WEBVTT 00:00.870 --> 00:04.530 This is the last video lecture in that section. 00:04.530 --> 00:10.950 These will always be me practicing with you about what we've learned in current section the next lecture 00:10.950 --> 00:15.430 will always be some practice problems for you to do on your own. 00:15.450 --> 00:22.350 This will help you gain the confidence and experience in what we've been learning so let's do some more 00:22.350 --> 00:25.860 practice to solidify everything. 00:27.510 --> 00:36.600 Sue problem one write an algorithm that gets a number from the user from 1 to 7 and prints the corresponding 00:36.810 --> 00:38.870 Dave. 00:38.960 --> 00:41.430 We start that week with Monday. 00:41.870 --> 00:51.310 So the first thing to do as outlined is always to see if we understand the problem first. 00:51.340 --> 00:59.620 So if we start with Monday then that would mean Monday would correspond to the number 1 and 2 would 00:59.620 --> 01:02.370 be Tuesday every Wednesday and so on. 01:02.370 --> 01:14.380 So we end the week at Sunday which would be 7 so knowing this then we should start. 01:14.550 --> 01:21.580 So let's say we have a variable day and we're going to set that to the user input. 01:21.950 --> 01:22.940 Good day 01:29.420 --> 01:29.860 user 01:37.150 --> 01:45.040 next is we have to decide day of week it is. 01:45.130 --> 01:52.990 So this will be our IF control statements. 01:53.370 --> 02:04.990 So if de equals are equal to 1 then we know it's Monday right. 02:06.410 --> 02:07.110 But it's 02:10.680 --> 02:15.870 Monday. 02:17.670 --> 02:18.840 Otherwise 02:23.100 --> 02:28.620 if DE is to 02:31.690 --> 02:32.210 you 02:37.300 --> 02:37.810 in 02:44.140 --> 02:48.610 Tuesday and so on. 02:48.630 --> 02:55.800 So let's just finish all these other cases up. 02:56.190 --> 03:05.100 If a will to read an 03:11.900 --> 03:13.370 it's day 03:24.870 --> 03:30.760 if Daisy go to four then 03:35.800 --> 03:37.960 I could teach there is the 03:48.320 --> 03:51.850 lies day see 03:54.900 --> 03:57.450 five in 04:04.420 --> 04:04.990 Friday 04:11.160 --> 04:14.180 seven otherwise 04:16.930 --> 04:21.700 day to sick it's 04:24.480 --> 04:25.020 an 04:32.020 --> 04:32.950 Saturday 04:42.570 --> 04:44.090 all day 04:46.810 --> 04:50.960 to seven Sunday 04:58.340 --> 05:00.570 and then we're going to have one more actually. 05:00.680 --> 05:03.100 So were I to say otherwise. 05:12.220 --> 05:15.500 Otherwise it's just going to be an air raid. 05:17.090 --> 05:28.050 Because what if the user included negative 1 or 10 Those don't correspond any day so we're just going 05:28.050 --> 05:30.690 to put a general message that says 05:36.570 --> 05:42.160 what it's that's not the 05:48.910 --> 05:49.420 care. 05:49.720 --> 05:57.130 So we're always going to be checking for errors in our code later on because either can easily type 05:57.130 --> 05:59.880 something incorrectly. 05:59.940 --> 06:06.620 So that's going to be one thing we're going to be looking out for future. 06:06.640 --> 06:10.910 So we move on here to problem to 06:15.300 --> 06:26.220 so choose says right now for them that sums all the odd numbers from 1 to 10 where n is a number from 06:26.220 --> 06:30.500 the user output the result so 06:34.030 --> 06:39.350 this is quite similar to some of the last problems we just did. 06:41.030 --> 06:51.810 We're going to have an RE get in but it's the user user. 06:51.940 --> 07:02.400 Give us some number N and then we have what we have or some in to start the summit in zero. 07:02.440 --> 07:06.790 So sign some value zero for now. 07:08.670 --> 07:17.890 Loop from 1 up to including in his arse. 07:17.990 --> 07:20.110 Rumors are stopping condition 07:27.700 --> 07:28.230 for 07:31.120 --> 07:37.630 and we just read this in English for now but later on it'll actually be bit more formal. 