not a subset of B. 12:14.400 --> 12:23.640 Now remember, we created C and C was a union of E and B, so C contains all the elements of A and B. 12:23.970 --> 12:31.590 So if we say C, A subset of C. 12:34.720 --> 12:44.500 Sorry is subset of see, so it gives a true that is it is a subset of C and similarly if we try to do 12:44.500 --> 12:51.020 it on V, so which is a subset of C, it gives a true value. 12:51.700 --> 12:55.360 So this is how we can check if a value is a subset. 12:55.390 --> 13:03.730 Now if you want to check if OPSEC is a super sick of another set, we can do it by C dog is superset. 13:05.200 --> 13:15.910 Of the so it gives a true value, which means that is a superset of the now another thing which we can 13:15.910 --> 13:19.970 do is we can find out the difference and the symmetric difference. 13:20.290 --> 13:23.730 So let us try to find out the difference between A and B.. 13:24.280 --> 13:28.190 So a dot difference. 13:30.910 --> 13:31.300 The. 13:33.380 --> 13:37.940 So we can get the values of a job as an only in a. and not in the. 13:39.180 --> 13:43.590 We can find out the difference. 13:45.180 --> 13:45.540 A. 13:47.080 --> 13:50.230 And let me bring the values of. 13:53.690 --> 13:59.790 A and B here's. 14:01.240 --> 14:03.850 So that you can see what other differences. 14:07.410 --> 14:17.790 So here you can see that the value of A is B, B, C, E, X and B, while the value of B is DC high, 14:17.820 --> 14:20.610 H, A, Z, X and Y. 14:20.790 --> 14:27.810 So here are the values which are present only in A are A, B and B QR. 14:29.230 --> 14:38.200 Similarly, here we are finding a difference of B minus E, so the values which are only present and 14:38.200 --> 14:44.110 B are high Y and Z, so that comes up with the result of. 14:45.050 --> 14:54.700 The difference now is they want to find out symmetric difference so we can do it by simply stating it 14:54.700 --> 14:57.110 not symmetric. 15:00.050 --> 15:01.370 Defense. 15:02.910 --> 15:03.390 The. 15:04.700 --> 15:14.300 And gives this value and we can simply find out we got symmetric defense. 15:17.060 --> 15:24.560 So here you can see that the symmetric defense is seen from either direction while defense has different 15:24.560 --> 15:28.660 values based on the value which we are subtracting it from. 15:28.670 --> 15:36.380 So subtracting B from E, then it has the values which are only present in A Anovia, subtracting E 15:36.380 --> 15:40.400 from B, then it has values which are present only in the. 15:41.480 --> 15:41.990 Thank you.