0 1 00:00:21,510 --> 00:00:22,190 Hello. 1 2 00:00:22,260 --> 00:00:32,750 Let's continue to learn structure takes basic structure and I will create a new project in programs 2 3 00:00:32,780 --> 00:00:33,440 area. 3 4 00:00:33,530 --> 00:00:35,700 I will create two program 4 5 00:00:35,810 --> 00:00:37,820 One will be ladder diagram 5 6 00:00:42,860 --> 00:00:45,950 and another will be structure text 6 7 00:00:54,380 --> 00:01:00,510 and program is creating now and program zero in the ladder diagram area. 7 8 00:01:00,650 --> 00:01:12,170 I will add LD M1 for example and plus D10 D12 to D14 multiplied by D14 D16 8 9 00:01:12,170 --> 00:01:13,910 to D20. 9 10 00:01:13,940 --> 00:01:16,270 So this is a ladder diagram example. 10 11 00:01:16,280 --> 00:01:22,610 For example in here and how to write this ladder diagram. 11 12 00:01:22,610 --> 00:01:25,740 Example as ST language. 12 13 00:01:25,880 --> 00:01:31,910 So I will create a I already created a st language program area in here. 13 14 00:01:31,910 --> 00:01:42,510 So let's write if M1 THEN and I will check one is it m1 or m0 m1. 14 15 00:01:42,510 --> 00:01:43,290 That's okay. 15 16 00:01:43,320 --> 00:01:52,250 And D10 multiplied D12 equals to D14 D14 multiplied by D16 to d20. 16 17 00:01:52,290 --> 00:01:59,880 So the way is going to d20 what should we do. 17 18 00:01:59,920 --> 00:02:02,260 We can say D20. 18 19 00:02:02,410 --> 00:02:05,290 equals to D16 19 20 00:02:05,440 --> 00:02:11,330 Multiply by D10 plus D12 END_IF 20 21 00:02:12,040 --> 00:02:14,640 so let's take a look. 21 22 00:02:14,740 --> 00:02:15,610 Is it correct 22 23 00:02:18,640 --> 00:02:22,340 D20 equals to 16 multiplied by 14. 23 24 00:02:22,360 --> 00:02:26,000 But already 14 is equals to 10 plus 12. 24 25 00:02:26,140 --> 00:02:35,100 So let's check once ten plus twelve multiply by D16 equals to D20 25 26 00:02:36,220 --> 00:02:37,150 Let's check once. 26 27 00:02:37,150 --> 00:02:37,600 to. 27 28 00:02:37,630 --> 00:02:39,830 Is it correct or not is it. 28 29 00:02:39,910 --> 00:02:42,330 The project is compiling now. 29 30 00:02:42,730 --> 00:02:52,600 I will send this code to my simulator and say transfer it's transferring now and transfer is finished. 30 31 00:02:52,600 --> 00:03:02,500 Go program 0 and activate M1 and let's give to present value to D10 ,D10 equals to 5. 31 32 00:03:02,570 --> 00:03:03,180 Okay. 32 33 00:03:03,280 --> 00:03:06,660 And D12 equals two let's say two. 33 34 00:03:06,880 --> 00:03:12,570 Okay and D16 will be equals to two. 34 35 00:03:12,640 --> 00:03:13,900 That's okay. 35 36 00:03:14,200 --> 00:03:14,680 And 36 37 00:03:17,780 --> 00:03:19,420 that's okay. 37 38 00:03:19,420 --> 00:03:23,320 Finished my cpu is stopped now. 38 39 00:03:23,320 --> 00:03:25,290 So the result is zero. 39 40 00:03:25,420 --> 00:03:29,910 I will say run plc it's run now. 40 41 00:03:30,440 --> 00:03:30,900 -- 41 42 00:03:30,920 --> 00:03:36,280 Set on and change present value because of it wasn't it was a stop. 42 43 00:03:36,280 --> 00:03:37,260 position. 