1 00:00:21,410 --> 00:00:22,050 Hello. 2 00:00:22,160 --> 00:00:30,710 In this video we are going to learn data addressing for the bit addressing the meaning of the bit zero 3 00:00:30,740 --> 00:00:41,570 or one or on and off control is only available for one bit addressing like it's five or M0 or 4 00:00:41,690 --> 00:00:43,080 out Y1 5 00:00:43,160 --> 00:00:43,830 -- 6 00:00:44,030 --> 00:00:51,550 The basic comments are usually addressed with a single bit four digit addressing digit means 4 bit. 7 00:00:51,590 --> 00:01:01,340 So if we say two digit equals to one byte ,four digit equals to one word so far with addressing 8 00:01:01,400 --> 00:01:01,990 is a digit. 9 00:01:02,600 --> 00:01:12,260 And we can express it like this k1 is four point or four bit according to what according to this 10 00:01:12,470 --> 00:01:13,460 usage. 11 00:01:13,470 --> 00:01:20,930 Okay so for example K1 M0 4 bits are expressed by addressing at the end of the common process the 12 00:01:20,930 --> 00:01:29,960 values of m0 or 1 and 2 and 3 bits have been moved to the first four bits of sixteen bit D0 13 00:01:30,020 --> 00:01:31,500 memory region. 14 00:01:31,520 --> 00:01:45,010 So for these zero memory region we can use one digit addressing 4 bits 0 and 1 and 2 and 3 4 bytes 15 00:01:45,050 --> 00:01:53,620 addressing four and one byte is eight bits so we can express it with k 2 because of the remember in 16 00:01:53,630 --> 00:01:59,750 here k 1 Was it cool 2 4 bit or K was equal to 4B. 17 00:02:00,020 --> 00:02:05,760 So K to 4 multiply by 2 8 point or 8 bit. 18 00:02:05,990 --> 00:02:18,380 So if we move K to M 0 to the zero then we can assign a B to inside of 2 to 0 3 digit addressing so 19 00:02:18,380 --> 00:02:26,990 three digit means twelve bits forty four cha three bits form with play three bits so for example 12 20 00:02:26,990 --> 00:02:35,390 points can be expected with an addressing such as K 3 m 0 like this then we can see it in here usage 21 00:02:35,840 --> 00:02:39,160 and word other thing if we want to. 22 00:02:39,260 --> 00:02:42,650 Addressing address to avert. 23 00:02:42,650 --> 00:02:51,230 So the word can be used with the timers and counters or data registers etc. these registers are word 24 00:02:51,230 --> 00:03:00,050 side so word is a two byte or sixteen bit so we can say that one word equals sixteen bit so we can 25 00:03:00,050 --> 00:03:06,030 say one word equal to k4 multiply by 4. 26 00:03:06,110 --> 00:03:15,960 So that means sixteen point or sixteen bit than complete word can be addressed by bits to it and in 27 00:03:15,960 --> 00:03:20,710 here m 0 or M auxiliary relay are an example. 28 00:03:20,750 --> 00:03:29,030 So if you want to use addressing for double word so that means the addressing method described so far 29 00:03:29,390 --> 00:03:33,770 was the word addressing format in the k 1 and k 4 range. 30 00:03:33,920 --> 00:03:44,480 Some commands are expert with the 32 bit memory area so K1 is four point K2 eight points K 3 twelve 31 00:03:44,480 --> 00:03:46,960 point K 4 sixteen point. 32 00:03:47,150 --> 00:03:58,610 But if we use k 5 then we can address 20 points or two and to be in word area and if we if we go a little 33 00:03:58,610 --> 00:04:04,640 bit further both to 16 bit or one word we shall use double word. 34 00:04:04,940 --> 00:04:16,220 So for example if we say okay k8 we can use thirty two point and what about the indirect addressing. 35 00:04:16,220 --> 00:04:24,530 So while indirect addressing can be used with the word parameters can X and can Y and can M and can 36 00:04:24,710 --> 00:04:29,330 timer and counter and data registers. 37 00:04:29,540 --> 00:04:37,460 It cannot be used with the parameter it's a m as ejector right not able to command allows indirect addressing. 38 00:04:37,460 --> 00:04:45,800 So in here we can see a usage of indirect addressing so it will it is really helpful for us and we are 39 00:04:45,800 --> 00:04:53,620 going to use indirect addressing while we are writing up serial communication program for the drives. 