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Hello.
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In this video we are going to learn analog input and output usage.
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The common analog signals are voltage as voltage 0 to 10 Volt and the current as current 4 to
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20 mA to use the analog signals inside of the PLC.
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We have to convert them as digital values like 0 to 4000 , 0 to 8000.
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The important point is here.
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Animal input means analog to digital converter and analog output means digital to analog converter.
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For example if our converter is 8 bit so 1 divided by 2^8 - 1.
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So 10 divided by 255.
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Equals to 0.04V as we can say it.
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Resolution.
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So if we to this equation if we apply 4V  to analog input of module we are going to read 1000
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value inside of our plc.
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It's calculated for 8 bit but let's say our converter is 12 bit.
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So 10 divided by 4095.
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So it equals
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from  equation.
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Result is 0.00244 
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This is a voltage value and it equals one bit.
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So if I apply 2.44Vdc to analog input of module we are going to read one thousandth
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value inside of plc.
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It is calculated for 12 bit  example that DVP06XA analog input and output modules allows
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4 analog input and 2 x 12 bit digital output connections the data transfer can be done using DVP
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06XA via RS485 communication or by connecting directly these modules to our CPU.
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If you put this module to CPU the closest module a number is going to be 0.
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The furthest modules number is going to be 7 and the maximum 8 modules can be connected to CPU in
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here.
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You can take a picture also you can see how to voltage input is applied to our modules how to connect
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your current input to your module and how to output from module voltage output then you can get a cabling
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structure is here v+ is for voltage I+ for current input and output and the com is common
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cable communication and in here you can see your power supply and the ground connection and you can
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see in here Channel 1 the lowest side and Channel 3 and Channel 5 for voltage or current output and
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channel 6.
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And in here Channel 4 and in here Channel 2 IO terminals in here you can see what is offset and gain
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and offset is a starting point from zero then you can adopt it for example inside of the plc you are
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reading a zero and offset is zero but you can adapt your offset.
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For example 1V then until one volt to your analog input.
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for example it can come zero point five fold or zero point six volt than you will read zero inside your
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plc THEN you can block or you can cut some sections of your analog input and the gain is you are
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going to see a 1000 as digital value insİDE your plc according to or after 5v applied to your
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analog input module.
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The for example Channel 1 and if you want to see 1000 when 6 voltDc apply to your analog input then
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you can adopt it with the gain settings and in here also you can see current input and digital output.
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So for example for the current input you can start if you want to start for example from 4 ma
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then you need to adopt your offset settings in here we can see a complete control registers of DVP06XA
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and we are going to learn how to read this manual and how can we control this manual , okay.
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Let's go to our example in Channel 1 of analog module ,sensor is connected to this sensor is 4 to 20
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ma pnp current output it gives to us 4 to 20 ma,and when this sensor detects the
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light and it will give a current output to us and if this output is greater than 10ma motor1
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is going to start if this output greater than 15 ma motor 2 starts to run in the second
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input.
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This is our first input channel and you can see the current input connection is done in here we have
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one we can see thermocouple symbol temperature sensor is connected and this sensor output than that
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means input of our analog module is between 0 to 10VDC 
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So if boiler water temperatures lower than 5V, motor3 is going to turn and starts and if boiler
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water temperatures is bigger than 5v motor 4 is going to start to turn and now let's how to, try
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to solve this problem with use of our DVP06XA's module control registers and first thing we need
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to use TO command for write to module and if you need to read from module we need to use FROM command
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and this is our channel numbers and this is, these are all bit numbers of our channels so this table
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shows bits of all channels and we will assign bit values as 0 or 1 and we will calculate our value to
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send device first let's determine whether the status of channels of our analog module.
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So Channel 1 is going to be current input read rest of all will be voltage input.
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Let's take a look to voltage input is 0 0 0 and current input or current output but this needs to be
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input not an output but okay we will use this one mode 3 and this should be 0 1 1 So Channel 1 will
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be current input so I will put it tohere and the 0 0 0 will be Channel 2 the rest of all will be voltage
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input so all of them will be 0.
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If you calculate this number as binary, you can open your calculator and you
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can write this as binary but this is work like this.
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0 0 0 1 and 1 0 and 1 1.
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These are all 0 so this is 3 as hexadecimal 3 and decimal 3 also but we need to send hexadecimal values
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to our plc hexadecimal 3 value that we get and this and this value in here.
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to first module with   first scan inside in the first second with the TO Command we write this value
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to our analog module and now we need to adapt our offset and gain adjustment and authorization
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settings must be done so in the first scan and the controller registers 33 we write 
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h0 but why.
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Let's take a look to in here.
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33 is control registers that offset and gain took tuning 
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I couldn't say authorization so the default is 0 0 0 so we need to use this 0 value because
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  we need to get permission for the offset and gain settings so what is the gain an offset adjustment
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and why is it needed conversion of analog signal to digital signal in plc between 0 to 4000 value
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for the voltage input and 1 to 0 to 1000 value for the current input then it changes to according to plc
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brands and the hardware.
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For example 10 Volt it means 10 divided by 4000 and 2.5 mv equals to 1 as digital
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value in plc.
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In other words lowest valued bit that we can express as resolution is that sensitivity and it equals
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2.5 mv
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And in this case for example it is necessary to use the expression of for example 8000 lowest values
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bit equals to two , why because 800
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Multiply by 2.5 mv will be two volt and 2000 value
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will be five volt and 2000 multiply by 2.5mV
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mv , this is the answer of our question and if we looked in the same way for the current 20ma
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current and one lowest valued bit will be 20 mA divided by 1000 and will be 20 ma
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And in here Channel 1 will work in the range of 4-20mA  and the Channel 2 is going to be
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range will be 0-10 Volt and output channel in the range of will be 5 to 10 Volt.
