1 00:00:00,360 --> 00:00:01,110 Hello fellas. 2 00:00:01,140 --> 00:00:02,870 Welcome back. 3 00:00:02,880 --> 00:00:08,580 We shall examine the two fundamental architectures used by computer systems in this lesson. 4 00:00:08,580 --> 00:00:12,560 And this lesson comes with a bit of exciting history. 5 00:00:12,570 --> 00:00:18,890 Some of you may know John Foy mine introduced the design of this toward program computer. 6 00:00:18,900 --> 00:00:25,450 This design is known as the von Neumann architecture and it started a new epoch of computers. 7 00:00:25,530 --> 00:00:30,400 Von Neumann introduced a number of parameters for his universal computer. 8 00:00:30,420 --> 00:00:40,550 He said a computer can system memory and arithmetic logic unit control unit and input an output devices. 9 00:00:40,570 --> 00:00:45,430 Also he says all parts of the computer are connected together by a bus. 10 00:00:45,430 --> 00:00:53,060 Also the computer structure is independent of the computer problem and the computer is programmed with 11 00:00:53,080 --> 00:00:54,820 content of the memory. 12 00:00:54,820 --> 00:00:58,750 He gives more parameters but yeah I wouldn't talk about all of them. 13 00:00:58,780 --> 00:01:04,930 This is the structure of the universe or computer proposed by John Faulkner a month in 1947. 14 00:01:04,930 --> 00:01:11,980 Data is passed to the blocks using the data box and the control unit controls or blocks using control. 15 00:01:12,280 --> 00:01:20,650 Using the control bus today we are able to integrate the control you need in the arithmetic logic units 16 00:01:20,770 --> 00:01:28,090 into a single integrated circuit which we call the CPSU audit process all because of this technological 17 00:01:28,090 --> 00:01:28,930 advancement. 18 00:01:28,930 --> 00:01:32,910 We are able to simplify the phone Norman architecture. 19 00:01:32,980 --> 00:01:39,210 This is the defining moment architecture I used to date in modern computers. 20 00:01:39,220 --> 00:01:46,600 Notice that there is a single bus running from the CPSU to the memory I use devices are simply connected 21 00:01:46,600 --> 00:01:48,520 to this bus. 22 00:01:48,520 --> 00:01:51,360 Next let's take a look at the other architecture. 23 00:01:51,370 --> 00:01:53,650 The Harvard architecture. 24 00:01:53,960 --> 00:02:01,170 As you may know the mark to computer was introduced at Harvard in 1947. 25 00:02:01,190 --> 00:02:08,810 It wasn't as more dynastic for Norman machine but it introduce a slightly different architecture. 26 00:02:08,810 --> 00:02:17,240 It separated memory for data from memory for instructions thereby coming up with a structure like this 27 00:02:18,200 --> 00:02:23,630 with two buses connected to the CPE one for data and one for instructions. 28 00:02:23,690 --> 00:02:28,650 We often simplify the structure of the Von Neumann machine to something like this. 29 00:02:28,760 --> 00:02:36,110 The CPSU on one side memory on the other side in a single bus connecting the in memory and this bus 30 00:02:36,200 --> 00:02:39,360 is known as the data and instruction bus. 31 00:02:39,680 --> 00:02:46,250 The Harvard architecture is often simplified into something like this CPE on one side memory on the 32 00:02:46,250 --> 00:02:50,630 other side and two buses connecting the seat in memory. 33 00:02:50,630 --> 00:02:58,940 One bus for data under the bus for instruction there are many differences between the Harvard system 34 00:02:58,970 --> 00:03:01,280 and the phone in my mind system. 35 00:03:01,280 --> 00:03:07,690 In terms of implementation cost and performance I'll just mention a few differences here. 36 00:03:07,760 --> 00:03:13,700 First and foremost a single bus is simpler for control unit design and therefore development of control 37 00:03:13,700 --> 00:03:17,820 units become faster and cheaper. 38 00:03:17,840 --> 00:03:23,080 The von Neumann architecture office a common memory for both data and structures. 39 00:03:23,150 --> 00:03:29,690 While the Harvard architecture offers separate memories for detainees structures this allows the Harvard 40 00:03:29,690 --> 00:03:36,950 system to perform to assign the teeniest memory fetches which the von Neumann system is not capable 41 00:03:36,950 --> 00:03:37,970 of. 42 00:03:37,970 --> 00:03:39,940 So this all there is to it. 43 00:03:39,950 --> 00:03:45,710 This is very straightforward and yes I'll see you in the next lesson.