40 00:04:53,630 --> 00:04:58,990 So it will help to reduce a programming line for us. 41 00:04:59,030 --> 00:05:07,620 For example if x 0 becomes high so these 5 e will move to the 8. 42 00:05:07,850 --> 00:05:14,030 So let's say equals to 8 and F equals to 14. 43 00:05:14,030 --> 00:05:18,410 So these 5 E means do . 44 00:05:18,470 --> 00:05:25,810 This is a data registers 5 and 8 5+ 8 a then equals to 13. 45 00:05:26,070 --> 00:05:30,070 It is close to the thirteen. 46 00:05:30,120 --> 00:05:32,940 So what about the A@F. 47 00:05:32,940 --> 00:05:38,750 So here 8 and f is 14 14 plus 8. 48 00:05:38,820 --> 00:05:47,700 So it equals D22 when the condition exists or high done D 13 well who is going to be transferred 49 00:05:47,700 --> 00:05:56,030 to D22 for the ISPsoft usage so you can see in here we are adding at sine. 50 00:05:56,310 --> 00:06:00,490 So in here imagine E 0 is 5. 51 00:06:00,540 --> 00:06:06,830 So the 10 5 five will transfer to D0 in here. 52 00:06:06,840 --> 00:06:13,790 Imagine if zero is to D100 and two will transfer or move to the zero. 53 00:06:13,800 --> 00:06:18,060 For example in here let's say is zero equals to 10. 54 00:06:18,060 --> 00:06:24,870 So the one under than ten is going to transfer in here but we need to know if 0 0. 55 00:06:24,880 --> 00:06:26,790 Let's let's give an example. 56 00:06:26,840 --> 00:06:28,010 It goes to 3. 57 00:06:28,200 --> 00:06:34,830 So the one under then 10 is going to move to the one under then 3. 58 00:06:34,860 --> 00:06:40,990 So let's take a look once to our ISPSoft software 59 00:06:41,280 --> 00:06:48,840 Let's write the program and let's analyze what's going on with this addressing and let's let's practice 60 00:06:48,930 --> 00:06:49,410 a little bit. 61 00:06:49,890 --> 00:06:57,960 So a new project and controller type DVP and the plc type is going to be SS2 and I will create 62 00:06:57,960 --> 00:07:02,370 the one program will be later on and data 63 00:07:04,990 --> 00:07:14,330 I will give a name addressing and it will be program with the ladder diagram and I will create a device 64 00:07:14,350 --> 00:07:22,140 monitor table 2 if you want to monitor your your values or data registers or bits and everything in 65 00:07:22,340 --> 00:07:30,390 a piece of software so unique you can create a device monitor table in here just come here and right 66 00:07:30,400 --> 00:07:37,840 click and new and give a name to your monitor table and it can be stay like this and I will say okay 67 00:07:38,170 --> 00:07:52,510 and I will write my code okay LD M1000 always open contact and I will say to here okay first addressing 68 00:07:52,510 --> 00:07:54,480 of all collateral. 69 00:07:54,520 --> 00:07:55,020 I will. 70 00:07:55,020 --> 00:08:05,980 I will give this example to let's say 8 bit one bite addressing k 2 because of these m 0 and first 71 00:08:06,010 --> 00:08:12,120 I will use this instruction to the zero. 72 00:08:12,160 --> 00:08:14,910 This is the first thing and the second thing. 73 00:08:15,150 --> 00:08:21,490 And I will I will say LDI 20 for the indirect addressing. 74 00:08:21,700 --> 00:08:31,290 I will say D1 under then is 0 to d 1 under then 8. 75 00:08:31,430 --> 00:08:38,310 I have zero and I will send my project to Plc to simulator. 76 00:08:38,320 --> 00:08:39,340 Okay. 77 00:08:39,460 --> 00:08:41,180 And I want to transfer it. 78 00:08:41,200 --> 00:08:42,100 Okay. 79 00:08:42,100 --> 00:08:46,590 Transfer my project to Plc and now it's transferring. 80 00:08:47,320 --> 00:08:48,420 Yes. 81 00:08:48,580 --> 00:08:55,960 And I will say okay we have a runs so run status but I will say again to run. 82 00:08:55,960 --> 00:08:56,320 Okay. 83 00:08:56,320 --> 00:09:04,300 Monitor table I will monitor my m balloons than just time. 84 00:09:04,930 --> 00:09:12,670 M auxiliary relay that I'm going to monitor and I will take a look wants to what will 85 00:09:12,670 --> 00:09:14,630 happen in D0 86 00:09:14,800 --> 00:09:15,540 --- 87 00:09:15,640 --> 00:09:25,660 In here we send to K to M zero to D0 because of I'm going to watch these zero values and 88 00:09:25,840 --> 00:09:27,980 I will add these values also. 89 00:09:28,430 --> 00:09:41,950 Okay and monitor table and I will say E 0 and I will say F 0 first of all for the bit other seeing 90 00:09:42,070 --> 00:09:51,490 what we are going to learn or what we are going to work with this which is actually realized. 