0
1
00:00:21,930 --> 00:00:22,540
Hello.
1

2
00:00:22,540 --> 00:00:23,390
Let's continue.
2

3
00:00:23,390 --> 00:00:27,560
to questions and answers part 4.
3

4
00:00:27,640 --> 00:00:28,410
Let's take a look.
4

5
00:00:28,410 --> 00:00:37,720
The question one How to two wire PT100 connection and answer the correct connection type is as shown
5

6
00:00:37,780 --> 00:00:46,240
on the two wire line then connecting your sensor to the L+ and L- terminals you must bridge
6

7
00:00:46,240 --> 00:00:55,540
the L- an I-  terminals between themselves in here you can see three wire connection
7

8
00:00:55,840 --> 00:00:59,260
in three way connection in here.
8

9
00:00:59,460 --> 00:01:00,660
We have a bridge.
9

10
00:01:00,670 --> 00:01:07,010
So I- is not connected to L- in here.
10

11
00:01:07,050 --> 00:01:14,340
So for three wire L+ and L- and I- can connect to separately.
11

12
00:01:14,730 --> 00:01:23,310
But for two wire for example for the PT1000 you can connect to L+ to and L+ connection
12

13
00:01:23,730 --> 00:01:33,840
after you connect your L- connection you need to put a bridge to here for I- connection this
13

14
00:01:33,840 --> 00:01:45,930
is how to wire PT100 or PT1000  connection as to wire or three wire question 2 how do I
14

15
00:01:45,930 --> 00:01:54,450
direct the high speed input to the high speed output is it possible for example we are reading the pulses
15

16
00:01:54,450 --> 00:02:04,530
coming from encoder to my input and suddenly from my output we are sending these pulses directly.
16

17
00:02:04,530 --> 00:02:05,700
Is it possible.
17

18
00:02:05,700 --> 00:02:13,560
So let's take a look at our answer the time to read the logic input differs within the plcs scan
18

19
00:02:13,560 --> 00:02:21,630
time cycle also the reading filter time of the inputs is 10milliseconds at the default settings it
19

20
00:02:21,630 --> 00:02:22,560
is set.
20

21
00:02:22,590 --> 00:02:31,230
This means that you cannot read an input below 10 milliseconds and activate the output contact at the
21

22
00:02:31,230 --> 00:02:32,140
same time.
22

23
00:02:32,250 --> 00:02:41,460
If your plc scan time is over 10 milliseconds it also means that you cannot operate under this cycle
23

24
00:02:41,760 --> 00:02:43,770
time period.
24

25
00:02:43,770 --> 00:02:45,220
So let's take a look.
25

26
00:02:45,220 --> 00:02:46,760
to question 3.
26

27
00:02:46,830 --> 00:02:53,430
I want to run a pid controlled hydrofor with the VFD  series driver.
27

28
00:02:53,430 --> 00:03:03,260
We have driver means VFD we have 4 to 20 mA ten bar pressure sensor is there an example with
28

29
00:03:03,270 --> 00:03:04,150
connection.
29

30
00:03:04,290 --> 00:03:10,590
scheme or parameter explanations with application.
30

31
00:03:10,590 --> 00:03:11,460
Let's take a look.
31

32
00:03:11,530 --> 00:03:25,080
to answers and our scheme for VFD-E PID settings parameter ten to 10.00 for PID set
32

33
00:03:25,080 --> 00:03:32,640
point selection we can enter the PID set value to parameter 10.11 by setting the parameter
33

34
00:03:33,120 --> 00:03:44,730
10.00 from 10.04 and or enter it as desired from the parameter 2.00 parameter by setting
34

35
00:03:44,730 --> 00:03:55,480
the parameter 10.00 to 1, parameter 10.01 for PID feedback input terminal.
35

36
00:03:56,140 --> 00:04:05,320
So in here PID feedback input negative feedback ACI set to 4 to 20mA that we can do it
36

37
00:04:05,320 --> 00:04:14,630
in here 10.02, 1.0 factory value proportional gain it should be determined and
37

38
00:04:14,630 --> 00:04:21,590
adjusted according to the characteristics of the system 10.03 is 1.00
38

39
00:04:21,590 --> 00:04:29,060
factory value of integral time ,it should be determined and adjusted according to characteristics
39