07:39.250 --> 07:42.100 So inside the loop. 07:43.710 --> 07:54.530 We're going to say we want the current number that we're at or remember it counts up from 1 to an current 07:54.630 --> 07:55.240 number 07:59.020 --> 08:00.050 is called CNH 08:02.800 --> 08:08.790 And then Rich check says the opposite of what we had before. 08:08.790 --> 08:13.070 Before we had it had to be exactly divisible by two. 08:13.090 --> 08:24.230 But now you want see and is not exactly divisible. 08:26.270 --> 08:32.410 Visible by two then 08:38.690 --> 08:39.800 then we just add 08:42.650 --> 08:44.720 cn to the current Some 08:48.810 --> 08:49.980 adze n 08:54.040 --> 09:03.230 to this current sum and then reassign the sum to be that number. 09:03.420 --> 09:04.020 Finally 09:07.090 --> 09:10.370 put some. 09:10.860 --> 09:15.280 That's it. 09:15.590 --> 09:16.700 This makes sense. 09:22.170 --> 09:24.670 To problem re 09:28.340 --> 09:35.440 solve problem 3 says right now for them that takes in two numbers from the user the first number will 09:35.440 --> 09:41.350 be the base and the second number and the second will be the exponent. 09:41.350 --> 09:48.530 So this is like two to the power of some number base and power of some numbers. 09:48.910 --> 09:51.520 So calculate the results of the base. 09:51.640 --> 09:55.550 Number two the power of the exponent and output the result. 09:55.610 --> 09:55.970 So 10:01.360 --> 10:06.070 starch will need that base from the user. 10:06.070 --> 10:16.430 So say first step is get the base get base the 10:24.440 --> 10:27.960 and then get in touch 10:31.200 --> 10:31.790 user 10:38.380 --> 10:46.440 and then we have another variable actually that will help us is kind of like are some that we had before 10:46.470 --> 10:54.870 but rushing in to say he which is short for power is two to one. 10:54.930 --> 10:58.290 We'll see why in the second. 10:58.510 --> 11:08.280 Let's go to Lou loop from one up to and including 11:19.380 --> 11:23.050 in here in the loop. 11:23.050 --> 11:33.650 We'll say he Zeek hoped he times be so here removing. 11:33.680 --> 11:37.520 How many times removing 11:41.090 --> 11:47.610 e times are 8. 11:47.680 --> 11:48.840 So you count. 11:48.940 --> 11:52.030 So let's say e was five. 11:52.190 --> 11:54.630 So a count from one to five. 11:54.670 --> 12:04.350 Say five times and then in the loop since he starts at 1. 12:04.540 --> 12:07.940 Any number of times one is just that number. 12:07.990 --> 12:15.840 So it'll start from let's say who's to the five so is the base. 12:15.870 --> 12:19.250 So he would be 1 times 2. 12:19.410 --> 12:22.400 And then we reassign it to be to be piece. 12:22.410 --> 12:31.470 He is now two for the next and then two times two again which before. 12:32.000 --> 12:34.130 So see why we needed that one here. 12:34.180 --> 12:36.300 One kind of doesn't affect anything. 12:37.820 --> 12:49.210 It'll just be the base in the first iteration and then you say two times two times two times too great 12:49.920 --> 12:51.590 to think. 12:51.970 --> 12:58.880 So two to five in that case would be three to in. 12:59.060 --> 13:07.640 And then once it's over the loop is over and just say OK it's he right. 13:07.770 --> 13:09.870 He has our results 13:12.760 --> 13:15.310 hopefully that makes sense. 13:17.310 --> 13:21.950 Again don't worry too much if we're not completely getting this yet. 13:22.310 --> 13:29.810 We'll be doing a lot more examples in the following sections in fact be doing a lot more this kind of 13:29.810 --> 13:30.360 stuff. 13:30.360 --> 13:38.130 But I just wanted to give you a taste of what we'll be doing in the kinds of problems will be solved. 13:38.590 --> 13:40.480 So see you in the next section.