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Okay first gain settings and office settings.
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Let's take a look them all then come here and we will see also in here analyzed one by one for the gain
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settings it is starting from Channel 24 to channel 29.
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Let's go to here.
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24 to 29
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You can see them all in here for the Channel 1 and Channel 4.
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gain settings default value was 1000 when the voltage input range from 800 to 4000 for the
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current input 800  to 2600 for the outputs of ourChannel 5 and Channel6
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to adjust gain of outputs.
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Look in here.
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Default is K 2000  and the range is 0-4000 and come here.
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Let's take a look once to our values.
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So what is the meaning of 1000 in here.
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So first thing we need to know.
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The gain settings for the current input.
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Like in here.
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Channel 1 will be default 1000 for the current input.
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So in here K 4000 will be a maximum value of our voltage input because we will say it like this.
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Now if 20 ma comes to our current input channel then it will be 1000  value inside of
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the PLC.
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If we see 10 volt of our channel 2 or analog input then this will be inside of the PLC 4000 value.
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So Channel 3 and Channel 4 not used and the outputs.
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Also we adopted it like this.
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We will give to 0-10 volt output.
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So if we give 10 Volt as analog output from our plc we are writing to this registers to 4000 in our
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PLC offsets settings for 4 mA ,in here we need to write here to 200
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Why.
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Because1 lowest valued bit is 20uA and we calculated in here and 20uA
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multiply by 200 -> 200 x 20uA an it equals to
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4000uA and it equals to 4 mA
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So we want to use our analog input as 4-20mA because of we want to started to 4mA
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we write it here.
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K200
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So it is now default offset value and it will start from 4mA
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to 20mA and the range will be like this.
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And for the our analog   inputs for Channel 2 we are going to use 0 to 10 volts and we don't need
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to use an offset anything and for Channel 4 No ,for Channel 5 we write in here.
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K1000 Why?
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Because let's go back to here and for offset of Channel 5 you can see it.
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The range is K -2000 to +2000 so two thousand equals to 10v for analog
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output.
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This is equals to 10 volts because we are using 0 to 10 volt.
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Okay go back here.
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So if we start it from the K1000.
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It starts from 5 volt so in our example let's go to there.
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So we are   wanting to   calculate according to 5V lower than or bigger than.
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So   we can adopt it these offsets to 1000 and it starts from 5V to 10v then
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Channel 6 is not used so we can leave it like this and for the CR
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24 to 29 is for the Channel 1 to Channel 6 sequentially in order to enter gain settings from table.
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And we already saw it ,in here from CR registers 18 to CR 23.
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These are all adjusted offset settings and the for the gain value for Channel 1 2 and 3.
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It's starting from 24 to 29.
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And this one is coming from here so CR1 that we can adopt our input and output mode.
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And we are going to read our values from where.
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Let's take a look it also and let's take a look once to our complete plc project.
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Remember in the first line we adopted our channels current and voltage situations and the permissions
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for the offset and gain settings.
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So we adopted it we write H3 and we write 0 to first module to CR33
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and offset settings are adopted for 4mA and for 5V and the gain settings of all channels
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adopted when we get 20mA  we will get 1000.
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When we get what inside of the plc  4000 and it will be equal to 10 volt and the outputs will
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be 0 to 10 volt.
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And if we write 4000 to our outputs it will give 10 volt and in here we are reading   from analog
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inputs with the from command.
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So from the first module we are reading C12-13
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Let's take a look.
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12 is Channel One input present value then Channel 13 or control registers 13 is Channel 2 input
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present value.
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So we are reading current from here analog input from here and we are writing these values to D200
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is our current input value D202  inside of it we can see our voltage
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input value.
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So let's compare it for example in here we are comparing Channel 1 as mA
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So what we did we are starting from 200 and the maximum value is 1000.
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So in here we have 16 mA and so it is starting from 4-20Ma And  800 equals
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16Ma and so 1Ma equals to I'm sorry like this 50 value,
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If you want to   compare with 10 mA and 10 mA.
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Multiply by 50.
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So we get this value.
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So we are comparing it with this value.
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And if it's bigger than for example 500.
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So let's go back our   question.
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So if it is bigger than 10 mA then motor1  is going to start.
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Okay.
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Let's take a look ones in here.
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If it's bigger than this value so the motor will turn and if it bigger than 15 mA then 15 multiply
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by 50.
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So it is equal to 750.
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The second motor is going to turn and the compare Channel 2 which   5V.
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So   remember we started from K 1000
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It is our now.
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  zero position.
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So K2000 = 5V
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So because we started from   one thousand one thousand is zero and   go back to here and let's take
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a look to it for the offset value.
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This is our range.
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So two K 2000 
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So in here let's go back to here.
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So K 2000 = 5V
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Why.
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Because what we have we have 0 to
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K2000 it started from here.
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And this is completely.
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2000 was 10 Volt and one thousand is 5Volt
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So now we are starting from this one than the rest of all is not used but we can go a little
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bit further.
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How like this K 2000 is - K1000 and it equals 1000 so 1000 equals 5V
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And if it D202 our temperature is lower than 5V according to our comparision.
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Motor 3 is going to turn and if D202
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D202 value is equals or bigger than 5V
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K2000
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That means the 4. Motor will turn these are the outputs are from plc  then you can
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connect this output to your motors to your relays or contactors etc. then you can turn
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motors according to analog inputs then and also analog output.
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In this video.
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Finished in here.
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see you in the next video.