91 00:09:51,580 --> 00:09:59,170 For example you are working with a lot of actually release a lot of bits then you want to know which 92 00:09:59,650 --> 00:10:03,510 contacts are active and which ones are disabled. 93 00:10:03,610 --> 00:10:06,640 So how can you take them all one by one. 94 00:10:06,640 --> 00:10:12,450 It can take a lot of time and one by one you can you can lose a lot of time. 95 00:10:12,490 --> 00:10:20,920 So for example your and one contact is high set on and your fifth contact and 5 is on. 96 00:10:21,190 --> 00:10:22,400 So let's take a look. 97 00:10:22,400 --> 00:10:25,610 These 0 is now equals 34. 98 00:10:25,780 --> 00:10:29,110 So 34 means as binary. 99 00:10:29,110 --> 00:10:36,520 Your second and your sixth contact because it's starting from the zero is active. 100 00:10:36,700 --> 00:10:47,110 So let's active activate M 3 and set on you say you our value is change and now what we did we addressed 101 00:10:47,530 --> 00:10:50,730 byte so byte equals bit. 102 00:10:50,920 --> 00:10:53,960 So what happens if I activate m 9. 103 00:10:54,160 --> 00:10:59,250 Set on You see nothing is changed and of nothing's changed. 104 00:10:59,260 --> 00:11:08,160 So now we learn we can monitor or we can follow a bit value inside of these your. 105 00:11:08,170 --> 00:11:13,660 So what happens for example if I say not okay too. 106 00:11:13,930 --> 00:11:15,470 I will say okay. 107 00:11:15,580 --> 00:11:17,280 4 for example in here. 108 00:11:17,290 --> 00:11:26,620 So I want to watch and I want to address one word or sixteen bit and I will send it to PLC now it's 109 00:11:26,650 --> 00:11:31,360 transferring with the online it edit update program line update is completed. 110 00:11:31,430 --> 00:11:40,940 Okay now let's go back to monitor table and at M10 and eight more. 111 00:11:40,990 --> 00:11:41,800 No. 112 00:11:42,050 --> 00:11:47,190 Ve changed a nine contact to all but these four didn't change. 113 00:11:47,230 --> 00:11:49,980 Now I will change to M9 set on. 114 00:11:49,990 --> 00:11:58,270 So you see all these zero value is changed and now it's bigger than because after a bit than we activate 115 00:11:58,270 --> 00:11:59,170 the tenth bit. 116 00:11:59,290 --> 00:12:05,800 If you put the 10. Bit 1 as binary numbers then you can. 117 00:12:05,980 --> 00:12:12,060 You can reach not this number because M1 and M3 and these ones are high. 118 00:12:12,130 --> 00:12:19,870 Let's set off these ones and as binary effect to a tiny bit and it cost as decimal five hundred and 119 00:12:19,920 --> 00:12:24,190 twelve and let us imagine M fifteen is active. 120 00:12:24,310 --> 00:12:30,790 So our value is higher than thirty two thousand seven hundred and sixty seven. 121 00:12:30,790 --> 00:12:34,860 So it's this activities D1 activate and 14. 122 00:12:35,110 --> 00:12:37,300 So you see this is our value. 123 00:12:37,420 --> 00:12:40,200 What about a 17 set on. 124 00:12:40,250 --> 00:12:47,520 Nothing nothing's changed because now we are addressed just 16 bit inside of the zero. 125 00:12:47,770 --> 00:12:56,730 So this is addressing the methods of the of your bits of your values inside of the plc projects. 126 00:12:56,800 --> 00:13:02,680 So let's take a look wants to in indirect addressing what will happen. 127 00:13:02,690 --> 00:13:10,620 do you want one under eight it is zero value is going to transfer to d 1 under then f 0. 