40
00:04:29,060 --> 00:04:32,910
of the system 10.04
40

41
00:04:33,180 --> 00:04:35,540
Is it close to 0.00
41

42
00:04:35,550 --> 00:04:39,500
So this is factory value of derivative control.
42

43
00:04:39,520 --> 00:04:44,670
It should be determined and adjusted according to characteristics of the system also.
43

44
00:04:44,910 --> 00:04:46,390
10.11
44

45
00:04:46,620 --> 00:04:54,290
equals  to 12.5 PID setpoint source after selecting 10.00 parameter
45

46
00:04:54,300 --> 00:05:03,900
As for PID set value is entered from this parameter in here we have a fuse or circuit breaker and
46

47
00:05:03,900 --> 00:05:14,030
in here we have VFD-E and in here our motor connection and you can see in here acı-acm for 4-20mA
47

48
00:05:14,040 --> 00:05:15,890
4-20mA
48

49
00:05:15,970 --> 00:05:26,150
This outputs current outputs can be used like this with these parameters after you adopt these parameters
49

50
00:05:26,700 --> 00:05:30,750
PID set points selections and etc.
50

51
00:05:31,310 --> 00:05:43,400
This can be used but in here  I need to correct one thing we will use this 4-20mA
51

52
00:05:43,420 --> 00:05:46,060
10 bar pressure sensor.
52

53
00:05:46,090 --> 00:05:49,100
This one for the control this motor.
53

54
00:05:49,180 --> 00:05:54,730
So we are not sending analog outputs to here.
54

55
00:05:54,740 --> 00:06:03,610
Here we are getting analog inputs from here to my VFD-E and we are turning our motors according to
55

56
00:06:03,610 --> 00:06:11,130
these analog inputs to inside of my VFD or drive.
56

57
00:06:11,200 --> 00:06:22,360
Question 4 how to reset from Z phase with 3600 pulse rotary encoder I connected phases are A and B
57

58
00:06:22,360 --> 00:06:32,390
and Z to the physical inputs x0,X1 x2 respectively I counted down and up with the C251
58

59
00:06:32,390 --> 00:06:33,870
x251
59

60
00:06:33,970 --> 00:06:40,610
How can I perform the reset by catching the Z phase while the motor is returning.
60

61
00:06:40,690 --> 00:06:50,050
I would be glad if you could help plc model is that DVP12SA2  , answer is that if the
61

62
00:06:50,080 --> 00:07:01,540
aim is to reset the counter value in each z phase the encoder is using C252 number in here you can
62

63
00:07:01,540 --> 00:07:12,120
see for example in question the user or customer said x 0 X1 and X2 is used,
63

64
00:07:12,160 --> 00:07:15,420
I am going to ride side from here okay.
64

65
00:07:15,510 --> 00:07:23,530
We will go up and down or a and b phase a input on phase b input is used and up and downs.
65

66
00:07:23,550 --> 00:07:29,110
Okay but also we need to reset for example in our application.
66

67
00:07:29,200 --> 00:07:32,160
We need to reset something else that's okay.
67

68
00:07:32,170 --> 00:07:41,720
So when we can use or we need to use two phase two input a counter C252, x0 is a phase X1
68

69
00:07:41,830 --> 00:07:48,030
is B phase x 4 is Z phase 
69

70
00:07:48,190 --> 00:07:48,570
So
70

71
00:07:51,790 --> 00:07:53,370
what was the question.
71

72
00:07:53,380 --> 00:08:01,090
So in here how can I perform the reset by catching the Z phase while the motor is returning.
72

73
00:08:01,090 --> 00:08:11,230
So if you use not C251 counter because in here there is no reset condition but if you connect your
73

74
00:08:11,410 --> 00:08:15,860
x4 in here Z is connected to here.
74

75
00:08:16,000 --> 00:08:16,750
Okay.
75

76
00:08:16,750 --> 00:08:25,720
And when x 4 is goes high my C252 counters becomes reset.
76

77
00:08:26,050 --> 00:08:33,700
So it can be solution of this question and in here.
77

78
00:08:33,700 --> 00:08:42,930
Question again encoder 3600 pass but reset it at 14400 pulse
78

79
00:08:42,940 --> 00:08:47,350
What is the reason for this problem in X2 interrupt.
79

80
00:08:47,350 --> 00:08:53,440
I can reset from Z phase ,Z phase with the C251 counter.
80

81
00:08:53,530 --> 00:08:58,900
There was no different situation with the C252 counter.
81