43 44 00:03:37,280 --> 00:03:39,440 So the values are cleared now. 44 45 00:03:39,710 --> 00:03:50,590 So D10 give a valued to a d12 will be for example five and D16 will be two then 45 46 00:03:50,660 --> 00:03:58,340 output two plus five is equal to seven and seven multiplied by two fourteen and go to a ST program 46 47 00:03:58,670 --> 00:04:05,930 in here you can see D20 is fourteen so that's okay change present value in here for example 47 48 00:04:05,960 --> 00:04:14,680 D12 to for example ten and the result will be twelve multiply by two and twenty four. 48 49 00:04:14,870 --> 00:04:15,350 That's okay. 49 50 00:04:15,350 --> 00:04:27,520 Go offline and program zero delete this one and complete the ladder diagram is deleted and we will say 50 51 00:04:27,570 --> 00:04:37,450 just only ST language section to our simulator and project is compiling and download this execution 51 52 00:04:37,450 --> 00:04:39,750 code to simulator and transfer again 52 53 00:04:45,180 --> 00:04:52,620 then go back to running state and if M1 that's ok and change present values. 53 54 00:04:52,680 --> 00:04:57,010 D12 five and D10 will be five. 54 55 00:04:57,010 --> 00:05:07,110 For example D16 will be five so five plus five equals to Ten Ten multiplied by five equals to 50. 55 56 00:05:07,110 --> 00:05:21,350 So this is working and go off line and say else D20 will be zero and go online again if M1 is not 56 57 00:05:21,620 --> 00:05:23,180 active or not high. 57 58 00:05:23,180 --> 00:05:31,290 So D20 will be zero download this code to simulator and OK 58 59 00:05:34,830 --> 00:05:47,370 and say yes m1 is active and then I will change these ones and D5 , D12 will be five 59 60 00:05:47,460 --> 00:05:49,880 and D16 will be five. 60 61 00:05:49,920 --> 00:05:55,060 So you see D20 is 50 now if M1 is set off 61 62 00:05:55,170 --> 00:06:05,660 So because of else condition D20 equals to now zero and I will finish this video for a moment but first 62 63 00:06:05,660 --> 00:06:08,340 of all I need to explain one more thing. 63 64 00:06:08,600 --> 00:06:12,670 Structure of ST 64 65 00:06:13,160 --> 00:06:13,530 -- 65 66 00:06:13,580 --> 00:06:14,110 How is it. 66 67 00:06:14,120 --> 00:06:19,190 So we need comment 67 68 00:06:19,270 --> 00:06:20,650 Like I am writing now. 68 69 00:06:20,650 --> 00:06:21,460 This is a. 69 70 00:06:21,880 --> 00:06:27,460 When we put when we want to put a comment like here we can say this is 70 71 00:06:31,200 --> 00:06:39,600 is comment like this structure of st equals to we have a comment in here. 71 72 00:06:39,610 --> 00:06:51,060 That's okay and we need keyword and we need expression and we need again. 72 73 00:06:51,100 --> 00:06:52,070 Keyword. 73 74 00:06:52,540 --> 00:06:54,880 And we have substatement 74 75 00:06:57,790 --> 00:07:01,340 and we have keyword again. 75 76 00:07:01,360 --> 00:07:05,590 So let's check this one we didn't used comment. 76 77 00:07:05,680 --> 00:07:09,580 That's okay but keyword is in here. 77 78 00:07:09,580 --> 00:07:16,870 If ->if is keyword, expression is M1 and the keyword again then and the keyword again. 78 79 00:07:17,290 --> 00:07:31,300 END_IF; , and keyword again ELSE sub-statement is this one this is substatement and this is for example keyword 79 80 00:07:31,780 --> 00:07:38,170 and this is our expression and this is our keyword again. 80 81 00:07:38,890 --> 00:07:41,920 This is our keyword again like this. 81 82 00:07:42,160 --> 00:07:49,240 This is how to create ST language programming examples how to write a a ST language and how 82 83 00:07:49,240 --> 00:07:58,600 to structure of ST or how to adopt your structure text programming language in the plcs 83 84 00:07:58,900 --> 00:08:07,240 but we will learn if and repeat and while and for and case loops and also the usage of the structure 84 85 00:08:07,240 --> 00:08:15,560 texts in plc like and conditions or conditions or parenthesis and everything but for the moment I 85 86 00:08:15,570 --> 00:08:17,110 am finished for this video. 86 87 00:08:17,140 --> 00:08:18,700 See you in the next video.