128 00:13:10,640 --> 00:13:20,320 So let's let's do a value to is real and f 0 for example inside of the Monitor table I will give you 129 00:13:20,500 --> 00:13:28,930 a value to zero it will be time and a zero it will be 20 130 00:13:32,150 --> 00:13:35,500 and go back to data addressing area okay. 131 00:13:35,660 --> 00:13:46,820 Now for example o d 1 under that kind Malu is going to move to the one hundred and twenty so let's let's 132 00:13:46,820 --> 00:13:55,730 change the value inside of the the one under then time and in here left double click d one under then 133 00:13:56,240 --> 00:14:01,900 turn and left click d one under then twenty. 134 00:14:01,940 --> 00:14:12,650 So now let's change it to for example three now o the one underlined time blue is three and after I 135 00:14:12,800 --> 00:14:21,140 activate two M twenty contact we are we need to see the one hundred and twenty equals two three. 136 00:14:21,260 --> 00:14:28,420 Let's try once M twenty set on so go back our monitor table than you see. 137 00:14:28,910 --> 00:14:33,410 d121 to became three. 138 00:14:33,650 --> 00:14:39,040 So let's change for example this value to 5. 139 00:14:39,840 --> 00:14:42,540 And we can see it's five. 140 00:14:42,540 --> 00:14:47,270 So what happens if I change is zero to 30. 141 00:14:47,280 --> 00:14:51,720 Now you can see the one hundred and twenty is zero. 142 00:14:51,720 --> 00:14:52,450 Why. 143 00:14:52,530 --> 00:14:59,640 Because now we are transferring 120 data registers to the one hundred and twenty. 144 00:14:59,640 --> 00:15:04,060 Let's take a look once the one hundred and twenty and it's your. 145 00:15:04,080 --> 00:15:13,650 So what I what I change to this value for example is give a value to the one hundred and twenty fifty. 146 00:15:13,800 --> 00:15:17,100 Then we need to see fifty in here. 147 00:15:17,130 --> 00:15:27,920 Let's change a zero to for example 50 and now we need to change this value for example to 60. 148 00:15:28,380 --> 00:15:35,750 Okay now we need to see the one hundred and fifty must be equal to sixty. 149 00:15:35,770 --> 00:15:38,570 It's at the one hundred and fifty here. 150 00:15:38,670 --> 00:15:41,240 Then you can see it is sixty. 151 00:15:41,610 --> 00:15:51,390 So now we can address our bits our registers with the with the addressing methods so we can we can 152 00:15:51,390 --> 00:16:02,580 use k to M0 K to y 0 k 2 8 0 0 k 1 k three K for K five whatever you want to use you can use it like 153 00:16:02,580 --> 00:16:09,360 this and you can address your deeds and your values were with like this and you can monitor them you 154 00:16:09,360 --> 00:16:17,220 can take under control them all and with the indirect addressing you can use e areas and the F areas 155 00:16:17,280 --> 00:16:25,170 inside of the ıspsoft inside of the delta plcs and if you put in the ISPsoft the 5 for 156 00:16:25,170 --> 00:16:35,190 example D 5 it is 0 and if you give a value to each row you need to 8 for example 5 at 5 8 or 5 plus 157 00:16:35,700 --> 00:16:45,360 and your value of 0 then you will get a result of this ending and then these data registers that you 158 00:16:45,360 --> 00:16:53,070 are going to use actually inside of the Plc projects these are Y really important. 159 00:16:53,070 --> 00:16:59,700 Imagine you are communicating with the third to slave for example with the drives with we have these 160 00:17:00,060 --> 00:17:06,150 and you need to send them all a lot of information and you need to read a lot of information from them 161 00:17:06,540 --> 00:17:14,620 done you you need to write a lot of data registers inside of the program or you can increase your area 162 00:17:14,640 --> 00:17:21,870 Sweet Sixteen or thirty two each time and each cycle down you can read and write a lot of information 163 00:17:21,870 --> 00:17:24,810 with a free program line. 164 00:17:24,930 --> 00:17:33,460 So these are really important and we are going to use them all inside communication with the these and 165 00:17:33,520 --> 00:17:34,380 other device. 166 00:17:34,510 --> 00:17:39,780 So for a moment before this video I am finished and see you in the next video.