82
00:08:58,960 --> 00:09:06,890
So answer is that 3600 x 4 =14400 
82

83
00:09:06,940 --> 00:09:15,700
If you write one in D1122 you will read 3600 pulse encoder
83

84
00:09:15,760 --> 00:09:19,480
as three thousand six hundred.
84

85
00:09:19,510 --> 00:09:26,650
Remember there were core efficient value of the encoders.
85

86
00:09:26,740 --> 00:09:34,240
So for example if your encoder coefficient value is 1 and is your encoder is for example
86

87
00:09:34,240 --> 00:09:43,820
let's say 3600 so you will reach to Z phase after 3600 pulse
87

88
00:09:44,070 --> 00:09:53,820
but your coefficient value is let's say 2 , you will get this Z phase or you will get complete turn
88

89
00:09:54,150 --> 00:10:00,030
after 7200 pulse so and M1002
89

90
00:10:00,030 --> 00:10:02,880
This is the first second contact.
90

91
00:10:02,880 --> 00:10:14,460
It is moving to k 2 to D1022 example and we are multiplying our encoder value by 2 and we are reaching
91

92
00:10:14,460 --> 00:10:20,460
to Z phase after 7200 pulse for example.
92

93
00:10:20,470 --> 00:10:29,400
So if this value if your encoder value is increasing too for example 14400
93

94
00:10:29,400 --> 00:10:34,350
pulses and you are still waiting your Z phase.
94

95
00:10:34,530 --> 00:10:40,830
You need to check D1022 immediately if it is not equals one.
95

96
00:10:40,950 --> 00:10:43,010
You can change it or you can check it.
96

97
00:10:43,020 --> 00:10:54,030
And according to your value in D1022 you can continue to your project or programming and in here
97

98
00:10:54,570 --> 00:10:56,580
we have another one question.
98

99
00:10:56,580 --> 00:11:02,720
I want to read 4 -20  current with the DTC 1000.
99

100
00:11:02,730 --> 00:11:09,690
I found that the jumper positions should be changed in the document but I couldn't find the jumper location
100

101
00:11:09,690 --> 00:11:11,820
on DTC 1000.
101

102
00:11:11,850 --> 00:11:13,760
Where can I find these.
102

103
00:11:13,830 --> 00:11:20,850
So answer is that two sockets marked in the picture next to the terminal connection point of the DTC
103

104
00:11:20,850 --> 00:11:26,440
1000 module must be bridged with a jumper or different connection tool.
104

105
00:11:26,520 --> 00:11:28,840
In here you can see it.
105

106
00:11:29,010 --> 00:11:32,380
This two.
106

107
00:11:32,850 --> 00:11:43,200
How can I say inputs or this two connection points must be bridge with the jumper or you can you can
107

108
00:11:43,200 --> 00:11:47,960
connect it these things together with a different connection tool.
108

109
00:11:48,480 --> 00:11:57,330
So for example I want to read 0-10 VDC analog value with the DTC 1000 module but I couldn't find
109

110
00:11:57,330 --> 00:11:58,700
a very clear source.
110

111
00:11:58,710 --> 00:12:08,150
Can you help the plc that I use is 14SS2 and the DTC 1000 is bridged that moment.
111

112
00:12:08,220 --> 00:12:15,930
What should we do answer is that when connecting to 0-10 what to DTC the bridge inside , should
112

113
00:12:16,050 --> 00:12:25,200
not be connected for the 0-10 VDC it is not necessary to jumper put the jumper or bridge these
113

114
00:12:25,800 --> 00:12:31,740
connection points for current or 4-20mA current.
114

115
00:12:31,770 --> 00:12:39,630
If you want to work with the current you need to use jumper or unit to connect this connection point
115

116
00:12:39,630 --> 00:12:40,480
altogether.
116

117
00:12:40,650 --> 00:12:48,310
But for the 0-10 volts DC you don't need a bridge and that bridge is for just current input on
117

118
00:12:48,310 --> 00:12:54,810
a simplified connect to analog input to + and - input.
118

119
00:12:54,890 --> 00:12:55,630
That's all.
119

120
00:12:55,680 --> 00:13:04,750
And then you can run or you can use your DTC as 0-10 volt analog value.
120

121
00:13:05,100 --> 00:13:08,580
So for this video I am finished here.
121

122
00:13:08,580 --> 00:13:09,960
See you in the next video.
